(New member) Have any of you broken down a keno game?Prev Topic Next Topic

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Apr 22, 2017, 10:26 pm

Hello everyone. Have any of you broken down a keno game?

Out of a pool of 80 numbers, 20 are drawn. Order drawn is not important, so the numbers are put in numerical order afterward. (Forget about the tickets, or playing, just looking at the draw data.)

Selecting 20 out of 80, means that each number has a 25% chance of being drawn. The trick is that every number has the same total chance of being drawn, but not the same chance of being drawn in every place. (Example: The numbers 1 and 80, can only ever be the first and last numbers respectively. While the number 5 could be in any of the five lowest numbers drawn.) This means that 1 has a 25% chance of being drawn in the first (lowest number) slot, and 80 has a 25% chance of being drawn in the 20th (highest) slot.

The location chances of the first 10 numbers would be:

Num	Slot1	Slot2	Slot3	Slot4	Slot5	Slot6	Slot7	Slot8	Slot9	Slot10	Slot11
1	0.25
2	0.1899	0.0601
3	0.1436	0.0925	0.0139
4	0.1082	0.1063	0.0324	0.0031
5	0.0811	0.1082	0.0504	0.0097	0.0006
6	0.0606	0.1028	0.0649	0.019	0.0026	0.0001
7	0.045	0.0933	0.075	0.0298	0.0062	0.0006	2E-05
8	0.0333	0.082	0.0805	0.0408	0.0114	0.0018	0.0001	4E-06
9	0.0245	0.0703	0.082	0.0507	0.0181	0.0038	0.0005	3E-05	7E-07
10	0.018	0.0591	0.0802	0.0589	0.0257	0.0069	0.0011	0.0001	6E-06	1E-07

The blank spaces above indicate impossibilities.

Thanks- Just looking to see if I can find some like minds.

Datapile

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Apr 23, 2017, 10:51 am

If we accept the base chance percentage of 25%, then out of any pool of numbers an average of 25% of them will be drawn.

Applying this to the drawing that has come just before current, we should see an average of 5 numbers repeat in the current drawing. (Lets call this previous drawing D1, as it is 1 drawing ago.)

Count D1

0 0.1%

1 1.1%

2 5.0%

3 12.5%

4 20.4%

5 23.3%

6 19.0%

7 11.4%

8 5.0%

9 1.7%

10 0.4%

11 0.1%

12 0.0%

13 0.0%

14 0.0%

Average 5.0

This tells us that any current drawing will have between 1 and 10 numbers from the previous drawing. Any 20 number combination with less than 1 common number, or more than 10 will be wrong 99.8% of the time.

Datapile

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Apr 23, 2017, 11:02 am

Let us push on, and go further backward in time...

If D1 was the drawing just before current, then D2 is the drawing 2 back and so on.

If each drawing has numbers that repeat with any other drawing, what if we look at the numbers that haven't repeated?

For the drawing D2, of the pool of numbers that didn't get drawn in D1 (average of 15), how many will be drawn in the current drawing? 15 * 25% = 3.7.

Looking at historical data, we find the average is indeed 3.7. We also see that any 20 number combination that contains more than 9 numbers from this (undrawn D2) pool will be wrong.

Count	D1	D2
0	0.1%	1.0%
1	1.1%	5.8%
2	5.0%	15.1%
3	12.5%	23.6%
4	20.4%	24.1%
5	23.3%	17.2%
6	19.0%	8.8%
7	11.4%	3.3%
8	5.0%	0.9%
9	1.7%	0.2%
10	0.4%	0.0%
11	0.1%	0.0%
12	0.0%	0.0%
13	0.0%
14	0.0%
Average	5.0	3.7

Datapile

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Apr 23, 2017, 11:17 am

If we keep going backward, up to 10 drawings back, with numbers that have only been drawn once, we find that there is actionable information contained in the historical data.

