Dunwoody Georgia United States Member #747 September 29, 2002 659 Posts Offline

Posted: September 18, 2010, 2:47 pm - IP Logged

Quote: Originally posted by WIN D on September 17, 2010

Try this..... just play any 3 digits that way....... say 1,2,3, ......and play them all of the time. Unless you have a really bad run of really stupid luck the odds are that one of them will show around every 3 draws.

Remember, however, .....stupid stuff happens a lot and in streaks in Pick 3.......but on average you will be OK.

In the next 3 draws one of those should show in first position....... most of the time.

Thats because those 3 starter digits represent one third of the 1000 chart...... and so ........one of the (3) digits should show 1/3rd of the times.

At the end of the year....... on average...... you will have 36 straights starting with digit 1...... 36 with digit 2 ...and the same for digit 3. So, out of the 365 straights during the year....... about 108 straights ......of them will be one of these 3 digits and start of that way.

365/ divided by 108 ...... is 33.7962 ........ or about 1/3 of the time..... or every 3 draws.

Yes just like playing 789 in the last position is the same thing! The Middle digit is the key because it swings up and down so radical? Just my thoughts! Well Mine a a few others.

It's Never Too Late To Be The Person You Could Of Been!

United States Member #75358 June 1, 2009 5345 Posts Offline

Posted: September 18, 2010, 3:02 pm - IP Logged

Quote: Originally posted by danyo1332 on September 18, 2010

So what ya thnk Joker? Tonight eve in FL guna start with a 5 or 0 by lookin at the pattern?

Well, like I wrote in the last page, this has been on a lucky streak, especially with the 3rd consecutive draw right on the mark. If I was playing for real, I'd probbably back off for tonight, but since I'm playing make believe, yeah go ahead....lol

Another note: When there are too many indicators, what I like to do is play only the indicator that is 2 consecutive draws back, so my next bet will be the 3rd consecutive draw, just like the way it's been hitting.

Tuesday September 14, mid - 605.................................eve-374

Wednesday September 15, mid - 449..........................eve-124

Thursday September 16, mid - 690...............................eve-398

Friday September 17, mid - 033......................................eve-157

Saturday September 18, mid - 861.................................eve- ?

In this case, 3 consecutive draws back would be the 0 indicator which yields a 5, so yes you are right. You have to remember that it won't always work like clockwork, meaning hitting on the 3rd consecutive draw all the time. In a perfect world I would be rich rich rich...lol.....I've seen hits the next draw, the second draw, the third, and even fourth and fifth, but within 3 consecutive draws is the norm.

United States Member #75358 June 1, 2009 5345 Posts Offline

Posted: September 18, 2010, 3:09 pm - IP Logged

Quote: Originally posted by danyo1332 on September 18, 2010

so this works for the 1st,2nd,AND 3rd position!?

Ha ha ha...you read my mind....Techinically NO, but I was looking at the numbers the other day and saw that the 3rd position numbers actually predicted the 3rd position numbers in the next few draws, just like the first position of this sytem. The problem I found is that they match up only a few times.

Example: mid: 301

eve: 826

See how the 3 in the first position is correct in predicting the 8?, and the 1 is also correct in predicting the 6? Well, that doesn't happen all the time, but in my back test yesterday, it did happen a couple of times. Most of the time they were scattered, and didn't work together. OH BOY, wouldn't that be awesome? If all 3 matched, but someone would have figured that out a long time ago by just playing morror numbers for all 3.

Also, you will see in your backtest, that when a first position predictis the next first position, the second and third positions have already been predicted a few draws back, maybe 4 or 5 draws.

In hindsight is easy to see where the indicators for all 3 positions were, but in reality you'd have to play EVERY position 3 consecutive, most of the time 4 consecutive draws back. Plus the fact that this less common than the first position only.

United States Member #75358 June 1, 2009 5345 Posts Offline

Posted: September 18, 2010, 3:26 pm - IP Logged

Quote: Originally posted by joker17 on September 18, 2010

Well, like I wrote in the last page, this has been on a lucky streak, especially with the 3rd consecutive draw right on the mark. If I was playing for real, I'd probbably back off for tonight, but since I'm playing make believe, yeah go ahead....lol

Another note: When there are too many indicators, what I like to do is play only the indicator that is 2 consecutive draws back, so my next bet will be the 3rd consecutive draw, just like the way it's been hitting.

Tuesday September 14, mid - 605.................................eve-374

Wednesday September 15, mid - 449..........................eve-124

Thursday September 16, mid - 690...............................eve-398

Friday September 17, mid - 033......................................eve-157

Saturday September 18, mid - 861.................................eve- ?

