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knockout p3

546 replies. Last post 3 days ago by lakerben.

 Page 5 of 37
New Mexico
United States
Member #86099
January 29, 2010
11115 Posts
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 Posted: April 21, 2014, 2:15 pm - IP Logged

Kansas

p3 176

55  55  55

1      7      6

54   48   49

09   93    94

487 last night !

Brookneal,VA
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April 16, 2014
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 Posted: April 21, 2014, 6:59 pm - IP Logged

can you use this method on Doubles.....VA was 898 todays drawing.

New Mexico
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January 29, 2010
11115 Posts
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 Posted: April 22, 2014, 12:31 am - IP Logged

can you use this method on Doubles.....VA was 898 todays drawing.

From the first post.

898 equals 25 root 7.

73 73 73

8   9    8

65   64   65

10   19  10

190  659 190 649 156

New Mexico
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 Posted: April 24, 2014, 10:42 pm - IP Logged

Nm p3

346 sum 13 root 4.

46 46 46

3    4     6

43   42   40

98   97    95

789 579 249 279

New Mexico
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 Posted: April 27, 2014, 2:18 pm - IP Logged

ks

680

14 sum root 5

55 55 55

6   8   0

49  47  55

94  92  00

499 927 505

Pittsburg, Ks
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January 17, 2004
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 Posted: April 27, 2014, 8:35 pm - IP Logged

ks

680

14 sum root 5

55 55 55

6   8   0

49  47  55

94  92  00

499 927 505

Sometimes when I use this system I wheel all the numbers.  I also sometimes heel the sum and mirror numbers. I usually had to many numbers when I wheeled all 12 numbers. BTW your system had Kansas 680 last night .It was random but it was there. Thanks for pencil and paper systems. I like doing them.Good luck

God Bless America

New Mexico
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January 29, 2010
11115 Posts
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 Posted: April 27, 2014, 9:35 pm - IP Logged

Sometimes when I use this system I wheel all the numbers.  I also sometimes heel the sum and mirror numbers. I usually had to many numbers when I wheeled all 12 numbers. BTW your system had Kansas 680 last night .It was random but it was there. Thanks for pencil and paper systems. I like doing them.Good luck

Pittsburg, Ks
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January 17, 2004
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 Posted: April 29, 2014, 10:45 pm - IP Logged

4/29/14

lakerben's Knockp3 283

283=13=4+6=10

46     46    46

2      8      3

44     38    43

99    83     98

3489/333444888999

Kansas winner was 444. I like this system. BTW, I was

backtesting with 10. I tried using it on NM but it didn't seem to work. It did work pretty well for Kansas. Of all  the systems posted tonight your Knockout P3 was the only one to have the winner WTG Benny

God Bless America

New Mexico
United States
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January 29, 2010
11115 Posts
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 Posted: April 30, 2014, 1:57 am - IP Logged

4/29/14

lakerben's Knockp3 283

283=13=4+6=10

46     46    46

2      8      3

44     38    43

99    83     98

3489/333444888999

Kansas winner was 444. I like this system. BTW, I was

backtesting with 10. I tried using it on NM but it didn't seem to work. It did work pretty well for Kansas. Of all  the systems posted tonight your Knockout P3 was the only one to have the winner WTG Benny

Pittsburg, Ks
United States
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January 17, 2004
80629 Posts
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 Posted: April 30, 2014, 9:46 pm - IP Logged

Me too. i am going to try to start using this system for real

God Bless America

New Member
Jacksonville, FL
United States
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April 23, 2014
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 Posted: May 2, 2014, 1:29 pm - IP Logged

First of all, thanks for everything you guys do. I'm new to the forum and I see people have had success with some of the systems provided in the forum. I see how the strategy works but my only questions for this particular system is, how do you get the root number? I'm confused... :/

New Member

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April 8, 2014
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 Posted: May 2, 2014, 6:02 pm - IP Logged

I came upon a small twist to this GREAT "system".

While putting down the two digits that add to ten (in the example 91)
I inadvertently put 19...... so I tried using BOTH the 91 and the 19
and tested the 19 instead of the MIRROR #s.
I only used the mirror numbers when 5 was the root because all the pairs would be duplicates.

For the month of April only 3 days produced NO hits, all the other days
(remember 4 draws per day) produced a minimum or ONE hit.

Example

April 30 morning draw was 5-8-0 =13 root is 4

64     64     64     46   46   46
-5      -8      -0     -5   -8    -0
59     56     64     41    38   46

Pull out all the unique numbers: 5 9 6 4 1 3 8  (sometimes only 4 -5 -6 unique numbers)
Wheel all 7 numbers FOR ONLY THE NEXT DRAW for 50 cents, cost is \$171.50 .

315 HIT for \$450 on the next draw

Knowing that there were only 3 days with out a hit in any of the 4 draws.....

I took a look at starting each day and play until you have a hit and STOP that day.

RESULTS:

57          plays
\$150      bet (average)
\$8550    total bet

24         winning days
\$450     per hit
10800   TOTAL win

NET PROFIT: \$2250 (ON-LINE bets)

New Mexico
United States
Member #86099
January 29, 2010
11115 Posts
Online
 Posted: May 2, 2014, 7:04 pm - IP Logged

I came upon a small twist to this GREAT "system".

While putting down the two digits that add to ten (in the example 91)
I inadvertently put 19...... so I tried using BOTH the 91 and the 19
and tested the 19 instead of the MIRROR #s.
I only used the mirror numbers when 5 was the root because all the pairs would be duplicates.

For the month of April only 3 days produced NO hits, all the other days
(remember 4 draws per day) produced a minimum or ONE hit.

Example

April 30 morning draw was 5-8-0 =13 root is 4

64     64     64     46   46   46
-5      -8      -0     -5   -8    -0
59     56     64     41    38   46

Pull out all the unique numbers: 5 9 6 4 1 3 8  (sometimes only 4 -5 -6 unique numbers)
Wheel all 7 numbers FOR ONLY THE NEXT DRAW for 50 cents, cost is \$171.50 .

315 HIT for \$450 on the next draw

Knowing that there were only 3 days with out a hit in any of the 4 draws.....

I took a look at starting each day and play until you have a hit and STOP that day.

RESULTS:

57          plays
\$150      bet (average)
\$8550    total bet

24         winning days
\$450     per hit
10800   TOTAL win

NET PROFIT: \$2250 (ON-LINE bets)

Good job!

New Member

United States
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April 8, 2014
7 Posts
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 Posted: May 2, 2014, 10:57 pm - IP Logged

Update on my earlier TEXAS P3 test, 58 plays, average quantity of wheel
numbers was 6.19 (mostly 6 or 7 numbers to wheel)

Therefore, the average cost to play is about \$111 per play, including this evening's play (6 PM)
there are 58 plays and 24 wins (actually more than 24 wins but using my method of quiting
after a win that day.

the new net is \$4,362 (using the \$111 average)

I just played the 10PM P3 and wheeled: 1 3 4 5 6 7 9

LETS SEE!

New Mexico
United States
Member #86099
January 29, 2010
11115 Posts
Online
 Posted: May 2, 2014, 11:28 pm - IP Logged

Update on my earlier TEXAS P3 test, 58 plays, average quantity of wheel
numbers was 6.19 (mostly 6 or 7 numbers to wheel)

Therefore, the average cost to play is about \$111 per play, including this evening's play (6 PM)
there are 58 plays and 24 wins (actually more than 24 wins but using my method of quiting
after a win that day.

the new net is \$4,362 (using the \$111 average)

I just played the 10PM P3 and wheeled: 1 3 4 5 6 7 9

LETS SEE!

Good luck Ron!