Count	D1	D2	D3	D4	D5	D6	D7	D8	D9	D10
0	0.1%	1.0%	3.7%	9.3%	17.8%	28.1%	39.2%	50.0%	59.7%	68.1%
1	1.1%	5.8%	14.6%	25.2%	33.6%	38.2%	38.8%	36.0%	31.7%	26.8%
2	5.0%	15.1%	25.5%	30.0%	28.5%	23.2%	17.0%	11.5%	7.4%	4.6%
3	12.5%	23.6%	26.1%	21.4%	14.2%	8.2%	4.3%	2.1%	1.0%	0.5%
4	20.4%	24.1%	17.9%	10.0%	4.6%	1.9%	0.7%	0.3%	0.1%	0.0%
5	23.3%	17.2%	8.4%	3.2%	1.0%	0.3%	0.1%	0.0%	0.0%	0.0%
6	19.0%	8.8%	2.9%	0.7%	0.2%	0.0%	0.0%	0.0%	0.0%	0.0%
7	11.4%	3.3%	0.7%	0.1%	0.0%	0.0%	0.0%
8	5.0%	0.9%	0.1%	0.0%	0.0%	0.0%
9	1.7%	0.2%	0.0%	0.0%	0.0%
10	0.4%	0.0%	0.0%	0.0%
11	0.1%	0.0%	0.0%
12	0.0%	0.0%
13	0.0%
14	0.0%
Average	5.0	3.7	2.8	2.1	1.6	1.2	0.9	0.7	0.5	0.4

Add all of the numbers drawn at each distance D1-D10 in the current drawing, and we find that 30% of the time we will reach 20. However now we also know roughly how many will come from each distance pool.

D1_10 Sum	Chance
12	0%
13	0%
14	0%
15	0%
16	2%
17	7%
18	22%
19	38%
20	30%

Novan60

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Apr 23, 2017, 4:14 pm

Keno has been my game of choice because within each drawing there are tens of thousand of possible patterns to try and match. Each drawing is like playing 184,756 lotto drawings. I've managed to hit 9 out of 10 twice and averaged above the statistical average on the 8's and 7's.

Every strategy that I have explored always breaks down to the base 1 in 4 odds. The problem is that while it averages out to that over time in a given window it can go as high as 1 in 62 or as frequent as 8 in 8.

I have decided to focus on strategies that require me to make as few choices as possible with the least possible amount of variables for each choice that are based on target conditions a winning set is consistently made up of.

For example we can see that over the next 7 drawings there is a 95% chance that on average 146 winning number sets will appears where all 10 of the numbers appeared in a 4,3,4,4 pattern in the four prior drawings. For the 4's there are 4,845 possible winning combinations and 1,140 for the 3's. If I can get the odds of picking the right one down to 1 in 20 50% of the time I'll be happy as that would give me 1 in 160,000 chance of winning 50% of the time.
Datapile

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Apr 23, 2017, 5:35 pm

I've been doing this solo for years, so I'm a little behind on the terminology- So in one of the next 10 drawings there will be : 4 numbers from the last drawing, 3 numbers from the 2nd one back, 4 in the 3rd, and 4 in the 4th?

I'm foolhardy- have this crazy notion that it's possible to build a multifaceted model, where by I can find all 20 numbers. The trick is giving a program a clear set of steps, so that it can narrow down several broad categories, until the last step is finding the combination that fits all the adjusted criteria.

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas
Novan60

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Apr 23, 2017, 7:40 pm

Quote: Originally posted by Datapile on Apr 23, 2017
I've been doing this solo for years, so I'm a little behind on the terminology- So in one of the next 10 drawings there will be : 4 numbers from the last drawing, 3 numbers from the 2nd one back, 4 in the 3rd, and 4 in the 4th?

I'm foolhardy- have this crazy notion that it's possible to build a multifaceted model, where by I can find all 20 numbers. The trick is giving a program a clear set of steps, so that it can narrow down several broad categories, until the last step is finding the combination that fits all the adjusted criteria.

No worries on terminology. Like you I have been doing this solo for a long time as well and have made up my own terminology along the way.

