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# Vtracs same as LDR (shortsum)

Topic closed. 5 replies. Last post 6 years ago by Jordans121.

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Thread Starter

United States
Member #69169
January 5, 2009
2122 Posts
Offline
 Posted: December 12, 2010, 2:26 pm - IP Logged

Over the past few months I have been really breaking down the vtracs and their distribution of numbers and what i have found is that when broken down from all possible P3 bx combinations you will end up with 10 sets of 22 numbers which is the same as choosing a shortsum (1=22 nums). Furthermore, I found that when you select a sum of a set of representers (vtracs) you only have 7 instead of 13 using regular vtrac sums. The only difference is that you can break vtrac numbers down to 12,8, and 6.

This is how you arrive at my conclusion: (suggest excel) take each shortsum and assign a differerent vtrac to it. Such as LDR 1 will be represented by 123, etc...

when you finish get the sum of the represented vtrac: 123=6. Do this to all of the LDR's and representers and see what I'm talking about. Its pretty cool. At the end you will find that if you select representer sum 9 (135 and 234) you will only have to play 200 numbers straight. All sums holds either 200 (8,9,10) numbers or 100 numbers (6,7,11,12).

Also, what I did is I kept the Representer of a double vtrac in my spreadsheet which is "D" and what ever number corresponds with it. At the end of the day you will see that every thing is distributed equally.

Again, you can do this with regular vtracs but it take much longer to accomplish.

You can all so this with  Rootsums but each will not be represented with an equal distribution  of numbers. Thank me later

For example IL should have representer sum 8 soon...

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,350,354,363,369,372,378,381,387,390,396

404,408,413,417,422,426,431,435,440,444,453,459,462,468,471,477,480,486,495,499

503,507,512,516,521,525,530,534,543,549,552,558,561,567,570,576,585,589,594,598

602,606,611,615,620,624,633,639,642,648,651,657,660,666,675,679,684,688,693,697

701,705,710,714,723,729,732,738,741,747,750,756,765,769,774,778,783,787,792,796

800,804,813,819,822,828,831,837,840,846,855,859,864,868,873,877,882,886,891,895

903,909,912,918,921,927,930,936,945,949,954,958,963,967,972,976,981,985,990,994

"Many Strategies|One Game"

Thread Starter

United States
Member #69169
January 5, 2009
2122 Posts
Offline
 Posted: December 12, 2010, 2:47 pm - IP Logged

Depending on how you represent each LDR you will have a different set of numbers but they still will be equally distributed in terms of the amount of numbers. Also, each holds singles, doubles, and triples, niiiiice!!

"Many Strategies|One Game"

Chief Bottle Washer
New Jersey
United States
Member #1
May 31, 2000
23596 Posts
Online
 Posted: December 13, 2010, 11:26 am - IP Logged

<Moved to Pick 3 forum>

Please post in the appropriate forum ... thank you.

Thread Starter

United States
Member #69169
January 5, 2009
2122 Posts
Offline
 Posted: December 13, 2010, 5:35 pm - IP Logged

Over the past few months I have been really breaking down the vtracs and their distribution of numbers and what i have found is that when broken down from all possible P3 bx combinations you will end up with 10 sets of 22 numbers which is the same as choosing a shortsum (1=22 nums). Furthermore, I found that when you select a sum of a set of representers (vtracs) you only have 7 instead of 13 using regular vtrac sums. The only difference is that you can break vtrac numbers down to 12,8, and 6.

This is how you arrive at my conclusion: (suggest excel) take each shortsum and assign a differerent vtrac to it. Such as LDR 1 will be represented by 123, etc...

when you finish get the sum of the represented vtrac: 123=6. Do this to all of the LDR's and representers and see what I'm talking about. Its pretty cool. At the end you will find that if you select representer sum 9 (135 and 234) you will only have to play 200 numbers straight. All sums holds either 200 (8,9,10) numbers or 100 numbers (6,7,11,12).

Also, what I did is I kept the Representer of a double vtrac in my spreadsheet which is "D" and what ever number corresponds with it. At the end of the day you will see that every thing is distributed equally.

