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# who is willing to test with me my pick3 system at LP prediction page?

Topic closed. 73 replies. Last post 2 years ago by Hans.

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United States
Member #128790
June 2, 2012
5431 Posts
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 Posted: November 27, 2014, 10:44 pm - IP Logged
 Wed, Nov 19, 2014 3-3-2, Lucky Sum: 8?Prize Payouts Tue, Nov 18, 2014 5-5-4, Lucky Sum: 14?Prize Payouts Mon, Nov 17, 2014 8-4-0, Lucky Sum: 12?Prize Payouts Sun, Nov 16, 2014 5-6-3, Lucky Sum: 14?Prize Payouts Sat, Nov 15, 2014 5-2-2, Lucky Sum: 9?Prize Payouts Fri, Nov 14, 2014 1-4-7, Lucky Sum: 12?Prize Payouts Thu, Nov 13, 2014 8-8-2, Lucky Sum: 18?Prize Payouts Wed, Nov 12, 2014 3-4-2, Lucky Sum: 9?Prize Payouts

with key digit 2,you can track back 8 drawings to Wed, Nov 12.,when 3-4-2 hit

so let's suppose every 8 drawing you win with the correct key digit,your overall wager is 10*8=80 dollars,a boxed 6 way paid 80 dollars.

And that means you didn't lose and didn't win.

But when it comes to the time you win within 8 drawings,your prize ratio would be above 100%,and while beyond 8 drawings,below 100%.

It's more about timing and how you calculate to play.

Hans

I'm curious to see a month's worth of back testing in any state where all three numbers from the last winning combo was used as a KEY number. Since about 70% of the time, at least one number repeats from the last draw, it would be interesting to see. Of course the cost triples, but how many more wins would there be?...Enough to justify the cost?

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
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 Posted: November 27, 2014, 11:26 pm - IP Logged

I'm curious to see a month's worth of back testing in any state where all three numbers from the last winning combo was used as a KEY number. Since about 70% of the time, at least one number repeats from the last draw, it would be interesting to see. Of course the cost triples, but how many more wins would there be?...Enough to justify the cost?

Using only one key digit would be profitable while using last 3 digit would bring the total average prize ratio around 80%,so I suggest using 2 digit,either from past drawing or from any system prediction.

my system usually predict one or two digit for play,with 20 tickets!

see the reference at

VERY VERY NICE HANS! Went back and checked these pairs from the beginning of November (in Texas).

With the correct banker they would have hit 35 boxes in 65 draws. Or 27 Boxes and 8 straight with the banker in the 3rd position. yellow = pair; blue = banker; green = straight; orange = double

Texas has four drawings. Morning, Day, Evening and Night. Read across, i.e., 1,3,8,12 would be the morning draw; 4,6,5,15 the day draw; 3,9,4,16 evening, and 7,8,0,15 the night.

Only 1 day (the 7th) with no hits.

But the 13th produced 3 straights in a row.

Don't know if you've noticed, but the BANKER rarely repeats in wins over these 65 draws. With more data that might change.

Now to get wayyyyyy out on a limb with a saw in my hand, playing \$1 a combo (50/50 box/straight hit), one hit a day (\$40 win) would be break even for 4 plays a day (\$10 a draw * 4 draws a day). 2 hits  = \$80 3 hits = \$120

The 13th (three straights) = \$1160. (\$580 for the double and \$290 for the other two)

All told one day -\$40, three days breaking even. Average winning \$180 a day.

But like I said, I'm way out on a limb since it all comes down to picking the right banker.

Definitely MAJOR LEAGUE STUFF HANS!

Thanks,

G

reference by windsome

Calculating the last 100 draws for each state's pick 3 the Side Pairs seem to win the most

Screen shots of Midday, Evening, Combined Front, Back and Side Pairs

https://app.box.com/s/7o3ckz5kcl91l4oumi0s

Of course the key to winning straigt's is selecting the Banker or Key digit whether it be the 1st, 2nd, or 3rd digit.

Pennsylvania Pick 3 Midday draws hit 19 times (side pairs) in the last 100 draws.  The 3,8 side pair being drawn 4 times.

New York Pick 3 Evening draws hit 19 times (side pairs) in the last 100 draws.  The 8,0 side pair drawn 5 times and 3,8 3 4 times.

