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# I can predict one number for sure in a random game

Topic closed. 88 replies. Last post 4 years ago by theo1946.

 Page 6 of 6

United States
Member #134627
November 2, 2012
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 Posted: January 14, 2013, 4:46 pm - IP Logged

Say, you have it nailed down, to guess 1 number among 5. The similar results can be obtained by other quite simple methods as well. One can do it by , say, 5, 6 different ways, and then combine the groups he came up with. Several numbers among them will be repeated, so remove the doubles, etc. What is left is group of numbers that has all 5 numbers in it. Play this group.

bgonÃ§alves
Brasil
Member #92564
June 9, 2010
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 Posted: January 15, 2013, 12:35 pm - IP Logged
Hello, have you tried this from a 6/49 lottery, catch up to 64 past sweepstakes
And do and straight, join in straight 4 sweepstakes, forming a line of 24 numbers
This is how
Join or combine in sequel
.2 .3 .4 groups1 = we will have 24 numbers
5.6 .7, 8........... until the Group = 61, 62, 63.64
Total 16 rows, or is simply that a Union in sequence of 4 sweepstakes or groups in
Or remaining 25 have the 6 numbers, we have to use the last 64 results, you can also use half of the sweepstakes on its side and half on the other side, three on the right and three on the left, joining three of a draw with another three draw rather than the whole lot of 6
Course will give more 16, but will be more accurate, we cannot play the 16 lines makes delay statistics in 16 rows, I saw this pattern that in 50 to 70 sweepstakes had ranges of results without leaving the ultimate draw, pair to the next.
Carters Lake, Ga.
United States
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June 29, 2004
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 Posted: January 15, 2013, 12:50 pm - IP Logged

To win it, you must have one of these pairs in it.

15 16 17 19 20 23 24 28 30 34

38 40 48 56 57 59 67 69 79 80

Unless it is a double or triple,

one of the above pairs will be in it 99% of the time.

EZ

........ in the long run........

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: January 15, 2013, 1:00 pm - IP Logged
Hello, you can also see vertically six sweepstakes join by 36 we ai position numbers,
And six draws in sequence horizontally, then can cross the 4 groups horizontally with the six vertically of each position, then vertically we have -49 .36 = 13 if not in 36 the six numbers on the next draw will be within the 13 numbers,
Somerset
United Kingdom
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December 17, 2004
189 Posts
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 Posted: January 15, 2013, 4:16 pm - IP Logged

I have a mathimatical formula that produces one number for sure

But that one number is found in a group of 5 numbers. But one of the 5 will show.

The math formula works about 95% of the time.

What could a player do with a math formula like this? Could it be an advantage to anyone?

Logic states otherwise

Assuming were talking a 5/56 game

5/56 = 3,819,816 total combinations with each ball appearing 341,055 times within the total combinations

3,819,816 / 341,055 = 11.2 to 1

Each time a number is drawn the pool and pick reduces

Now we have 4 remaining to find a pool of 55

4/55 =341,055

In the 341,055 total combinations each ball appears 24,804 times

341,055/ 24,804 = 13.75 to 1

or would could say 55/4 = 13.75 to 1

Now we have 3 remaining to find a pool of 54

3/54 = 24,804

In the 24,804 total combinations each ball appears 1,378 times

24,804 / 1,378 = 18 to 1

or would could say 54/3=18 to 1

Now we have 2 remaining

2/53 = 1,378

In the 1,378 total combinations each ball appears 55 times

1,378 / 53 = 26 to 1

or would could say 53/2 = 26.5

Now we have 1 remaining to find a pool of 52

1/52 = 52

In the 52 total combinations each ball appears 1 time

52 / 1 = 52 to 1

-----------------------------------------------------------

11.2 + 13.75 + 18 + 26.6 + 52 = 121.55

121.55/ 5 = 24.31

I would suggest the best possible outcome any algorithm could achieve from your scenario would be just under the 25% hit ratio mark.

So you hit one once every 4 draws, that's the best you can do with this draw

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.

United States
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November 2, 2012
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 Posted: January 16, 2013, 11:52 am - IP Logged

I think chance of picking number correctly increases with ecah next number. To calculate 4th number as member of 4 number group is incorrect. It is still part of 5 number combination. If out of 56 numbers one is already chosen, the next one has to be chosen among 55 numbers., and it makes for a slightly better chance and so on.

United States
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November 2, 2012
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 Posted: January 16, 2013, 12:22 pm - IP Logged

Say, I use game  from 08/05/11 to calculate winning numbers: 1-5-18-27-36

I'll use 1,2,3, method.

1-1=0

5-2=3

18-3=15

27-2=25

36-1=35

Next day game is: 3-10-15-27-35. I guessed 3 numbers. Keep your hopes up, people. I could also leave 1 in place, since there is no 0 in this game. Then I'd have 4 numbers matched.

United States
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June 2, 2012
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 Posted: January 16, 2013, 11:08 pm - IP Logged

Wait a minute, now you have my attention. Did you make all that money by playing your system? Cause if you did, then I will expend as much energy needed to learn everything in this thread. lol

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: January 18, 2013, 6:33 am - IP Logged
Hello, uluska, I think you can also use this example = a 53/5 lottery
Go in the directory of sweepstakes of 53/5, and choose a number of each draw past
Using a drawing as a base or pivot, example was a result of
The number chosen is the 2nd position, then choose a number of each draw, past
But in different positions of the 2nd position, (which is the default) hitting the base number of a draw, the other numbers are in different positions, looking vertically
Or choose a number of different positions in each draw of the pivot
Economy class
Belgium
Member #123700
February 27, 2012
4035 Posts
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 Posted: January 18, 2013, 5:50 pm - IP Logged

Sorry boys, I have better.

Maryland
United States
Member #126396
April 8, 2012
413 Posts
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 Posted: February 11, 2013, 11:36 am - IP Logged

Hi Scientistman I really like what you said in your post:

"sometimes it is easier to look at the numbers physically and start choosing the numbers."

So true. Most of the times I  choose more correct numbers by pencil and paper then by wheeling them on software..I dont even want to deal with wheeling anymore..

"when really picking the numbers one should keep it very simple, yet we complcate things or think to much we screw ourselves right out of a big win.."

So true too! I always feel that it is more simple then it looks and answer around the corner, but because thinking going on to much and things get complicated we taking orselfes away from the answer..

tvpventures..

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Indonesia
Member #138826
February 7, 2013
3 Posts
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 Posted: March 1, 2013, 11:08 am - IP Logged

In my country, there is a game call pick 116. It means pick 1 numbers out of 16. The range of number is from 01 to 16. If you can pick 1 correct, you win. The prize is up to \$60 for each \$1. Another words, you multiply your bet with 60. Can you predict it?

u\$a
United States
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February 22, 2011
19967 Posts
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 Posted: March 1, 2013, 11:17 pm - IP Logged

Sorry boys, I have better.

OK were listening

Bakersfield, Ca
United States
Member #89877
April 17, 2010
203 Posts
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 Posted: March 9, 2013, 3:50 pm - IP Logged

To hvan368

Don't need to predict a number. If you play all 16 numbers you still would come out a winner if it is a \$60 payout.

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