Again, you can do this with regular vtracs but it take much longer to accomplish.

You can all so this with  Rootsums but each will not be represented with an equal distribution  of numbers. Thank me later

For example IL should have representer sum 8 soon...

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,350,354,363,369,372,378,381,387,390,396

404,408,413,417,422,426,431,435,440,444,453,459,462,468,471,477,480,486,495,499

503,507,512,516,521,525,530,534,543,549,552,558,561,567,570,576,585,589,594,598

602,606,611,615,620,624,633,639,642,648,651,657,660,666,675,679,684,688,693,697

701,705,710,714,723,729,732,738,741,747,750,756,765,769,774,778,783,787,792,796

800,804,813,819,822,828,831,837,840,846,855,859,864,868,873,877,882,886,891,895

903,909,912,918,921,927,930,936,945,949,954,958,963,967,972,976,981,985,990,994

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,350,354,363,369,372,378,381,387,390,396

404,408,413,417,422,426,431,435,440,444,453,459,462,468,471,477,480,486,495,499

503,507,512,516,521,525,530,534,543,549,552,558,561,567,570,576,585,589,594,598

602,606,611,615,620,624,633,639,642,648,651,657,660,666,675,679,684,688,693,697

701,705,710,714,723,729,732,738,741,747,750,756,765,769,774,778,783,787,792,796

800,804,813,819,822,828,831,837,840,846,855,859,864,868,873,877,882,886,891,895

903,909,912,918,921,927,930,936,945,949,954,958,963,967,972,976,981,985,990,994

As promised, there it was!

If you played online you spend 50 to 100 to win 225 and if at the store (not reccommended) you spend 100 and win 250

anyway you look at it there some money to be made.

"Many Strategies|One Game"

*4-2-8*
United States
Member #81314
October 16, 2009
20286 Posts
Offline
 Posted: December 13, 2010, 7:56 pm - IP Logged

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,350,354,363,369,372,378,381,387,390,396

404,408,413,417,422,426,431,435,440,444,453,459,462,468,471,477,480,486,495,499

503,507,512,516,521,525,530,534,543,549,552,558,561,567,570,576,585,589,594,598

602,606,611,615,620,624,633,639,642,648,651,657,660,666,675,679,684,688,693,697

701,705,710,714,723,729,732,738,741,747,750,756,765,769,774,778,783,787,792,796

800,804,813,819,822,828,831,837,840,846,855,859,864,868,873,877,882,886,891,895

903,909,912,918,921,927,930,936,945,949,954,958,963,967,972,976,981,985,990,994

As promised, there it was!

If you played online you spend 50 to 100 to win 225 and if at the store (not reccommended) you spend 100 and win 250

anyway you look at it there some money to be made.

Good Workout @ Jordans121

Wish I could have played in Illinois today, Missouri has not let that, 125 go since December of Last YEAR.

Hope Missouri follows Illinois, but,I didn't play, 125 tonight, lmaoooooooooooooooooooo

Good Luck.

0,1,2,3,4,5,6,7,8,9

Thread Starter

United States
Member #69169
January 5, 2009
2122 Posts
Offline
 Posted: December 13, 2010, 11:03 pm - IP Logged

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,350,354,363,369,372,378,381,387,390,396

404,408,413,417,422,426,431,435,440,444,453,459,462,468,471,477,480,486,495,499

503,507,512,516,521,525,530,534,543,549,552,558,561,567,570,576,585,589,594,598

602,606,611,615,620,624,633,639,642,648,651,657,660,666,675,679,684,688,693,697

701,705,710,714,723,729,732,738,741,747,750,756,765,769,774,778,783,787,792,796

800,804,813,819,822,828,831,837,840,846,855,859,864,868,873,877,882,886,891,895

903,909,912,918,921,927,930,936,945,949,954,958,963,967,972,976,981,985,990,994

Theres another one!!

As promised, there it was!

If you played online you spend 50 to 100 to win 225 and if at the store (not reccommended) you spend 100 and win 250

anyway you look at it there some money to be made.

"Many Strategies|One Game"

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