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Member #90040
April 20, 2010
473 Posts
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 Posted: November 28, 2014, 12:04 am - IP Logged

There is nothing special about "at least one of 3 digits" repeat in the next draw.

You need to play 136 of 220 box combinations or 61.8 % for one guaranteed hit IF at least one of 3 digits hits next time.

Odds are the same for any 3 digits.

United States
Member #59354
March 13, 2008
3985 Posts
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 Posted: November 28, 2014, 6:45 am - IP Logged

MO pick-3 midday and evening combined = 10 hits in 16 games, 5ea MD and EV for a hit rate of .625%.

Figure out a way to pick the correct key and this would be great.  No key, no win.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

United States
Member #59354
March 13, 2008
3985 Posts
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 Posted: November 28, 2014, 9:44 am - IP Logged

Hi all

Here is a simple betting strategy for the pairs hans posted.

4-3

8-0

3-6

4-5

9-0

2-7

3-7

6-4

8-2

3-8

In MO p-3 both midday and evening draws the pairs have hit better than 50% since hans posted the

the list.  I made a few test and found that around every 1 in 3 games a pair of digits taken from the

previous two drawings shows.

Example

11/26/14 = 7-3-1

11/25/14 = 5-3-7 two previous games
11/24/14 = 2-5-7

In the 24th and 25th draws there were 4 total digits that make up both lines 2-3-5-7.  We can get 6 pairs

from these 4 digits.  Red indicates matches from hans list

2-3

2-5

2-7

3-5

3-7

5-7

If we look at the previous 2 drawings digits then convert them to all possible pairs and cross-referenced these

against the pairs posted then we see there are only two.  These are the two pairs we would play for the next

drawing.

When I ran the analysis I only looked for pairs and excluded trays.  What this means is that the key would have

to come from outside digits.  In this case we would be looking at digits 1-4-6-8-9-0 so if everything falls correctly

then it would take 12 lines to cover a box hit playing every possible key.

Given the high hit rates for both it may be worth digging into a little deeper.  Each game setup would be a little

different depending on the number of overall pairs that can be gotten from the previous two drawings.  This may

not work every time but could provide a simple means to reduce the number of lines needed if playing hans list as

one could play just the pairs plus one key digit taken from the outside digits.  These could also be cross-referenced

so that the key digit does not add to the pairs in hans list.

example

if digit 1 were selected as the key then are lines would produce the pairs

1-2

1-3

1-5

1-7

none of which are in hans list

if digit 6 was the key then we would have pairs

6-2

6-3

6-5

6-7

one conflicting pair and if we select 4 as the key then

4-2

4-3  <- key digit adds another pair match

4-5  <- key digit adds another pair match

4-7

etc.............

This could provide a means to play a couple lines with a small investment and still give a good overall

return.  If playing 5 or less lines then one would only have to win around 1 in 20 games to break even.

I will try to do a few more test to see how this would fair but for the test I have ran it looks interesting.

Anyway, just thinking out loud.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

United States
Member #161388
November 28, 2014
83 Posts
Offline
 Posted: November 28, 2014, 9:59 am - IP Logged

Lots of ifs, lots of permutations.  mmx1 seems to have the general analysis down on this one.  Smarter, more out of the box ideas, is what will yield any hidden secrets (= better odds of winning).

MrProgrammer

United States
Member #59354
March 13, 2008
3985 Posts
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 Posted: November 28, 2014, 9:59 am - IP Logged

I made a few errors but think I got them all edited out before the time ran out but might have missed

something so beware.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

ORLANDO, FLORIDA
United States
Member #4924
June 3, 2004
5912 Posts
Offline
 Posted: November 28, 2014, 10:01 am - IP Logged

VERY VERY NICE HANS! Went back and checked these pairs from the beginning of November (in Texas).

With the correct banker they would have hit 35 boxes in 65 draws. Or 27 Boxes and 8 straight with the banker in the 3rd position. yellow = pair; blue = banker; green = straight; orange = double

Texas has four drawings. Morning, Day, Evening and Night. Read across, i.e., 1,3,8,12 would be the morning draw; 4,6,5,15 the day draw; 3,9,4,16 evening, and 7,8,0,15 the night.

Only 1 day (the 7th) with no hits.

But the 13th produced 3 straights in a row.

Don't know if you've noticed, but the BANKER rarely repeats in wins over these 65 draws. With more data that might change.

