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Tricks for texas daily numbers 3 digit with 1 pair to use

Topic closed. 19 replies. Last post 12 months ago by ALX.

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Tialuvslotto's avatar - Jailin
Texas
United States
Member #150797
December 31, 2013
815 Posts
Offline
Posted: December 10, 2015, 8:34 am - IP Logged

Please look at hilbilly's first post at the top of the page and you will see the winning P3 numbers and the P4 numbers listed by date. Look at both Nov 24th P4 first and last digits=2 3  3 8 now look at the next day winning P3 number= 832. Look at both Dec 1st P4 first and last digits= 3 9  1 1 now look at the next day winning P3 winning number= 913. Easy, right?

So you wait to play until Pick 4 Morn-Eve and Mid-Nite share a digit then play the combined pairs?

Well done ALX! Banana

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

~Robert A. Heinlein

    Avatar
    Maine
    United States
    Member #99
    January 27, 2002
    1013 Posts
    Online
    Posted: December 10, 2015, 4:21 pm - IP Logged

    Just in case anybody thinks hillbilly's ideas are not awesome....

    The last two P4 winners in Texas were:

    0436...1st and last digits are 0 xx 6 or pair 06

    5698...1st and last digits are 5 xx 8 or pair 58 

    Today the first two Texas P3 numbers were 680 and 905 

    If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

    06 *

    05 *

    08 *

    65

    68 *

    58

    680 has the pairs 06, 08, and 68

    905 has the pair 05

    If it wasn't impossible I wouldn't even consider it!

      MrsGH01's avatar - yesnurse

      United States
      Member #155745
      May 28, 2014
      982 Posts
      Offline
      Posted: December 11, 2015, 6:41 am - IP Logged

      Just in case anybody thinks hillbilly's ideas are not awesome....

      The last two P4 winners in Texas were:

      0436...1st and last digits are 0 xx 6 or pair 06

      5698...1st and last digits are 5 xx 8 or pair 58 

      Today the first two Texas P3 numbers were 680 and 905 

      If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

      06 *

      05 *

      08 *

      65

      68 *

      58

      680 has the pairs 06, 08, and 68

      905 has the pair 05

      hi Alx or Hillbilly  so yesterday results were 

      5726

      0203

      2963

      0758

      so now the pairs would be 

      50

      20

      63

      68

      56

      26

      03

      08

      is this correct thanks for your help

      MrsGH01

        Avatar
        Maine
        United States
        Member #99
        January 27, 2002
        1013 Posts
        Online
        Posted: December 11, 2015, 12:05 pm - IP Logged

        hi Alx or Hillbilly  so yesterday results were 

        5726

        0203

        2963

        0758

        so now the pairs would be 

        50

        20

        63

        68

        56

        26

        03

        08

        is this correct thanks for your help

        No, you have 2963 and the number was 2936. I would just use the last two P4 winners, 2 93 6 and 0 75 8 and their 1st and last numbers, which are ...2-6-0-8 ....then make the four combos that they are...260 268 208 and 608. (You had 680 yesterday so unless you think it will repeat exactly, you can eliminate it). Or you could make six pairs from those four numbers and add a third number...... 

        26

        20

        28

        60

        68

        08

        You can use the first and last numbers from the last four P4 winners if you like, but it gives a lot of combos and pairs.

        This is a quick and easy method that uses a small number of combos and sometimes works. Today the 1st Texas P3 was 819...so it did not work today... yet. Play with it and see how it does. Good Luck!

        If it wasn't impossible I wouldn't even consider it!

          Avatar
          Maine
          United States
          Member #99
          January 27, 2002
          1013 Posts
          Online
          Posted: December 11, 2015, 12:18 pm - IP Logged

          Just in case anybody thinks hillbilly's ideas are not awesome....

          The last two P4 winners in Texas were:

          0436...1st and last digits are 0 xx 6 or pair 06

          5698...1st and last digits are 5 xx 8 or pair 58 

          Today the first two Texas P3 numbers were 680 and 905 

          If you combine these two pairs you have 0658 and if you make pairs from these four numbers you have

          06 *

          05 *

          08 *

          65

          68 *

          58

          680 has the pairs 06, 08, and 68

          905 has the pair 05

          Just to be clear, in this post I meant to say that we had the pairs 06 58. If we combine these pairs = 0658 we can make only four combos = 065 068 058 and 658. 680 was a winning number and so we had 068 as a box hit.

          Good Luck!

          If it wasn't impossible I wouldn't even consider it!