Tricks for texas daily numbers 3 digit with 1 pair to usePrev TopicNext Topic

• Tialuvslotto

  

  Texas
  United States
  Member #150,790
  December 31, 2013
  824 Posts
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  Dec 10, 2015, 8:34 am

  ▲▼
  In response to ALX

  Quote: Originally posted by ALX on Dec 9, 2015

  Please look at hilbilly's first post at the top of the page and you will see the winning P3 numbers and the P4 numbers listed by date. Look at both Nov 24th P4 first and last digits=2 3  3 8 now look at the next day winning P3 number= 832. Look at both Dec 1st P4 first and last digits= 3 9  1 1 now look at the next day winning P3 winning number= 913. Easy, right?

  So you wait to play until Pick 4 Morn-Eve and Mid-Nite share a digit then play the combined pairs?

  Well done ALX! 

  "There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

  ~Robert A. Heinlein
• ALX

  

  Maine
  United States
  Member #99
  January 27, 2002
  4,360 Posts
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  Dec 10, 2015, 4:21 pm

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  Just in case anybody thinks hillbilly's ideas are not awesome....

  The last two P4 winners in Texas were:

  0436...1st and last digits are 0 xx 6 or pair 06

  5698...1st and last digits are 5 xx 8 or pair 58 

  Today the first two Texas P3 numbers were 680 and 905 

  If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

  06 *

  05 *

  08 *

  65

  68 *

  58

  680 has the pairs 06, 08, and 68

  905 has the pair 05

  If it wasn't impossible I wouldn't even consider it!  As Gail Howard used to say, "What happens most is what is most likely to happen".
• MrsGH01

  

  Brenham
  United States
  Member #155,738
  May 28, 2014
  2,253 Posts
  Offline
  Dec 11, 2015, 6:41 am

  ▲▼
  In response to ALX

  Quote: Originally posted by ALX on Dec 10, 2015

  Just in case anybody thinks hillbilly's ideas are not awesome....

  The last two P4 winners in Texas were:

  0436...1st and last digits are 0 xx 6 or pair 06

  5698...1st and last digits are 5 xx 8 or pair 58 

  Today the first two Texas P3 numbers were 680 and 905 

  If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

  06 *

  05 *

  08 *

  65

  68 *

  58

  680 has the pairs 06, 08, and 68

  905 has the pair 05

  hi Alx or Hillbilly  so yesterday results were 

  5726

  0203

  2963

  0758

  so now the pairs would be 

  50

  20

  63

  68

  56

  26

  03

  08

  is this correct thanks for your help

               Mrsg01
• ALX

  

  Maine
  United States
  Member #99
  January 27, 2002
  4,360 Posts
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  Dec 11, 2015, 12:05 pm

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  In response to MrsGH01

  Quote: Originally posted by MrsGH01 on Dec 11, 2015

  hi Alx or Hillbilly  so yesterday results were 

  5726

  0203

  2963

  0758

  so now the pairs would be 

  50

  20

  63

  68

  56

  26

  03

  08

  is this correct thanks for your help

  No, you have 2963 and the number was 2936. I would just use the last two P4 winners, 2 93 6 and 0 75 8 and their 1st and last numbers, which are ...2-6-0-8 ....then make the four combos that they are...260 268 208 and 608. (You had 680 yesterday so unless you think it will repeat exactly, you can eliminate it). Or you could make six pairs from those four numbers and add a third number...... 

  26

  20

  28

  60

  68

  08

  You can use the first and last numbers from the last four P4 winners if you like, but it gives a lot of combos and pairs.

  This is a quick and easy method that uses a small number of combos and sometimes works. Today the 1st Texas P3 was 819...so it did not work today... yet. Play with it and see how it does. Good Luck!

  If it wasn't impossible I wouldn't even consider it!  As Gail Howard used to say, "What happens most is what is most likely to happen".
• ALX

  

  Maine
  United States
  Member #99
  January 27, 2002
  4,360 Posts
  Offline
  Dec 11, 2015, 12:18 pm

  ▲▼
  In response to ALX

  Quote: Originally posted by ALX on Dec 10, 2015

  Just in case anybody thinks hillbilly's ideas are not awesome....

  The last two P4 winners in Texas were:

  0436...1st and last digits are 0 xx 6 or pair 06

  5698...1st and last digits are 5 xx 8 or pair 58 

  Today the first two Texas P3 numbers were 680 and 905 

  If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

  06 *

  05 *

  08 *

  65

  68 *

  58

  680 has the pairs 06, 08, and 68

  905 has the pair 05

  Just to be clear, in this post I meant to say that we had the pairs 06 58. If we combine these pairs = 0658 we can make only four combos = 065 068 058 and 658. 680 was a winning number and so we had 068 as a box hit.

  Good Luck!

  If it wasn't impossible I wouldn't even consider it!  As Gail Howard used to say, "What happens most is what is most likely to happen".