United States Member #111714 May 31, 2011 104 Posts Offline

Posted: April 2, 2013, 5:34 pm - IP Logged

Quote: Originally posted by onlymoney on April 2, 2013

Trust me, that's an illusion which I fell for the first time. Below is MMM. Five digits in each position. 5X5X5=125. There are another 7 versions you'd have to consider to guarantee a staright hit, since we don't know which version will hit.

The math doesn't lie. What i didn't consider was the first pairs in each group had to be matched up with the last position (3rd) position to make it complete.

Florida, Feb. 19 mid-279 eve-716

MMM

5 0 2

6 1 3

7 2 4

8 3 5

9 4 6

To calculate how much it costs, you multiply the first column to the second column, and then multiply that to the third column.

5X5=25

25X5=125

I'd have to do the above for all 8 versions. 125X8=1000

Florida, Feb. 19 mid-279 eve-716

MMM

5 0 2

6 1 3

7 2 4

8 3 5

9 4 6

Why do you still think this column has 15 numbers?

Park City, UT United States Member #69864 January 18, 2009 993 Posts Offline

Posted: April 2, 2013, 6:10 pm - IP Logged

Another way to look it is that for each position you are making a decision either S or M you can think of that as a coin flip. Each decision leaves you with 5 numbers at each position. So if you were correct in all of your decisions you would have 5*5*5 = 125 combos to guarantee a win. Since their are 8 ways to arrange S and M into 3 positions you would have 125 * 8.

Winsum at one time had a system where you made these coin flip decisions to reduce the matrix based on binary representation of a pick 3 number. I think you had 6 coin flip decisions to leave you with 16 numbers to play. Its not easy to correctly predict 6 coin flips. Your odds are 1 in 64. You would have to have predictive skills of better than 1 in 32 to make it a profitable play. So in essense you have to be twice as good as random.

bgonÃ§alves Brasil Member #92564 June 9, 2010 2125 Posts Offline

Posted: April 2, 2013, 6:31 pm - IP Logged

Hello, Jimmy, yes we yes, 125 combinations of 5x5x5, but I need your help in the following Combine the 5 draws, but not repeating the position Example is in the 1st column digit base this on the second draw your partner can not be the second draw, or just play straight goal is to play in the same position, From each of the five draws, when doing 5x5x5, there are always combinations combinations straight, avoid this goal is to reduce the 125 to less combinations when controlling the frequency of jumps within 5 draws, will be a good reduction, not needing to play the 125 possible, this is the goal!! then filter these conbinaçoes of at most one digit between 200 sweepstakes, or other limit until a couple begins to repeat

To continue with coin flip decisions a good play is making the decision of either low or high for each position. Low being 0-4 digits and high being 5-9 digits.

The above draws were from Idaho Pick3 midday draw.

Sat, Mar 16,2013 157 -> LHH Sun, Mar 17, 2013 085->LHH Mon Mar 18, 2013 821 ->HLL

The rule is this if you see 2 consecutive Low by position then you have 75% chance that the next position in next draw will be high.

The same holds true is if you see two conseutive high by position then you have 75% chance that the next position in next draw will be low.

So if you wait until all 3 positions have 2 consecutive lows or highs in each position you have the optimum time to jump in and make a bet on the next draw.

So you can see that the Saturday draw and Sunday draw lined up perfectly where you had two consecutive draws in the same LH range so it was easy to predict the Monday draw being HLL of course that is a $125 bet. Of course it doesn't always work and $125 is a steep bet to win $500.

If your trying to defeat Pick 3 with math versus patterns then I think looking for coin flip situitions and applying the 75% rule is a good strategy. In other words the 75% rule says that only 25% of the time will you see 3 consecutive heads, or 3 consecutive tails.

Lets say you get 3 consecutive Low's then the odds say you have 87.5 % for the next draw being high in that position. So even if all 3 positions do not line up you might still accurately use this concept to predict 1 position. Using this with a pair system such as Dr. Miracle might be useful in only predicting 1 position.