Now to get wayyyyyy out on a limb with a saw in my hand, playing \$1 a combo (50/50 box/straight hit), one hit a day (\$40 win) would be break even for 4 plays a day (\$10 a draw * 4 draws a day). 2 hits  = \$80 3 hits = \$120

The 13th (three straights) = \$1160. (\$580 for the double and \$290 for the other two)

All told one day -\$40, three days breaking even. Average winning \$180 a day.

But like I said, I'm way out on a limb since it all comes down to picking the right banker.

Definitely MAJOR LEAGUE STUFF HANS!

Thanks,

G

Gary,

Have you or anyone else did any testing using ,"completing the cycle?" I think I got the expression from lotterybraker. The values on the right are the number of draws for 0,1 to complete the cycle.

 0,1 11/28/14 4 8 7 2 11/27/14 3 5 1 1 11/26/14 3 0 8 2 11/26/14 7 5 9 5 11/25/14 1 5 4 4 11/25/14 9 2 4 3 11/24/14 1 1 8 2 11/24/14 6 4 7 1 11/23/14 8 1 0 0

United States
Member #59354
March 13, 2008
3985 Posts
Offline
 Posted: November 28, 2014, 10:03 am - IP Logged

MrProgrammer

Don't need permutations if playing box, read what is said.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

Tn
United States
Member #54963
September 4, 2007
1164 Posts
Offline
 Posted: November 28, 2014, 1:53 pm - IP Logged

Hi all

Here is a simple betting strategy for the pairs hans posted.

4-3

8-0

3-6

4-5

9-0

2-7

3-7

6-4

8-2

3-8

In MO p-3 both midday and evening draws the pairs have hit better than 50% since hans posted the

the list.  I made a few test and found that around every 1 in 3 games a pair of digits taken from the

previous two drawings shows.

Example

11/26/14 = 7-3-1

11/25/14 = 5-3-7 two previous games
11/24/14 = 2-5-7

In the 24th and 25th draws there were 4 total digits that make up both lines 2-3-5-7.  We can get 6 pairs

from these 4 digits.  Red indicates matches from hans list

2-3

2-5

2-7

3-5

3-7

5-7

If we look at the previous 2 drawings digits then convert them to all possible pairs and cross-referenced these

against the pairs posted then we see there are only two.  These are the two pairs we would play for the next

drawing.

When I ran the analysis I only looked for pairs and excluded trays.  What this means is that the key would have

to come from outside digits.  In this case we would be looking at digits 1-4-6-8-9-0 so if everything falls correctly

then it would take 12 lines to cover a box hit playing every possible key.

Given the high hit rates for both it may be worth digging into a little deeper.  Each game setup would be a little

different depending on the number of overall pairs that can be gotten from the previous two drawings.  This may

not work every time but could provide a simple means to reduce the number of lines needed if playing hans list as

one could play just the pairs plus one key digit taken from the outside digits.  These could also be cross-referenced

so that the key digit does not add to the pairs in hans list.

example

if digit 1 were selected as the key then are lines would produce the pairs

1-2

1-3

1-5

1-7

none of which are in hans list

if digit 6 was the key then we would have pairs

6-2

6-3

6-5

6-7

one conflicting pair and if we select 4 as the key then

4-2

4-3  <- key digit adds another pair match

4-5  <- key digit adds another pair match

4-7

etc.............

This could provide a means to play a couple lines with a small investment and still give a good overall

return.  If playing 5 or less lines then one would only have to win around 1 in 20 games to break even.

I will try to do a few more test to see how this would fair but for the test I have ran it looks interesting.

Anyway, just thinking out loud.

RL

Keep us up what you find RL!! Interesting!

WHEN IT FEELS THE WHOLE WORLD SUCKS!

RELAX.........IT'S ONLY GRAVITY

I think I can I think I can!!!!

Park City, UT
United States
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January 18, 2009
993 Posts
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 Posted: November 28, 2014, 2:25 pm - IP Logged

You guys realize that the 10 pairs Hans posted equate to 450 combinations out of the 1000 possible.

So you can expect one of these pairs to hit 45% of the time.

Digit 1 is excluded from the pairs so unless you choose 1 as your key digit you have excluded 271 combinations from consideration.

Benford followers would never exclude digit 1.