It was 7 days not 10, but you have the basic idea. When looking at the next X drawings from a given point in time we can see that the numbers appeared together in certain patterns in the previous drawings. In NY the jackpot is to match 10 numbers so I limited my results to only include combinations where all 10 of the numbers appeared in the previous 4 drawings.

Here is what it looks like i the next 28 drawings.

Here is what it looks like in the next 56 drawings.

Here is what it looks like when we go back 8 drawings and look at the next 28. Notice the sharp decline in average hits, that occurs because the further back we go the more defined our possibilities become. Unfortunately in order to go back enough drawings to accurately identify a playable amount of numbers we have to go several thousand drawings into the future until that number hits.

That said what it does do is provide some focus on where we can intelligently pick from with some assurance that we have not calculated ourselves out from any chance of winning.

Similarly we can look at the previous day's drawing and pick from 1 in 184,756 possible combinations and we can see that by drawing 328 there is an 89% chance that 15 of those 184, 756 will appear again as winners. That works out to be 1 in 12,317 89% of the time. Conversely I take that same 328 dollars and sink it into a single drawing my odds of winning are 1 in 27,170 100% of the time.

Normally I sample these for 1000-5000 day periods, but I did not save the results when I ran this one. When I ran it for full 1000 the end percentage had dropped down to somewhere under 70% if I remember correctly.

Here is the same process if I only target 6 digits. Of the 38,760 combinations of 6 digits on average 78 of them will appear by drawing 15 with 295 by drawing 56. That means that if I play the full 56 drawings I have a 1 in 131 chance of picking the correct 6 digits.

The problem is that these number appear consistently because of the volume of potential combinations that make them possible. In the end it still roughly conforms to the same 1 in 4 odds. The more conditions that get put in place to narrow down the numbers the longer the frequency between when that pattern appears as a winner.

The other part is that one condition may hold true 100% of the time but only yields 1 digit. When the condition is added for the second digit that 100% drops down to about 56%. And while the percentage is fairly consistent there will be a large degree of randomness within a small sampling of drawings making it impossible to play a consistent pattern. Eventually the best you can do is try to make it a 1 in 4 possibility.

For instance if I convert a set of numbers to an integer and then convert that integer to bits I wind up with 41 bits in order to accommodate all the possible numbers. I can tell you that a majority of the winning numbers consistently have 20 bits set to 1 and 21 set to 0. I can also tell you that if I pick 1 winning set from the previous day with 20 bits set to one that the a winner in the next drawing will have 20 bits different where 10 1's got flipped to 0 and 10 0's got flipped to 1.

If I take it a step further and ignore the first bit, divide the remaining bits by 4 so that there are 10 4 bit sections that 100% of the time in the next 7 drawings there will be 2 bits from each section that are changed. This works because for each section there are 6 possibilities resulting in over 60 million possible combinations.

I was quite hooked on that method for a while because I liked the idea of having to make a 1 in 6 choice 10 times as opposed to guessing at numbers.

The are all kinds of different ways to work this, but in the end it is going to come down to developing a system that allows you to get a good feeling for how the drawings are flowing so that you can make educated guesses within your strategy because it is impossible to predict exactly what numbers are going to show.
Datapile

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Apr 23, 2017, 8:33 pm

(After quick look at NY lottery... You're talking Pick 10, yes?

I've been leaning toward hexadecimal for a while- so that I'm only picking 20 from 0-F... Then trying to make rules as to frequency and behavior.

And I made a numbering algorithm, so that I can put in a full 20 digit sequence, and get its location ID or vice versa. (1,2...19,20 would be location ID 1. 61,62,...79,80 would be last possible combination 3535316142212174319.)

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas
Novan60

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Apr 23, 2017, 9:12 pm

Quote: Originally posted by Datapile on Apr 23, 2017
(After quick look at NY lottery... You're talking Pick 10, yes?

I've been leaning toward hexadecimal for a while- so that I'm only picking 20 from 0-F... Then trying to make rules as to frequency and behavior.

