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# johnph77...where did your learn math ?

Topic closed. 34 replies. Last post 11 years ago by johnph77.

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CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: March 25, 2006, 6:23 am - IP Logged

Guess What! -

I've spent a good part of my free time the last two days creating a text file explaining how every part of every formula inside the lottery tables on my website came to be, why it is there and what it does. But, from your last few posts, I've come to believe that, for whatever reason you've conceived, your only purpose in starting this thread was an attempt to vilify work that is presently beyond your understanding and comprehension. Therefore I will not post the contents of that text file. Do your own analysis if you think it necessary - or even possible.

I am not currently employed as a teacher. I see no need to justify my work to someone who is intellectually blind and wouldn't accept any explanation or justification anyway. That page on my site is there for informational purposes only. Use it as you see fit.

John

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

Findlay, Ohio
United States
Member #4855
May 28, 2004
400 Posts
Offline
 Posted: March 25, 2006, 1:55 pm - IP Logged

5 of 5 + MB = 175,711,536
((56!)/((56-5)!))/(5!)×46

4 of 5 + MB = 689,064.85
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
((5!)/((5-4)!))/(4!)×((51!)/((51-1)!))/(1!)

3 of 5 + MB = 13,781.30
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
((5!)/((5-3)!))/(3!)×((51!)/((51-2)!))/(2!)

2 of 5 + MB = 843.75
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
((5!)/((5-2)!))/(2!)×((51!)/((51-3)!))/(3!)

1 of 5 + MB = 140.63
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
((5!)/((5-1)!))/(1!)×((51!)/((51-4)!))/(4!)

0 of 5 + MB = 74.80
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
((5!)/((5-0)!))/(0!)×((51!)/((51-5)!))/(5!)

5 of 5 No MB = 3,904,700.80
((56!)/((56-5)!))/(5!)
--------------------------
45

4 of 5 No MB = 15,312.55
((56!)/((56-5)!))/(5!)×46
---------------------------------------------------
(((5!)/((5-4)!))/(4!)×((51!)/((51-1)!))/(1!))×45

3 of 5 No MB = 306.25
((56!)/((56-5)!))/(5!)×46
-------------------------------------------------------
(((5!)/((5-3)!))/(3!)×((51!)/((51-2)!))/(2!))*45

The world is round?? - No way!....I always thought it was square.  Factorial 0 IS defined as equaling one in combinatorics

~Probability=Odds in Motion~

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: March 25, 2006, 3:45 pm - IP Logged

Thoth -

From my site:

Mega Millions

21 Mar 06.

Participating jurisdictions - California, Georgia, Illinois, Maryland, Massachusetts, Michigan, New Jersey, New York, Ohio, Texas, Virginia, Washington.

Notes: Minimum bet \$1.00. Jackpot shown is minimum, rollover will increase payout and percentages. All California payouts are pari-mutuel, based on state sales.

Formula for Total Possibilities - ((56!/51!)/(5!)x(46)) = 175,711,536.

5/561/46FormulaPossibilitiesOdds - 1::PayoutTotal PayoutPayout Pct
51((5!/0!)/(5!))x((51!/51!)/(0!))1175,711,536.0010,000,000 +10,000,000 +5.69% +
50((5!/0!)/(5!))x((51!/51!)/(0!))x45453,904,700.80250,00011,250,0006.40%
41((5!/1!)/(4!))x((51!/50!)/(1!))255689,064.8510,0002,550,0001.45%
40((5!/1!)/(4!))x((51!/50!)/(1!))x4511,47515,312.551501,721,2500.98%
31((5!/2!)/(3!))x((51!/49!)/(2!))12,75013,781.301501,912,5001.09%
30((5!/2!)/(3!))x((51!/49!)/(2!))x45573,750306.2574,016,2502.29%
21((5!/3!)/(2!))x((51!/48!)/(3!))208,250843.75102,082,5001.19%
20((5!/3!)/(2!))x((51!/48!)/(3!))x459,371,25018.75000.00%
11((5!/4!)/(1!))x((51!/47!)/(4!))1,249,500140.6333,748,5002.13%
10((5!/4!)/(1!))x((51!/47!)/(4!))x4556,227,5003.13000.00%
01((5!/5!)/(0!))x((51!/46!)/(5!))2,349,06074.8024,698,1202.67%
00((5!/5!)/(0!))x((51!/46!)/(5!))x45105,707,7001.66000.00%
Total Winners4,405,08639.89 41,979,120 +23.89% +

ty & gl

j

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

Findlay, Ohio
United States
Member #4855
May 28, 2004
400 Posts
Offline
 Posted: March 25, 2006, 10:48 pm - IP Logged

There are many ways to arrive at the correct totals/odds.  I suppose that if there is a logic to the make up of the formula or if you understand them or explain them, they shouldnt really be considered "incorrect".

There are some who would argue that only one of the equations of 2*4 and ((2*2)+2+1+1), and 2^3 is correct-while others are not, depending on what they are applied to.

~Probability=Odds in Motion~

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: March 26, 2006, 12:47 am - IP Logged

Thoth -

So true. If "2" can be a variable it fouls up the whole works. I have my processing spreadsheet set up where "56" and the payouts are the only variables in a "5+bonus" table. Other tables are set up as needed. Works like a charm.

gl

j

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

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