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# Divided Wheeling

Topic closed. 7 replies. Last post 4 years ago by Stack47.

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United States
Member #134627
November 2, 2012
1001 Posts
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 Posted: January 2, 2013, 9:41 am - IP Logged

Say, you got 14  numbers you believe should work. To wheel them is too expensive. If you are willing to risk, but spend less, divide 14 numbers into 2 groups of 7, and then wheel each group, that will give you 21 ticket and 21 ticket in Fl Fantasy 5. What can possibly happen with those groups?

1. Each group has zero matching numbers (very unusual for such amount of wheels)

2. One group has 1 number match, another has zero.

3. One group has 2 number match, which means multiple free tickets, and another has nothing.

4. One group has 1 number match, and another has 2 ( multiple free tickets).

5. One group has 3 number match ( means multiple  prices  that 3 number guess can give, multiple \$10s on average), and another has zero.

6. One group has 2 number match and another has 2 number match ( both have multiple free tickets) Don't forget that free tickets might also win something.

7. One group has 1 number match, and another has 3 number match ( also multiple prices for 3 numbers).

8. One group has 2 number match ( multiple free tickets) and another has 3 numbers match ( multiple 3 number prices).

9. One group has zero numbers match, and another has 4 numbers match ( multiple prices that guessing 4 numbers can bring,multiple \$100s ).

10. One group has 1 number match, and another 4 numbers ( multiple \$100s on average).

11. One group has zero matches, and another has 5 ( Bingo! Multiple top prices! Or, rather you divide top price with yourself, if you are the only winner, and if there is another winner, you'll get bigger chunk).

Same goes for 13 numbers, 12 number groups, it is easier to divide them into 2 groups and take chance with that. If there are 10 numbers, make 2 groups of 6 numbers ( six wheels each), if 9, also, the same. 8 numbers can be also divided into two groups of 6, and 7 numbers can be simply wheeled to make 21 ticket, or divided into two groups of 6 for 12 tickets.

United States
Member #134627
November 2, 2012
1001 Posts
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 Posted: January 2, 2013, 10:21 am - IP Logged

Say, you want to divide desirable 14 numbers into 3 groups of 6, so you wheel each 6 numbers and get 18 tickets.

What can happen among those 3 groups? I'll skip the loosing variations, but, say, the group is seemingly good and has 3, 4, or 5 numbers in it.

With 3 numbers in a group of 14, among 3 groups you  can have:

1. 1 number in each group. :(

2. 0,1, and 2 numbers. OK, few free tickets.

3. 0,0, and 3 numbers. Fine, 3 number price multiplied few times.

With 4 number match among 14, how they can spread among 3 groups:

1. 1, 1, and 2 numbers. Ok, few free tickets.

2. 0, 2, and 2 numbers. Ok. Several free tickets.

3. 0, 1, 3. You get few \$10s on average.

4. 0, 0, and 4 numbers. 4 number price few times multiplied.

With 5 number match:

1. 1,1, and 3 numbers. You get few \$10s o average.

2. 1,2,2. You get several free tickets.

3. 0, 2, and 3. Free tickets and few \$10s.

4. 0, 1, 4. You get  few \$100s.

5. 0,0,and 5. You won top price!

Economy class
Belgium
Member #123700
February 27, 2012
4035 Posts
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 Posted: January 2, 2013, 2:52 pm - IP Logged

Too complicated. Just play two 10 number wheels and if you want, then overlap 6 numbers.

Dump Water Florida
United States
Member #380
June 5, 2002
3102 Posts
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 Posted: January 2, 2013, 3:04 pm - IP Logged

Wonderful idea splitting a large group of numbers into two smaller wheels, if your goal is to win 3 number prizes.

Terrible idea if your target is a jackpot due to the poor odds of getting all the winning numbers onto one half or the other.  The odds are the same as an all even all odd or all low or all high draw for the same number of numbers and the you still have to get all six on one line.

BobP

mid-Ohio
United States
Member #9
March 24, 2001
19821 Posts
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 Posted: January 2, 2013, 3:28 pm - IP Logged

Wonderful idea splitting a large group of numbers into two smaller wheels, if your goal is to win 3 number prizes.

Terrible idea if your target is a jackpot due to the poor odds of getting all the winning numbers onto one half or the other.  The odds are the same as an all even all odd or all low or all high draw for the same number of numbers and the you still have to get all six on one line.

BobP

True, there is no short cut for having full coverage without a full wheel.  Anything less, you have to be targeting something less than a jackpot.

* you don't need to buy more tickets, just buy a winning ticket *

United States
Member #116268
September 7, 2011
20244 Posts
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 Posted: January 2, 2013, 3:44 pm - IP Logged

True, there is no short cut for having full coverage without a full wheel.  Anything less, you have to be targeting something less than a jackpot.

I play a 4 if 4 of 12 because when I have all 5 winning numbers theres a 1 in 8 chance of matching 5 of 5.

United States
Member #134627
November 2, 2012
1001 Posts
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 Posted: January 2, 2013, 7:29 pm - IP Logged

To play all 14 numbers combinations one has to play 2002 wheels. Too many, since it is still not known if all 5 numbers are in particular group of 14 numbers.

Kentucky
United States
Member #32652
February 14, 2006
7298 Posts
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 Posted: January 2, 2013, 7:42 pm - IP Logged

To play all 14 numbers combinations one has to play 2002 wheels. Too many, since it is still not known if all 5 numbers are in particular group of 14 numbers.

"Too many, since it is still not known if all 5 numbers are in particular group of 14 numbers."

A wheel is used when you don't know which 5 or any of the 14 numbers will be drawn and it defeats the purpose of wheeling unless you're using key wheels.

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