And I made a numbering algorithm, so that I can put in a full 20 digit sequence, and get its location ID or vice versa. (1,2...19,20 would be location ID 1. 61,62,...79,80 would be last possible combination 3535316142212174319.)

It is hard enough trying to get 10 out of 20 much less the full 20. At this point while I'm always grateful when I hit an 8 or 7 out of 10 I'm more pissed off that I am having so much trouble getting those last 2-3 digits, much less the additional 10.

That said for a while I looked at targeting all 20, but abandoned that path pretty quickly as the odds were ridiculous. what makes Keno worth playing is not having to match the full 20.
Datapile

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Apr 24, 2017, 6:49 pm

Quote: Originally posted by Novan60 on Apr 23, 2017
It is hard enough trying to get 10 out of 20 much less the full 20. At this point while I'm always grateful when I hit an 8 or 7 out of 10 I'm more pissed off that I am having so much trouble getting those last 2-3 digits, much less the additional 10.

That said for a while I looked at targeting all 20, but abandoned that path pretty quickly as the odds were ridiculous. what makes Keno worth playing is not having to match the full 20.

IMHO, the evens are worse!

Novan, have you seen the ellipse that forms inside the diamond when you calculate the chance for each number, in each possible slot? (The 20/80 here is a bar game that runs every 4 minutes, for 340 drawings per day, so I have 1.3 million draws in the db...)

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas
Novan60

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Apr 24, 2017, 7:19 pm

Quote: Originally posted by Datapile on Apr 24, 2017
IMHO, the evens are worse!

Novan, have you seen the ellipse that forms inside the diamond when you calculate the chance for each number, in each possible slot? (The 20/80 here is a bar game that runs every 4 minutes, for 340 drawings per day, so I have 1.3 million draws in the db...)

I have not spent a lot of time trying to convert patterns to visualizations. I don't find them very helpful in this endeavor as all they do is confirm visually what I already know from the math.

In NY that game is the same as Quick Draw. I downloaded a half million results just to have them, but haven't made any use of them given that the 7000 plus Pick 10 drawings that I have are more than sufficient for my purposes.

After all of the research that I have done I have determined that I can use math to limit the number of random choices that I have to make to as few as possible and am then 100% dependent on luck to make it the rest of the way to the finish line.
Datapile

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Apr 24, 2017, 8:17 pm

(I'm looking for something new to show you- I never thought to look at the ratios the way you do, and I'm trying to find something that piques your interest...)

You can calculate the chance of every number in every slot in Excel with a formula- I suspect you've done this already. The data shows that for each slot, there is 1 number with the highest chance of being drawn in that slot. Also, the data shows that there is a direct inverse symmetry- 1 in N1 has the same chance as 80 in N20, 2 in N1 has the same chance as 79 in N20... This plays out with 1 side being the same as the other for every slot into the middle, where N10 from the top down has the same percentages as N11 from the bottom up.

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas

Datapile

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Apr 24, 2017, 8:20 pm

We can list each of these lines, and come up with a column for each slot for descending probability of being drawn. I call these probability lines 'apex lines' as they start with the highest chance, and go down from there...

