Welcome Guest
You last visited January 19, 2017, 9:52 am
All times shown are
Eastern Time (GMT-5:00)

# Number of odd combinations in a 5/39 game

Topic closed. 26 replies. Last post 6 years ago by GiveFive.

 Page 1 of 2
NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: August 23, 2010, 11:57 am - IP Logged

There are a total of 575,757 combinations of 5 numbers in a 5/39 game.

Since there are 19 even numbers in the set of 39 numbers, and 20 odd numbers, it seems to me that there are a slightly larger number of combinations with a 3 odd 2 even split, than a 3 even 2 odd split.

Does any one know how to calculate the number of 3 odd 2 even combinations? If so, how many are there?  Thanks in advance.

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: August 23, 2010, 7:34 pm - IP Logged

You are correct.

The number of combinations in 3/20 can be calculated with the formula (20x19x18)/1x2x3) = 1,140.

The number of combinations in 2/19 can be calculated with the formula (19x18)/(1x2) = 171.

Multiplying these two results will give you the total number of 3 odd/2 even in a 5/39 game - 194,940.

Conversely, the number of combinations in 3/19 can be calculated with the formula (19x18x17)/(1x2x3) = 969

The number of combinations in 2/20 can be calculated with the formula (20x19)/(1/2) = 190.

Multiplying these two results will give you the number of 2 odd/3 even in a 5/39 game - 184,110.

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: August 24, 2010, 8:07 am - IP Logged

You are correct.

The number of combinations in 3/20 can be calculated with the formula (20x19x18)/1x2x3) = 1,140.

The number of combinations in 2/19 can be calculated with the formula (19x18)/(1x2) = 171.

Multiplying these two results will give you the total number of 3 odd/2 even in a 5/39 game - 194,940.

Conversely, the number of combinations in 3/19 can be calculated with the formula (19x18x17)/(1x2x3) = 969

The number of combinations in 2/20 can be calculated with the formula (20x19)/(1/2) = 190.

Multiplying these two results will give you the number of 2 odd/3 even in a 5/39 game - 184,110.

Thanks so much!

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

Zeta Reticuli Star System
United States
Member #30470
January 17, 2006
10390 Posts
Offline
 Posted: August 26, 2010, 2:37 am - IP Logged

GiveFive

"Perimeter" numbers ( top sand bottom row, left and right outside columns) work out the same way, 20 and 19, but it just doesn't seem to matter as far as predictability goes. Not drawing by drawing. If you were to play thousands of drawings, sure, it would prove itself out, but day by day, goos luck.

Those who run the lotteries love it when players look for consistency in something that's designed not to have any.

There is one and only one 'proven' system, and that is to book the action. No matter the game, let the players pick their own losers.

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: September 1, 2010, 10:15 am - IP Logged

You are correct.

The number of combinations in 3/20 can be calculated with the formula (20x19x18)/1x2x3) = 1,140.

The number of combinations in 2/19 can be calculated with the formula (19x18)/(1x2) = 171.

Multiplying these two results will give you the total number of 3 odd/2 even in a 5/39 game - 194,940.

Conversely, the number of combinations in 3/19 can be calculated with the formula (19x18x17)/(1x2x3) = 969

The number of combinations in 2/20 can be calculated with the formula (20x19)/(1/2) = 190.

Multiplying these two results will give you the number of 2 odd/3 even in a 5/39 game - 184,110.

If I want to calculate the number of combinations in a "group" of numbers in a 5/39 game, how would I do that?  For instance, if I take the entire set of 39 numbers (1 - 39) and break it into 3 ranges of numbers.

(1 - 13, 14 - 26, & 27 - 39)

How many possible combinations of 5 numbers are there in each of those three ranges?   Thanks again!

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: September 1, 2010, 12:07 pm - IP Logged

Each group you cite has 13 numbers. The formula for 5-number groupings from 13 possibilities would be: (13x12x11x10x9x8)/(1x2x3x4x5) - 1,287.

