|Posted: March 2, 2007, 12:57 pm - IP Logged|
Pick 10 in NY pays out $4 if you have no winning numbers.
10/20/80...look at it this way...the odds are much better picking 10 from 60 than 10 from 20 out of 80, right? so I've been trying to "lose" for the past couple of days and yes I do get 9/10 losing numbers or 8 of 10...heh heh,
the odds are better but it isnt easy like I expected.
I'm trying to come up with a formula, but so far nothing.
I've tried pi x number x 2 and that is a bust. Always one number shows up.
This makes me mad because it should be easy!!
the no-wins pay out 13,000 and change every day, so somebody is getting it.
I would like to take out a little of the guesswork, but hitting one number will knock you out!
I WANT TO LOSE!!!!
Any ideas would be greatly appreciated.
I'm a Kenoholic and every Fall I fly to Vegas with a group of golfers. We rent a couple of vans, drive to southern Utah, play golf for 5 days and spend 2 or 3 days in Vegas before we go home. Since most of the guys are not gamblers, they spend alot time with me in the Keno Lounges. They get more play out their $25 than they would playing quarter slot machines and have more time to flirt with the tail waitresses too.
People probably play a 10-spot because they can win $100,000 for a buck and getting back $2 for hitting an occasional 5 numbers keeps them playing a little longer too, but zero hits pays nothing. However some casinos do have a "20-spot special" for $5 where zero hits pays $1000 and the only time you lose is when 3, 4, 5, or 6 of your numbers hit. The Orleans has a $2.50 "Super 20" where only 4, 5, or 6 hits are losers, but zero pays $250.
Though I saw a woman hit zero out of 20 playing 3 rows of 4 on the top and 2 on the bottom that she called "goal post", I've always thought of this game as an inexpensive way of gambling.
I can understand trying to hit "zero numbers" to win $1000 or even $250 but 4 bucks????