In this case, 3 consecutive draws back would be the 0 indicator which yields a 5, so yes you are right. You have to remember that it won't always work like clockwork, meaning hitting on the 3rd consecutive draw all the time. In a perfect world I would be rich rich rich...lol.....I've seen hits the next draw, the second draw, the third, and even fourth and fifth, but within 3 consecutive draws is the norm.

Oops, my bad. 2 consecutive draws back would be 157, so the 1 would be the indicator for 3 draws forward. So I'd beusing the 1 which would yield the 6 for tonight. This is conservative playing. Online, I could play for 25 cents per combo, and I' may be bold enough to play the 8 in 861 too.

United States Member #75358 June 1, 2009 5345 Posts Offline

Posted: September 18, 2010, 6:08 pm - IP Logged

Wow....Great news folks. I just found a way to get that elusive back pair to go with our first position indicator. I just did a backtest from August 27th in Florida. If played online using the following methods, one would've made a profit of $4,760 in 22 days, that $216 a day.......If played at the store, one would've made $1,960 in 22 days net, that's almost $90.00 a day.

I was looking at the p-3 bet generator that spits out 4 combos. I can't show you the generator, but if you want, just PM me and I can give you the link. All the generator does is add 666-222-888-444 to a number and spits out 4 combos. It's easy to do on paper, but if you're backtesting, it makes life a little easier.

Here's what I found.

Playing every draw, mid to eve costs anywhere from 10 bucks to 120 bucks depending if the number even has a qualifier. Some days there ar no qulifiers and NO money is spent at all.

I actually did every single draw, one by one and wrote down how much it would cost to play 3 consecutive draws for each draw from August 27th till last night, September 17th.

For example, starting with August 27th, the midday winner was 095. To play 095's generator output(if qualified to do so) would cost 20 dollars each draw for 3 draws equaling 60 bucks. How? well....here it goes....

If i put 095 in the generato.r, it spits out the following sets......651 217 873 439

What I'm looking for is the indicator number for the 0 in 095. o indicates a 5 for the next 3 consecutive draws right? We see a 5 in 651. Are you with me so far? To play the 5 in 651, we must play 510 511 512 513 514 515 516 517 518 519.......560 561 562 563 564 565 566 567 568. We covered the 5 with the other 2 numbers. (6) and (1). We had no winner in the next 3 consecutive draws, so that was 60 dollars spent. That was mid august 27th nid.

On agust 27th eve, the winning number was 908. I did the same process over again. The generator spit out 564 120 786 342...we are looking for the 9 indicator which is a 4. Now there are two 4's in the 4 sets....564 and 342...........................564= 460 461 462 463 464 465 466 467 468 469.....450 451 452 453 454 455 456 457 458 459..............................342=420 421 422 423 424 425 426 427 428 429.....430 431 432 433 434 435 436 437 438 439

That would cost 20 bucks each combo, for a total of 120 bucks for 3 draws. But not to worry because we won on the very next draw on August 28th mid with 431. So we only spent 40 bucks. It changes with each draw.

Here is the breakdown of the numbers and what they cost for the 22 days or 44 draws(2 draws per day):

120 bucks spent= 3 times

80 bucks spent= once

60 bucks spent= 16 times

40 bucks spent= once

30 bucks spent= once

20 bucks spent= 3 times

10 bucks spent= once

0 spent= 14 times.

So you see that every draw's costs varies, and 14 times there were no indicator output numbers that the generator spit out, so we didn't even play on those days that 0 was spent. We simply skipped that draw.

Here's one example of the 14 times when the generator did not spit out any indictor numbers:

August 30th mid-446.....generstor output.....002 668 224 880

The 4 in 446 indicates we should look out for a 9 in the first position within 3 consecutive draws, but there is not even one 9 in the four sets, so there is nothing to play. This is a good thing because it cuts down on the cost. We didn't have to play in 14 seperate draws.

In the end of the test, I tallied the cost which was $1,540 dollars, and there were 7 winners. So the online payout was $6,300. (7X900=6300)

6300 minus 1540 = $4,760 net profit in 22 days.

Or.....if played at the store, it would have been $3,500 minus 1,540 = $1,960 net profit.

We plug in 033 in the generator and it spits out the following 4 sets.......699 255 811 477

The "0" in 033 indicates we should be looking for a "5" in the first position, but only for tonight's drawing because that would end the 3 day consecutive plays for 033.

The only "5" is in 255......The sets to play are..........520 521 522 523 524 525 526 527 528 529..........550 551 552 553 554 555 556 557 558 559

Now we plug our final number 861 into the generator.........427 083 649 205

The "8" in 861 indicates we should look for a "3" in the first position within 3 consecutive draws.

There is only one "3" in the 4 sets above. That's 083. Now we again cover the "3" with the other 2 numbers........380 381 382 383 384 385 386 387 388 389..........................300 301 302 303 304 305 306 307 308 309