Maybe Hans has a good method for picking the key digit but I will pass on the specified 10 pairs.  After all successfully picking the key digit is all that is really needed to win Pick 3 everything else is just gravy.

Jimmy

United States
Member #116344
September 8, 2011
3928 Posts
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 Posted: November 28, 2014, 2:42 pm - IP Logged

Subsetting is a sampling choice, anytime you bet, your filter out some digits of the total 1000 combos. The focus is which section of pool need to be filtered out or sampled. Stat percentile is a waging tool, not a predictive method.

Hint> Position 1 digit + NP2 (straight) or   Position 1 +NC2 (box) hit, Number of picks is dependent on size of N, remember, that  a digit returns most often.

Park City, UT
United States
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January 18, 2009
993 Posts
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 Posted: November 28, 2014, 3:02 pm - IP Logged

Subsetting is a sampling choice, anytime you bet, your filter out some digits of the total 1000 combos. The focus is which section of pool need to be filtered out or sampled. Stat percentile is a waging tool, not a predictive method.

Hint> Position 1 digit + NP2 (straight) or   Position 1 +NC2 (box) hit, Number of picks is dependent on size of N, remember, that  a digit returns most often.

If you were responding to me I never said Stat percentile is a predictive method.  What I said was predicting the key digit by whatever means is more important than some randomly selected static 10 pairs.

Jimmy

United States
Member #116344
September 8, 2011
3928 Posts
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 Posted: November 28, 2014, 3:21 pm - IP Logged

Subsetting is a sampling choice, anytime you bet, your filter out some digits of the total 1000 combos. The focus is which section of pool need to be filtered out or sampled. Stat percentile is a waging tool, not a predictive method.

Hint> Position 1 digit + NP2 (straight) or   Position 1 +NC2 (box) hit, Number of picks is dependent on size of N, remember, that  a digit returns most often.

Fri, Nov 28, 2014 Thu, Nov 27, 2014 Wed, Nov 26, 2014 Tue, Nov 25, 2014 Drawing Date Pick 3 Pick 4 Midday Evening Midday Evening 5-5-7 1-5-4-5 3-5-1 4-8-7 9-1-3-1 0-4-2-0 7-5-9 3-0-8 2-0-3-7 5-6-5-0 9-2-4 1-5-4 6-0-1-5 5-5-8-9 6-4-7 1-1-8 9-1-6-6 3-3-8-6 8-0-7 8-1-0 9-7-1-7 5-2-6-1 4-9-2 3-0-5 0-9-8-2 8-0-4-4 5-6-4 0-1-1 1-7-7-5 3-5-3-7 9-8-4 3-8-0 3-4-9-7 6-1-4-2 6-5-5 1-5-7 1-5-6-3 5-1-6-4

Consider the draw set 564 , with key digits 7,4 as next position 1, I will set the size of N=5, why? based on observations that digit returns, members of N> 5,6,4,9,8,4,6,5,5> 56498

Picks for straight> 7 + 5P2(no digit repeat)> 20 picks>{5,6} {5,4} {5,9} {5,8} {6,5} {6,4} {6,9} {6,8} {4,5} {4,6} {4,9} {4,8} {9,5} {9,6} {9,4} {9,8} {8,5} {8,6} {8,4} {8,9}> hit 759

Total cost after  5 draws(a type draw-midday) for two keys 7, 4 will be \$40 x5 for profit of \$300

Try draw 380> key 8,1> N= 6, N[ 3,8,0,1,5,7]

Picks> 8+6P2> 3,8} {3,0} {3,1} {3,5} {3,7} {8,3} {8,0} {8,1} {8,5} {8,7} {0,3} {0,8} {0,1} {0,5} {0,7} {1,3} {1,8} {1,0} {1,5} {1,7} {5,3} {5,8} {5,0} {5,1} {5,7} {7,3} {7,8} {7,0} {7,1} {7,5}

Cost> 60 picks x 4 draws(evening draws)> 240 for prize of  \$1000+  with hits 810,118

NB> You're subsetting and filtering through the choice key digits (predictive method) and Permutation(waging strategy).

United States
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September 8, 2011
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 Posted: November 28, 2014, 3:42 pm - IP Logged

If you were responding to me I never said Stat percentile is a predictive method.  What I said was predicting the key digit by whatever means is more important than some randomly selected static 10 pairs.

Jimmy

No, was not responding to you, was just giving information that might help any body.

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