Apex	N1	N2	N3	N4	N5	N6	N7	N8	N9	N10	N11	N12	N13	N14	N15	N16	N17	N18	N19	N20
Apex1	1	5	9	13	17	22	26	30	34	38	43	47	51	55	59	64	68	72	76	80
Apex2	2	4	8	14	18	21	25	29	35	39	42	46	52	56	60	63	67	73	77	79
Apex3	3	6	10	12	16	23	27	31	33	37	44	48	50	54	58	65	69	71	75	78
Apex4	4	7	11	15	19	20	24	28	36	40	41	45	53	57	61	62	66	70	74	77
Apex5	5	3	7	11	15	24	28	32	32	36	45	49	49	53	57	66	70	74	78	76
Apex6	6	8	12	16	20	19	23	33	37	41	40	44	48	58	62	61	65	69	73	75
Apex7	7	9	6	10	21	25	29	27	31	35	46	50	54	52	56	60	71	75	72	74
Apex8	8	2	13	17	14	18	22	34	38	42	39	43	47	59	63	67	64	68	79	73
Apex9	9	10	14	18	22	26	30	26	30	34	47	51	55	51	55	59	63	67	71	72
Apex10	10	11	5	9	13	17	21	35	39	43	38	42	46	60	64	68	72	76	70	71
Apex11	11	12	15	19	23	27	31	25	29	33	48	52	56	50	54	58	62	66	69	70
Apex12	12	13	16	20	12	16	32	36	40	44	37	41	45	49	65	69	61	65	68	69
Apex13	13	14	17	8	24	28	20	24	28	32	49	53	57	61	53	57	73	64	67	68
Apex14	14	15	4	21	25	29	33	37	41	45	36	40	44	48	52	56	60	77	66	67
Apex15	15	16	18	22	11	15	19	23	27	31	50	54	58	62	66	70	59	63	65	66
Apex16	16	17	19	7	26	30	34	38	42	46	35	39	43	47	51	55	74	62	64	65
Apex17	17	18	20	23	27	14	18	22	26	30	51	55	59	63	67	54	58	61	63	64
Apex18	18	19	21	24	10	31	35	39	43	47	34	38	42	46	50	71	57	60	62	63
Apex19	19	20	3	6	28	32	36	21	25	29	52	56	60	45	49	53	75	78	61	62
Apex20	20	21	22	25	29	13	17	40	44	48	33	37	41	64	68	52	56	59	60	61
Apex21	21	22	23	26	9	33	37	41	45	49	32	36	40	44	48	72	55	58	59	60
Apex22	22	23	24	27	30	12	16	20	24	28	53	57	61	65	69	51	54	57	58	59
Apex23	23	24	25	5	31	34	38	42	46	50	31	35	39	43	47	50	76	56	57	58
Apex24	24	25	26	28	8	35	15	19	23	27	54	58	62	66	46	73	53	55	56	57
Apex25	25	26	27	29	32	11	39	43	47	51	30	34	38	42	70	49	52	54	55	56
Apex26	26	27	28	30	33	36	40	18	22	26	55	59	63	41	45	48	51	53	54	55
Apex27	27	28	29	31	7	37	14	44	48	52	29	33	37	67	44	74	50	52	53	54
Apex28	28	29	30	4	34	10	41	45	21	25	56	60	36	40	71	47	77	51	52	53
Apex29	29	30	31	32	35	38	42	17	49	53	28	32	64	39	43	46	49	50	51	52
Apex30	30	31	32	33	36	39	13	46	20	24	57	61	35	68	42	45	48	49	50	51