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: September 1, 2010, 12:33 pm - IP Logged

Each group you cite has 13 numbers. The formula for 5-number groupings from 13 possibilities would be: (13x12x11x10x9x8)/(1x2x3x4x5) - 1,287.

Once again, thank you very much!

I'm curious as to why you stopped multiplying after using 8 in thr front half of the equation.  Since there are 5 numbers picked, why wouldnt you stop after using 9?  If it's too complicated or complex to easily explain in a post, then that's fine....  I'm simply curious and I dont have a burning need to know!

BTW, prior to posting here, I Googled "calculating lottery odds", and I got quite a few hits.  Some sites even have built-in calculators that will do the math for you, but I didnt see exactly what I was looking for.

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: September 1, 2010, 4:23 pm - IP Logged

Because I screwed up. When entering the formula, "8" shouldn't be included - there are only five numbers in the desired combination.

The correct formula (and the one I used to obtain the actual number of combinations) is: (13x12x11x10x9)/(1x2x3x4x5) - 1,287

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: September 1, 2010, 5:29 pm - IP Logged

Because I screwed up. When entering the formula, "8" shouldn't be included - there are only five numbers in the desired combination.

The correct formula (and the one I used to obtain the actual number of combinations) is: (13x12x11x10x9)/(1x2x3x4x5) - 1,287

After I submitted my post, I used a calculator and did the math w/o using the 8, and got a result of 1,287!  Had I done that first, then I wouldnt have needed to bother you!  Sorry!

E-mailed you a link to the website.... Thanks!

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: September 1, 2010, 7:37 pm - IP Logged

Thanks for pointing out my error and giving me the chance to correct it.

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

The Ville, FL
United States
Member #95879
August 19, 2010
1708 Posts
Offline
 Posted: September 3, 2010, 10:32 am - IP Logged

Each group you cite has 13 numbers. The formula for 5-number groupings from 13 possibilities would be: (13x12x11x10x9x8)/(1x2x3x4x5) - 1,287.

Another way to calculate the different possiblities in a group of numbers is by using the COMBIN function in excel

For example say you have 15 numbers you play and you want groups of 3. The function would be :

=COMBIN(15,3)

that would give you 455 combinations.

Not sure if that helps or not but its pretty cool

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: September 4, 2010, 7:53 am - IP Logged

Another way to calculate the different possiblities in a group of numbers is by using the COMBIN function in excel

For example say you have 15 numbers you play and you want groups of 3. The function would be :

=COMBIN(15,3)

that would give you 455 combinations.

Not sure if that helps or not but its pretty cool

Thanks for the tip!  I'll give it a try.

And you're right, it is cool!

About playing the lottery --  You will lose more than you win. Until you hit a jackpot.  Then everything changes!

United States
Member #94616
July 24, 2010
4735 Posts
Offline
 Posted: September 5, 2010, 7:36 am - IP Logged

Because I screwed up. When entering the formula, "8" shouldn't be included - there are only five numbers in the desired combination.

The correct formula (and the one I used to obtain the actual number of combinations) is: (13x12x11x10x9)/(1x2x3x4x5) - 1,287

Is there a way to get EXCEL to 'create' the list of 1287?

Pennsylvania
United States
Member #2218
September 1, 2003
5396 Posts
Offline
 Posted: October 2, 2010, 12:22 pm - IP Logged

http://www.box.net/shared/0p4mx5hohn

Open the Excel file and in cell C1 enter either a 1, 2, or 3.

Click an empty cell under cell C1.

Then click the Toolbar.

The 1287 combinations will appear starting in cell M1.

In cell H1 you will see the legend for each Group number.

NY State
United States
Member #92609
June 10, 2010
3817 Posts
Offline
 Posted: October 4, 2010, 9:16 am - IP Logged

http://www.box.net/shared/0p4mx5hohn

Open the Excel file and in cell C1 enter either a 1, 2, or 3.

Click an empty cell under cell C1.

Then click the Toolbar.

The 1287 combinations will appear starting in cell M1.

In cell H1 you will see the legend for each Group number.

Winsum,