I have accurately used this concept with RL's dmp program to set filter values. My coin flip for filters is whether the filter value increases of decreases. If I see a filter go from 0 -> 1 -> 2. Then for the next draw I range the filter value between 0 and 1 betting on the filter value to decrease after 2 consecutive increases.

bgonÃ§alves Brasil Member #92564 June 9, 2010 2125 Posts Offline

Posted: April 2, 2013, 7:08 pm - IP Logged

Hello, ok ok! Jimmy very good job, thus meeting the more likely Output, one can discover patterns to divide a list of any U.S. state lotteries, or other record of pick3, split into groups of 5 sweepstakes, and see the frequency of each position, after dividing the sample = 5 in 5 draws on the last group of 5 draws The initial digit of the next lottery draw was in the room, the next one can avoid this And so with the 2nd and 3rd column can even see the delayed digit home (the pivot) in 4 5 groups) the pivot can also be the 2nd and can also be the 3rd column, goal is to avoid playing straight

Kentucky United States Member #32652 February 14, 2006 7314 Posts Offline

Posted: April 2, 2013, 8:29 pm - IP Logged

Quote: Originally posted by jimjwright on April 2, 2013

Another way to look it is that for each position you are making a decision either S or M you can think of that as a coin flip. Each decision leaves you with 5 numbers at each position. So if you were correct in all of your decisions you would have 5*5*5 = 125 combos to guarantee a win. Since their are 8 ways to arrange S and M into 3 positions you would have 125 * 8.

Winsum at one time had a system where you made these coin flip decisions to reduce the matrix based on binary representation of a pick 3 number. I think you had 6 coin flip decisions to leave you with 16 numbers to play. Its not easy to correctly predict 6 coin flips. Your odds are 1 in 64. You would have to have predictive skills of better than 1 in 32 to make it a profitable play. So in essense you have to be twice as good as random.

Jimmy

"I think you had 6 coin flip decisions to leave you with 16 numbers to play."

If the first 3 flips were LHL and the next 3 were OOE, decided "0" is low, the play is 1,3 with 5,7,9 with 0,2,4; 18 straight combos. There are 64 H/L - E/O outcomes, but they have different numbers of plays and deciding "0" as high or low makes a difference. It could be as high as 27 plays, 18, 12, or as low as 8.

u$a United States Member #106665 February 22, 2011 19871 Posts Offline

Posted: April 2, 2013, 8:58 pm - IP Logged

Quote: Originally posted by onlymoney on April 2, 2013

So to prove this may work as it stands right now, until someone can show me ehat I'm doing wrong, I'm going to predict tonight's Florida winner using today's midday winner-630.

To continue with coin flip decisions a good play is making the decision of either low or high for each position. Low being 0-4 digits and high being 5-9 digits.

The above draws were from Idaho Pick3 midday draw.

Sat, Mar 16,2013 157 -> LHH Sun, Mar 17, 2013 085->LHH Mon Mar 18, 2013 821 ->HLL

The rule is this if you see 2 consecutive Low by position then you have 75% chance that the next position in next draw will be high.

The same holds true is if you see two conseutive high by position then you have 75% chance that the next position in next draw will be low.

So if you wait until all 3 positions have 2 consecutive lows or highs in each position you have the optimum time to jump in and make a bet on the next draw.

So you can see that the Saturday draw and Sunday draw lined up perfectly where you had two consecutive draws in the same LH range so it was easy to predict the Monday draw being HLL of course that is a $125 bet. Of course it doesn't always work and $125 is a steep bet to win $500.

If your trying to defeat Pick 3 with math versus patterns then I think looking for coin flip situitions and applying the 75% rule is a good strategy. In other words the 75% rule says that only 25% of the time will you see 3 consecutive heads, or 3 consecutive tails.

Lets say you get 3 consecutive Low's then the odds say you have 87.5 % for the next draw being high in that position. So even if all 3 positions do not line up you might still accurately use this concept to predict 1 position. Using this with a pair system such as Dr. Miracle might be useful in only predicting 1 position.

I have accurately used this concept with RL's dmp program to set filter values. My coin flip for filters is whether the filter value increases of decreases. If I see a filter go from 0 -> 1 -> 2. Then for the next draw I range the filter value between 0 and 1 betting on the filter value to decrease after 2 consecutive increases.

Jimmy

I had never heard of the 75% theory. You can learn something new every day on LP. Thanks for sharing the info.

"You can observe a lot just by watching." Yogi Berra, Hall of Fame baseball player.

The numbers will tell you what numbers to play. Pay attention to the numbers.