Apex31	31	32	33	34	6	9	43	16	50	54	27	31	65	38	72	75	47	48	49	50
Apex32	32	33	34	35	37	40	12	47	51	23	58	30	34	69	41	44	46	47	48	49
Apex33	33	34	35	36	38	41	44	48	19	55	26	62	33	37	40	43	45	46	47	48
Apex34	34	35	36	37	39	42	45	15	52	22	59	29	66	36	39	42	44	45	46	47
Apex35	35	36	37	38	40	8	11	49	18	56	25	63	32	70	73	41	43	44	45	46
Apex36	36	37	38	39	41	43	46	14	53	21	60	28	67	35	38	40	42	43	44	45
Apex37	37	38	39	40	5	44	47	50	17	57	24	64	31	34	37	76	41	42	43	44
Apex38	38	39	40	41	42	45	10	51	54	20	61	27	30	71	36	39	40	41	42	43
Apex39	39	40	41	42	43	7	48	13	16	58	23	65	68	33	74	38	39	40	41	42
Apex40	40	41	42	43	44	46	49	52	55	19	62	26	29	32	35	37	38	39	40	41
Apex41	41	42	43	44	45	47	50	12	56	59	22	25	69	31	34	36	37	38	39	40
Apex42	42	43	44	45	46	48	9	53	15	18	63	66	28	72	33	35	36	37	38	39
Apex43	43	44	45	46	47	6	51	54	57	60	21	24	27	30	75	34	35	36	37	38
Apex44	44	45	46	47	48	49	52	11	14	17	64	67	70	29	32	33	34	35	36	37
Apex45	45	46	47	48	49	50	8	55	58	61	20	23	26	73	31	32	33	34	35	36
Apex46	46	47	48	49	50	51	53	56	59	62	19	22	25	28	30	31	32	33	34	35
Apex47	47	48	49	50	51	52	54	10	13	16	65	68	71	27	29	30	31	32	33	34
Apex48	48	49	50	51	52	53	55	57	60	63	18	21	24	26	28	29	30	31	32	33
Apex49	49	50	51	52	53	54	7	58	12	15	66	69	23	74	27	28	29	30	31	32
Apex50	50	51	52	53	54	55	56	9	61	64	17	20	72	25	26	27	28	29	30	31
Apex51	51	52	53	54	55	56	57	59	62	14	67	19	22	24	25	26	27	28	29	30
Apex52	52	53	54	55	56	57	58	60	11	65	16	70	21	23	24	25	26	27	28	29
Apex53	53	54	55	56	57	58	59	61	63	13	68	18	20	22	23	24	25	26	27	28
Apex54	54	55	56	57	58	59	60	8	10	66	15	71	73	21	22	23	24	25	26	27
Apex55	55	56	57	58	59	60	61	62	64	12	69	17	19	20	21	22	23	24	25	26
Apex56	56	57	58	59	60	61	62	63	65	67	14	16	18	19	20	21	22	23	24	25
Apex57	57	58	59	60	61	62	63	64	9	11	70	72	17	18	19	20	21	22	23	24
Apex58	58	59	60	61	62	63	64	65	66	68	13	15	16	17	18	19	20	21	22	23
Apex59	59	60	61	62	63	64	65	66	67	69	12	14	15	16	17	18	19	20	21	22
Apex60	60	61	62	63	64	65	66	67	68	10	71	13	14	15	16	17	18	19	20	21
Apex61	61	62	63	64	65	66	67	68	69	70	11	12	13	14	15	16	17	18	19	20

