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How lottery legend Joan Ginther used odds, Uncle Sam to win millionsNews Story
By Peter Mucha, Philly.com Second of three parts See Part 1 Joan Ginther wasn't necessarily lottery loco. Maybe it wasn't a case of dumb luck, but smart luck. She may have purchased at least 80,000 pricey tickets worth $2 million or more, according to expert analysis of 28 instant prizes she won, including three totalling $15 million. If she also was the source of two dozen lesser wins by her friend Anna Morales, Ginther might have spurred the purchase of as many as 100,000 ticket
Jul 2, 2014, 10:07 am - Todd - Lottery News

What constitutes a good reduction filter?Reply
Hi, Lakerben I've been around the lottery scene for a long time. My question is what do you base your assumptions on : by experience?? And what system do you use ? I've been testing and analyzing systems for over 25 years, and I have learned many different methods from Wheels,matrix of all sizes, grids you name it. I base my own designed system on historical data. The core of it is the amount of occurrences that happens for each lottery number over different windows in time. The
Jul 15, 2012, 2:55 am - JKING - Lottery Systems Forum

The End GameReply
Hi, The end game is more or less outlined above. Start with the least amount of risk and whittle the combinations down by taking ever increasing risk of eliminating the winning combination. The problem with filters is that you have to be very selective in the boundary conditions for each filter. If you run 20+ filters like I do, invariably lower values in one, if not in several filters, will occur. So you start will 100% filters with elimination of only the most skewed values .. BALLNUM=3
Jun 14, 2011, 9:01 pm - JKING - Lottery Systems Forum

Start off with only 527 numbers ...not 1000 each day.Reply
Hey WinD, I like you elimination method. Reduce 1000 down to 527. I'm experimenting this idea up here in PA evening. The filters I will be using is the following: 1. Reduce 1000 down to 527 2. Reduce the 527 down to 97 a. eliminate all sums that are less than 6 and greater than 23 b. eliminate all combos that do NOT have a pair (no-match boxed) in all 3 positions (Front, Back, and Side) that have 29 skips or less. So I'm using any Boxed Pair that has a skip of 30 or mo
Jul 10, 2008, 5:17 pm - winsumloosesum - Lottery Systems Forum

No delusion-100% winning methodReply
Hi JS1237, After thoroughly viewing this you should be able to do Pick 4 Permuation as well. If you do the Pick 3 manually, you can finish it in 20 minutes. The Pick 4 is more challenging. The following are the instructions and workout for the Pik 3 PLEASE READ THIS THOROUGHLY TO UNDERSTAND DSUM. ITS QUITE SIMPLE. THE DSUM FORMULA WILL BE AT THE END OF THIS POST. I APOLOGIZE BEFORE HAND IF THE CODE DOESN'T TRANSFER PROPERLY AND COME OUT STRAIGHT. THE DSUM PICK 3 IS JUST LIKE DSUM
May 25, 2006, 12:58 pm - Kola - Lottery Systems Forum

No delusion-100% winning methodReply
Hi JS1237, After thoroughly viewing this you should be able to do Pick 4 Permuation as well. If you do the Pick 3 manually, you can finish it in 20 minutes. The Pick 4 is more challenging. The following are the instructions and workout for the Pik 3 PLEASE READ THIS THOROUGHLY TO UNDERSTAND DSUM. ITS QUITE SIMPLE. THE DSUM FORMULA WILL BE AT THE END OF THIS POST. I APOLOGIZE BEFORE HAND IF THE CODE DOESN'T TRANSFER PROPERLY AND COME OUT STRAIGHT. THE DSUM PICK 3 IS JUST LIKE DSUM
May 25, 2006, 12:54 pm - Kola - Lottery Systems Forum

Dsum Method For Pick For
PLEASE READ THIS THOROUGHLY TO UNDERSTAND DSUM. ITS QUITE SIMPLE. THE DSUM FORMULA WILL BE AT THE END OF THIS POST OR IN THE IMMEDIATE NEXT POST. I APOLOGIZE BEFORE HAND IF THE CODE DOESN'T TRANSFER PROPERLY AND COME OUT STRIGHT. THE DSUM PICK 4 IS JUST LIKE DSUM FOR THE PICK 3 THE WINNING DRAW WILL ALWAYS BE FOUND IN THE RESULTS. THE TRICK IS TO NARROW DOWN THE RESULTS TO EXTRACT THE WINNING NUMBER. DSUM IS ADAPTABLE TO WORK WITH ANY TECHNIQUE ONE LIKE TO USE TO GET POSSIBLE NUM
May 24, 2006, 11:01 pm - Kola - Lottery Systems Forum