Kentucky United States
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February 14, 2006
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Quote: Originally posted by dr san on Dec 28, 2011
Hello, how can youcreatewheelsunder the following conditions, alotto49 / 6is dividedinto 4 parts In eachof the partiesis drawnnumbers,pairs andtrios example Anumber =17 A pair=26.34 A trio=12,25,46 In each of thefoursectors (industry or haveaquadranthasthe mostnumberone).
First,theunitnumberis drawn, then the bestpairs andtriosthe bestof each sector, the condition has to hitto hita pairor trioall, I wonderhow to combinethe trioof the industrysectorwith par3 withaunityof the sector, and other combinationsas well, on a rotating basis, I do not know how, butI had this idea.
What changes isthe otherwheelsand herewill combinesegments (pairs and triplets)
The warrantySETTINGtendsto hitany trioor pair
A 6/49 zone wheel using 12 numbers with 12 number pairs (66 pairs) with 13 number trios (286 trios) has 226,512 combinations. If you're talking about 12 numbers with 12 pairs with 13 trios, it's 1872 combinations.
I'm not sure what you mean by the fourth part because they only draw 6 numbers.
bgonçalves Brasil
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June 9, 2010
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Quote: Originally posted by Stack47 on Jan 11, 2012
A 6/49 zone wheel using 12 numbers with 12 number pairs (66 pairs) with 13 number trios (286 trios) has 226,512 combinations. If you're talking about 12 numbers with 12 pairs with 13 trios, it's 1872 combinations.
I'm not sure what you mean by the fourth part because they only draw 6 numbers.
Hello, stack, perfectlyok, okme andHans, we are seeing, when alotteryis divided49 / 6 4 sharesinthefoursectors, hasoneof the groups thatcarry moreovera sectorto bezero, we try to createarotating system, to get this condition, any memberthat has thelottery results49 / 6toconfirm this.(stay outof a sectorat the expenseof carryinganindustrygroup (number 12) stack47, if apresolftdoa wholestudybefore mountingthe wheelsbecausethe wheelswill bring togethergroupsofsegmentswith units(numbers)taking advantage ofthe condition ofadjustment of thetrio andpair asabase orreference, making predictionof 4groups isnecessary to providemorethanthewholenumber(49), because there seems to beanassociation inthefourgroups do notrepeatthe positionin90% of the sweepstakes.thenusingthe bell curvein 12numbers,then makeit clearin the otherthreegroups,