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas

Datapile

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Apr 24, 2017, 8:42 pm

If you take the first 20 Apex lines, and run them against historical data...(Remember: A number has to be in the exact slot for it to count as a hit its apex...)

Hit	Apex1	Apex2	Apex3	Apex4	Apex5	Apex6	Apex7	Apex8	Apex9	Apex10	Apex11	Apex12	Apex13	Apex14	Apex15	Apex16	Apex17	Apex18	Apex19	Apex20
0	0.170	0.024
1	0.332	0.145	0.027	0.008	0.005	0.003
2	0.265	0.217	0.068	0.036	0.022	0.012	0.007	0.005	0.002	0.001	0.001	0.001
3	0.144	0.215	0.102	0.067	0.043	0.026	0.019	0.014	0.008	0.006	0.004	0.003	0.001	0.001	0.001
4	0.061	0.171	0.126	0.092	0.064	0.046	0.032	0.024	0.016	0.012	0.009	0.006	0.005	0.003	0.002	0.001	0.001
5	0.021	0.113	0.136	0.110	0.081	0.063	0.046	0.034	0.025	0.020	0.014	0.011	0.009	0.006	0.004	0.003	0.002	0.001	0.001	0.001
6	0.006	0.064	0.133	0.118	0.095	0.075	0.059	0.045	0.035	0.028	0.021	0.017	0.014	0.010	0.008	0.006	0.004	0.003	0.002	0.002
7	0.001	0.031	0.119	0.118	0.103	0.085	0.071	0.056	0.046	0.035	0.029	0.023	0.019	0.014	0.012	0.009	0.007	0.006	0.004	0.003
8		0.013	0.097	0.111	0.105	0.093	0.081	0.065	0.057	0.045	0.037	0.029	0.025	0.020	0.016	0.012	0.010	0.008	0.006	0.005
9		0.005	0.074	0.098	0.103	0.097	0.087	0.074	0.065	0.053	0.045	0.037	0.031	0.025	0.022	0.017	0.014	0.011	0.009	0.008
10		0.002	0.051	0.080	0.095	0.097	0.092	0.082	0.073	0.062	0.053	0.045	0.038	0.032	0.027	0.023	0.019	0.015	0.013	0.011
11			0.033	0.061	0.083	0.092	0.092	0.086	0.080	0.070	0.061	0.054	0.045	0.040	0.034	0.029	0.024	0.021	0.017	0.014
12			0.019	0.044	0.068	0.083	0.090	0.088	0.084	0.077	0.069	0.062	0.053	0.048	0.040	0.036	0.030	0.026	0.022	0.018
13			0.009	0.028	0.052	0.071	0.083	0.087	0.087	0.082	0.076	0.070	0.061	0.056	0.048	0.044	0.037	0.033	0.028	0.023
14			0.004	0.016	0.036	0.057	0.073	0.083	0.088	0.086	0.083	0.077	0.070	0.065	0.057	0.052	0.045	0.040	0.035	0.029
15			0.002	0.008	0.023	0.042	0.060	0.075	0.084	0.087	0.088	0.084	0.079	0.074	0.067	0.062	0.054	0.048	0.043	0.038
16			0.001	0.004	0.013	0.029	0.047	0.065	0.077	0.086	0.090	0.091	0.088	0.084	0.078	0.073	0.066	0.060	0.054	0.048
17				0.001	0.006	0.017	0.032	0.051	0.067	0.081	0.090	0.095	0.096	0.095	0.091	0.087	0.081	0.075	0.068	0.062
18					0.002	0.008	0.019	0.036	0.053	0.072	0.087	0.098	0.105	0.108	0.108	0.106	0.101	0.097	0.089	0.082
19					0.001	0.003	0.009	0.021	0.036	0.057	0.078	0.097	0.115	0.126	0.133	0.137	0.136	0.134	0.128	0.121
20						0.001	0.003	0.008	0.018	0.038	0.064	0.100	0.146	0.191	0.251	0.303	0.366	0.419	0.480	0.535

The chance for how many (cumulative) numbers will be in an apex line, or all the ones before it.

This means that there are 61 possible numbers that can be drawn in any slot, however you will only need to look at the top 20 apex lines 53% of the time.

(If you are feeling lucky, all 20 numbers are contained (in exactly the right column) in the top 10 rows 3.8% of the time...)

Edmond: There are 72,519 stones in my walls. I've counted them many times.

Abbe Faria: But have you named them yet?

The Count of Monte Cristo by Alexandre Dumas

Novan60

United States
Member #180,181
February 23, 2017
125 Posts
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Apr 24, 2017, 10:19 pm

Quote: Originally posted by Datapile on Apr 24, 2017

If you take the first 20 Apex lines, and run them against historical data...(Remember: A number has to be in the exact slot for it to count as a hit its apex...)

