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one fine prediction!!

Topic closed. 10 replies. Last post 12 years ago by LANTERN.

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langley b.c.
Canada
Member #3313
January 10, 2004
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Posted: May 30, 2004, 10:29 pm - IP Logged

i lately have been fooling around with the gail howard software and have come across a chart that is hitting like pure dynamite gails last digits due  what i have done is back tested the chart with the last 20 drawings for the canada bc/49 these were my findings

6 numbers 1 time

5 numbers 3 times

4 numbers 4 times

3 numbers 6 times

i chose the least 5 occuring digits in the last 5 drawings  this translates into 25 numbers i would have to play to acheive the results above  not too bad 14 out of 20 games i would have been in the money!!!! i"am sure we could filter this group down to 18 numbers and still have yielded just about as much prizes anyway here is my prediction for the bc/49 using this theory  1-2-6-9-10-11-12-16-20-22-29-30-31-36-39-40-41-42

    paul762's avatar - lion

    United Kingdom
    Member #3002
    December 11, 2003
    477 Posts
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    Posted: May 31, 2004, 5:34 am - IP Logged

    lottosyncman, ive got this software too, is it chart (g) last digit analysis? if so how did you get your numbers? mines just got stats.?

    thanks.

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      New Member

      United States
      Member #2869
      November 25, 2003
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      Posted: May 31, 2004, 9:27 am - IP Logged

      > i chose the least 5 occuring digits in the last 5 drawings  this translates

      > into 25 numbers i would have to play



      I don't follow. What do you m ean "least 5 occuring digits in the last 5 drawings?"



      ->Later.....Spice

        LANTERN's avatar - kilroy 28_173_reasonably_small.jpg
        Tx
        United States
        Member #4570
        May 4, 2004
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        Posted: May 31, 2004, 9:39 am - IP Logged

        lottosyncman

        If those numbers were for the may 29 draw, then you got 3 numbers right, if they are for the next drawing then I reduced your numbers to these:

        1-2-6-9-16-22-30-36-39-40



        Now you only have 10 numbers to play.

        The trade off might be one winning number.

        But a lot cheaper to play.

          LANTERN's avatar - kilroy 28_173_reasonably_small.jpg
          Tx
          United States
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          May 4, 2004
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          Posted: May 31, 2004, 9:44 am - IP Logged

          lottosyncman

          Next time post all the 25 numbers and then also the reduced 18 numbers and if I see your post in time, then I will see if i can post a reduced numbers list of my own, I

          want to see how I would do at reducing the list of your numbers, but for any of this to work at all the 25 numbers have to have some winning numbers in them, or none of this

          will work at all.

            LANTERN's avatar - kilroy 28_173_reasonably_small.jpg
            Tx
            United States
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            May 4, 2004
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            Posted: May 31, 2004, 9:54 am - IP Logged

            I made I more number reduction, so now is onlu 9 numbers.

            1-2-6-16-22-30-36-39-40

              lottoarchitect's avatar - waveform

              Greece
              Member #2815
              November 18, 2003
              502 Posts
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              Posted: May 31, 2004, 3:20 pm - IP Logged
              Quote: Originally posted by lottosyncman on May 30, 2004



              i lately have been fooling around with the gail howard software and have come across a chart that is hitting like pure dynamite gails last digits due  what i have done is back tested the chart with the last 20 drawings for the canada bc/49 these were my findings

              6 numbers 1 time

              5 numbers 3 times

              4 numbers 4 times

              3 numbers 6 times

              i chose the least 5 occuring digits in the last 5 drawings  this translates into 25 numbers i would have to play to acheive the results above  not too bad 14 out of 20 games i would have been in the money!!!! i"am sure we could filter this group down to 18 numbers and still have yielded just about as much prizes anyway here is my prediction for the bc/49 using this theory  1-2-6-9-10-11-12-16-20-22-29-30-31-36-39-40-41-42





              This is totally subjective as it solely depends on the trends of the lottery. If you apply this in another area of the history draws, you possibly get other results. Try to expand the test range eg test 100 draws and see the rates you get. I run my own system for a game 6/49 and I pick 25 numbers in the last 20 draws. My results using my program:

              match 3: 5

              match 4: 5

              match 5: 5

              match 6: 1

              This is 16 out of 20 times hit. The above are based only on the Hot/Cold/Due system. The problem now is how to even reduce the total numbers or how to remove tickets generated by wheeling these 25 numbers. What do you mean by filtering numbers out? Based on which process?

              If I run it on another area, I might get different results as well.

              If you have something to do, at least do it well...

                LANTERN's avatar - kilroy 28_173_reasonably_small.jpg
                Tx
                United States
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                Posted: June 1, 2004, 2:59 pm - IP Logged

                Filtering numbers out based on past draws and statistics.

                Always past draws and always statistics.

                  Johannesburg
                  South Africa
                  Member #4640
                  May 12, 2004
                  178 Posts
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                  Posted: June 2, 2004, 8:58 am - IP Logged
                  Quote: Originally posted by lottosyncman on May 30, 2004



                  i lately have been fooling around with the gail howard software and have come across a chart that is hitting like pure dynamite gails last digits due  what i have done is back tested the chart with the last 20 drawings for the canada bc/49 these were my findings

                  6 numbers 1 time

                  5 numbers 3 times

                  4 numbers 4 times

                  3 numbers 6 times

                  i chose the least 5 occuring digits in the last 5 drawings  this translates into 25 numbers i would have to play to acheive the results above  not too bad 14 out of 20 games i would have been in the money!!!! i"am sure we could filter this group down to 18 numbers and still have yielded just about as much prizes anyway here is my prediction for the bc/49 using this theory  1-2-6-9-10-11-12-16-20-22-29-30-31-36-39-40-41-42




                  within 18 numbers covering 5-6 winning numbers isn't difficult for me.Its just how to wheel 18 numbers into a winner within 10 draws that gives me a headache.Hope todd could allow some post 20 picks.10 more picks is enough.
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                    Canada
                    Member #2612
                    October 25, 2003
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                    Posted: June 2, 2004, 12:33 pm - IP Logged

                    HI Lottosyncman, just curious, does that mean we would play those numbers that have been out, in just the next draw only or for a few draws after?

                      LANTERN's avatar - kilroy 28_173_reasonably_small.jpg
                      Tx
                      United States
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                      May 4, 2004
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                      Posted: June 3, 2004, 5:15 am - IP Logged



                      June 2 2004 winning numbers:



                      5, 24, 28, 31, 40, 41, 07 BB

                      Well you had 3 numbers right and my reducing method did not work at all.

                      But 3 winning numbers on 18 is not very good, but not very

                      bad either not bad at all, you are doing something right.

                      Get a way to reduce the numbers to 10 without cutting off the 3 winning numbers and you might not need LottoSync anymore.

                      You are not "UnderDog" or whatever your name was, no more for sure, now you can go back to naming yourself "LuckyHorse" yes sir, that is a much better name.

                      Bye.