Welcome Guest
You last visited December 10, 2016, 7:35 am
All times shown are
Eastern Time (GMT-5:00)

# I need help calculating my odds

Topic closed. 19 replies. Last post 2 years ago by Stack47.

 Page 1 of 2

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 7, 2015, 7:43 pm - IP Logged

If I play pick 3 (1 in 1,000), AND pick 4 exact (1 in 10,000), what are my overall combined odds of winning something?

United States
Member #41846
June 23, 2006
460 Posts
Offline
 Posted: February 8, 2015, 4:39 am - IP Logged

1/1000=.001 and 1/10000=.0001 so .001+.0001=.0011

mid-Ohio
United States
Member #9
March 24, 2001
19831 Posts
Offline
 Posted: February 8, 2015, 4:30 pm - IP Logged

If I play pick 3 (1 in 1,000), AND pick 4 exact (1 in 10,000), what are my overall combined odds of winning something?

Depends on how you're playing.  Check your lottery website to see the odds and payouts for winning a straight, a box or a pair.

* you don't need to buy more tickets, just buy a winning ticket *

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 8, 2015, 7:19 pm - IP Logged

Depends on how you're playing.  Check your lottery website to see the odds and payouts for winning a straight, a box or a pair.

I'm playing EXACT, pick 3 is 1 in 1,000 and pick 4 is 1 in 10,000 .

What are my overall combined chances of winning something?

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 8, 2015, 7:22 pm - IP Logged

1/1000=.001 and 1/10000=.0001 so .001+.0001=.0011

Are you saying that my combined overall odds are 1 in 11,000 or would it mean 2 in 11,000 since I have a total of two tickets?

United States
Member #41846
June 23, 2006
460 Posts
Offline
 Posted: February 9, 2015, 6:15 am - IP Logged

Are you saying that my combined overall odds are 1 in 11,000 or would it mean 2 in 11,000 since I have a total of two tickets?

no. you have two chances to win.   the probability of winning either game does not change. you have 1 chance in 1000 of hitting a pick 3 and 1 chance in 10000 of hitting a pick 4.

so combined you have 1 chance in 1000 of hitting a pick3 str (.001) and 1 chance of hitting a pick 4 str (.0001).  when you combine those two terms you have .0011 which is misleading, if you think this means you have increased or decreased you chance of hitting a pick3 or pick 4

mid-Ohio
United States
Member #9
March 24, 2001
19831 Posts
Offline
 Posted: February 9, 2015, 1:50 pm - IP Logged

I'm playing EXACT, pick 3 is 1 in 1,000 and pick 4 is 1 in 10,000 .

What are my overall combined chances of winning something?

In that case your best chance of winning something is 1 in 1,000 and your worst is 1 in 10,000, just combine them to get your overall combined chance.

* you don't need to buy more tickets, just buy a winning ticket *

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 9, 2015, 4:16 pm - IP Logged

In that case your best chance of winning something is 1 in 1,000 and your worst is 1 in 10,000, just combine them to get your overall combined chance.

I'm wondering if they can even be combined, since they're separate games.

If they can be combined, what are my combined odds, is it 1 in 11,000 or 2 in 11,000?

If it's 2 in 11,000 since I have two tickets, is that the same as 1 in 5,500?

mid-Ohio
United States
Member #9
March 24, 2001
19831 Posts
Offline
 Posted: February 9, 2015, 8:54 pm - IP Logged

I'm wondering if they can even be combined, since they're separate games.

If they can be combined, what are my combined odds, is it 1 in 11,000 or 2 in 11,000?

If it's 2 in 11,000 since I have two tickets, is that the same as 1 in 5,500?

Sometimes what seems obvious isn't correct, for example MegaMillions has 15 megaballs so you would think your odds of matching 0+1 would be 1:15 but it's 1:21 when it's calculated.

* you don't need to buy more tickets, just buy a winning ticket *

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 9, 2015, 9:22 pm - IP Logged

That has to be a typo.  I noticed the same thing on Powerball.  For Powerball it says to pick a powerball from 1 to 35 but then it says the odds of getting the powerball are 1:55

So, if you play MegaMillions and buy 15 tickets, each with a megaball from 1 to 15 then your odds are clearly 1:1 aren't they?

In other words if you buy the 15 megaballs then your chances of wining the megaball are 100%, so why do they say 1 in 21?

Park City, UT
United States
Member #69864
January 18, 2009
993 Posts
Offline
 Posted: February 10, 2015, 12:15 am - IP Logged

The odds of not winning a single exact pick3 is 999/1000.

The odds of not winning a single exact pick4 is 9999/10000.

So the odds of not winning both pick3 and pick4 would be 999/1000 * 9999/10000 which is .9989001.

So the odds of winning either a pick3 or pick4 would be 1 - .9989001 or .0010999

Jimmy

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 10, 2015, 12:20 am - IP Logged

so how is .0010999 described as 1 in how many?

another question, I'm not saying I want the odds of winning both, I'm saying what are the odds of winning anything if I play both?

Park City, UT
United States
Member #69864
January 18, 2009
993 Posts
Offline
 Posted: February 10, 2015, 12:24 am - IP Logged

The odds of getting exactly 0 WB and 1 PB is 1 in 55.

Its possible that you will get a WB along with the PB so that's why its not in 1 in 35.

Match 0 out of 5 white balls and match the Powerball (Payout = \$4)
The number of ways 0 of the 5 winning numbers on your lottery ticket can match the 5 white balls is COMBIN(5,0) = 1. The number of ways the 5 losing white numbers on your ticket can match any of the 54 losing white numbers is COMBIN(54,5) = 3,162,510.  The number of ways your Powerball number can match the single Powerball number is: COMBIN(1,1) = 1. The product of these is the number of ways you can win this configuration:  COMBIN(5,0) x COMBIN(54,5) x COMBIN(1,1) = 3,162,510. The probability of success is thus: 3,162,510/175,223,510 = 0.018048434+ or “One chance in 55.41”.

Jimmy

Park City, UT
United States
Member #69864
January 18, 2009
993 Posts
Offline
 Posted: February 10, 2015, 12:41 am - IP Logged

so how is .0010999 described as 1 in how many?

another question, I'm not saying I want the odds of winning both, I'm saying what are the odds of winning anything if I play both?

I just told you the probability of winning either pick 3 or pick 4 is 1 - .9989001 or .0010999.

If you want to express as odds then you will be successful 10999 times and unsuccessful 9989001 times out of 10,000,000 trials.

So the odds would be expressed as 10999:9989001

Jimmy

United States
Member #67870
December 7, 2008
154 Posts
Offline
 Posted: February 10, 2015, 1:07 am - IP Logged

thanks jimjwright, I thought the lottery had a typo, but your explanation makes sense.

and are the odds expressed as 10999:9989001 the same as saying 1 in 908?

 Page 1 of 2