Hit	Apex1	Apex2	Apex3	Apex4	Apex5	Apex6	Apex7	Apex8	Apex9	Apex10	Apex11	Apex12	Apex13	Apex14	Apex15	Apex16	Apex17	Apex18	Apex19	Apex20
0	0.170	0.024
1	0.332	0.145	0.027	0.008	0.005	0.003
2	0.265	0.217	0.068	0.036	0.022	0.012	0.007	0.005	0.002	0.001	0.001	0.001
3	0.144	0.215	0.102	0.067	0.043	0.026	0.019	0.014	0.008	0.006	0.004	0.003	0.001	0.001	0.001
4	0.061	0.171	0.126	0.092	0.064	0.046	0.032	0.024	0.016	0.012	0.009	0.006	0.005	0.003	0.002	0.001	0.001
5	0.021	0.113	0.136	0.110	0.081	0.063	0.046	0.034	0.025	0.020	0.014	0.011	0.009	0.006	0.004	0.003	0.002	0.001	0.001	0.001
6	0.006	0.064	0.133	0.118	0.095	0.075	0.059	0.045	0.035	0.028	0.021	0.017	0.014	0.010	0.008	0.006	0.004	0.003	0.002	0.002
7	0.001	0.031	0.119	0.118	0.103	0.085	0.071	0.056	0.046	0.035	0.029	0.023	0.019	0.014	0.012	0.009	0.007	0.006	0.004	0.003
8		0.013	0.097	0.111	0.105	0.093	0.081	0.065	0.057	0.045	0.037	0.029	0.025	0.020	0.016	0.012	0.010	0.008	0.006	0.005
9		0.005	0.074	0.098	0.103	0.097	0.087	0.074	0.065	0.053	0.045	0.037	0.031	0.025	0.022	0.017	0.014	0.011	0.009	0.008
10		0.002	0.051	0.080	0.095	0.097	0.092	0.082	0.073	0.062	0.053	0.045	0.038	0.032	0.027	0.023	0.019	0.015	0.013	0.011
11			0.033	0.061	0.083	0.092	0.092	0.086	0.080	0.070	0.061	0.054	0.045	0.040	0.034	0.029	0.024	0.021	0.017	0.014
12			0.019	0.044	0.068	0.083	0.090	0.088	0.084	0.077	0.069	0.062	0.053	0.048	0.040	0.036	0.030	0.026	0.022	0.018
13			0.009	0.028	0.052	0.071	0.083	0.087	0.087	0.082	0.076	0.070	0.061	0.056	0.048	0.044	0.037	0.033	0.028	0.023
14			0.004	0.016	0.036	0.057	0.073	0.083	0.088	0.086	0.083	0.077	0.070	0.065	0.057	0.052	0.045	0.040	0.035	0.029
15			0.002	0.008	0.023	0.042	0.060	0.075	0.084	0.087	0.088	0.084	0.079	0.074	0.067	0.062	0.054	0.048	0.043	0.038
16			0.001	0.004	0.013	0.029	0.047	0.065	0.077	0.086	0.090	0.091	0.088	0.084	0.078	0.073	0.066	0.060	0.054	0.048
17				0.001	0.006	0.017	0.032	0.051	0.067	0.081	0.090	0.095	0.096	0.095	0.091	0.087	0.081	0.075	0.068	0.062
18					0.002	0.008	0.019	0.036	0.053	0.072	0.087	0.098	0.105	0.108	0.108	0.106	0.101	0.097	0.089	0.082
19					0.001	0.003	0.009	0.021	0.036	0.057	0.078	0.097	0.115	0.126	0.133	0.137	0.136	0.134	0.128	0.121
20						0.001	0.003	0.008	0.018	0.038	0.064	0.100	0.146	0.191	0.251	0.303	0.366	0.419	0.480	0.535

The chance for how many (cumulative) numbers will be in an apex line, or all the ones before it.

This means that there are 61 possible numbers that can be drawn in any slot, however you will only need to look at the top 20 apex lines 53% of the time.

(If you are feeling lucky, all 20 numbers are contained (in exactly the right column) in the top 10 rows 3.8% of the time...)

You are correct in assuming that I already did something like this. Here is the thread. https://www.lotterypost.com/thread/310864

You can actually get it down to a very reliable 1 in the first 8 if you play the next seven drawings and even as low as 1 in 4 if you dynamically reorder the numbers based on certain logic derived from past performance.

I frequently refer to playing the next X drawings because I think it is impossible to predict what the numbers are going to be for a specific drawing. By factoring in multiple drawings it opens the possibility of patterns to play. Although the percentages do work out to be the same when divided by the individual drawings. if It also means I don't have to worry about running to the store each day to play as this is not a subscription game. I typically do increments of 7 because that is how many drawing NY allows for Pick 10 with 1 game card.

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