Welcome Guest
You last visited May 16, 2022, 8:03 pm
All times shown are
Eastern Time (GMT-5:00)

# Neural Net Lottery Picker

2058 replies. Last post 4 days ago by Miha69.

 Page 21 of 138
 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 12, 2015, 2:45 pm⮟A lot of questionsSo I choosed The basic settings 09 -03 1300 by commodity (empirism if you like)Then I remarked that the F have a significant impact on the drawings if i choose between 150 and 50So then i thought that if I could find the best back testing with a good "latest used" I will therefore amplify it with the F settings( or if you perfer I hoped for it).8 is due by the fact that on keno the average to get the full spectrum is between 7 and 9 draws so 8 is in the middle .Then aside  the skipped results you get the indication  "match" if I get at least 3 in one of the 8 line changing the "use latest" cursor I then test it with the backtesting until I achieve the best of it.pretty simple a some test (on the paper) gave me some good results on 5/6 draws , I was thinking that there can be some use of this strategy.....and here we are to improve it .
Lyon
France
Member #136716
December 17, 2012
94 Posts
Offline

It would be nice if someone somewhere could try these settings on an other Keno.

Again 2x 3/4 tonight (10 euros)

 4 7 9 11 12 13 14 17 18 23 26 33 34 37 38 40 48 57 65 68

Congratulations to you stoopendaal Great master piece.

 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 13, 2015, 5:24 pmToday fail but 70 Euros for these 6 trialsSome interesting  "back testing" by tonight with latest 63 (same rules for the rest)For the 6 next (with 5 top)F = 7 = 07 08 26 33 56F = 9 = 38 26 56 07 37F =11 = 26 07 37 54 21F = 13 = 26 07 33 53 54F = 15 = 48 54 26 21 34F =17 = 26 67 38 21 48F = 19 = 38 06 39 26  07let's see
 Gambler667AustraliaMember #166169May 8, 2015115 PostsOffline October 13, 2015, 7:53 pmHi Stoopendaal,Got it !! thanks a lot !Gambler667
25
Ontario
Member #109238
April 9, 2011
60613 Posts
Offline

It would be nice if someone somewhere could try these settings on an other Keno.

Again 2x 3/4 tonight (10 euros)

 4 7 9 11 12 13 14 17 18 23 26 33 34 37 38 40 48 57 65 68

Congratulations to you stoopendaal Great master piece.

Here In Ontario A 3 Of 4 Pays 0$You Need 3 Of 3 ($25 on $1 Bet or 4/4 On$1 Bet For \$100)

 winnerlottoNew MemberRomaniaMember #169238October 9, 20159 PostsOffline October 18, 2015, 12:05 amSo ? What happened with the simulation ?
 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 18, 2015, 8:18 amI thought nobody cares ...So results from the last trialThe 6 last draws05,09,10,17,22,23,26,31,34,36,41,44,47,50,56,59,60,61,65,70 05,06,18,19,22,25,26,31,36,37,38,39,46,48,54,63,64,66,67,70 04,05,07,12,18,19,27,28,35,40,42,48,49,58,59,60,61,62,63,64 07,08,24,25,27,33,40,41,45,48,49,56,57,60,62,64,65,66,67,68 03,11,13,21,22,25,27,28,32,36,43,44,45,46,48,50,51,57,65,69 03,04,06,11,12,23,25,28,30,32,33,37,40,43,44,49,59,61,63,65As you can see at least 4-5 time 4/5 (10 Euros as 5/5 are paid 100) and in France we get 2 Euros for 3/5No 5/5 but as you can see it worth to play .
 winnerlottoNew MemberRomaniaMember #169238October 9, 20159 PostsOffline October 23, 2015, 3:50 amI've done some simulation for Keno France 20/70 with the settings below (changing F from 7 to 9, 11, 13, 15, 17, 19 )    I think these are good results, giving 2-3 times better than theory. I will test some more to find if this is only pure luck or is something else.
 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 23, 2015, 11:56 amYES !! good to see your back up.I think we have set the good stategy for keno the F+++ is the key (I may say the best actually .I hope some will be inspired to try on other keno as well)But as I told you before I have no clue for the latest as I have a very good back up as well with a lower figure (51)And it's good as well to see that you come as well with a maximum of 6 draws (you have uploaded new sets each time I guess)Now it could be interesting to calculate the return if it worth to play 4 or 5 or 6 numbers (yesterday an other 4/4....)I like you excel file (mine is in collumn )if you don't mind to share (i am lazy isn't it?), by the way how many draws do you use , me I use the fdj backup in full (cvs file).I 'd like to see up to 25 the average of each F setup (10 lines from 7) I will push as well to 7 numbers for a whileThanks you
 stoopendaalThread StarterNetherlandsMember #3476January 24, 2004212 PostsOffline October 23, 2015, 11:59 amHi winnerlotto,I see you have put a lot of effort testing the application .In the latest version of the tool  (1.5) you have the option to adjust the number of neurons in the hidden layer (with a maximum of 20 neurons). Perceplotron version 1.5 ANN2 (64 bit version):  http://intelbet.somee.com/tools/perceplotron_64.rar or http://intelbet.somee.com/tools/perceplotron_64.exePerseplotron version 1.5 ANN2 (32 bit version): http://intelbet.somee.com/tools/perceplotron_32.rar or http://intelbet.somee.com/tools/perceplotron_32.exe Good luck!
 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 23, 2015, 12:10 pmHello stoopendaal,Many thanks for this fantastic tool you give us.I found the F+ strategy by accident, after a lot of trials,unfortunatly not as good as I wished for the loto but just keno 70/20 in France.what could be the aim (advantage)  to get more hidden neurons at your point of view .?
 stoopendaalThread StarterNetherlandsMember #3476January 24, 2004212 PostsOffline October 23, 2015, 1:05 pmHi jlg69, "what could be the aim (advantage)  to get more hidden neurons at your point of view .?"  There a different rules-of-thumb to determine the number of neurons in the hidden layer to optimize the neural network for your data (in our case to get better predictions )Here some rules you can test to find the best number of neurons in the hidden layer:1In sum, for most problems, one could probably get decent performance (even without a second optimization step) by setting the hidden layer configuration using just two rules: (i) number of hidden layers equals one; and (ii) the number of neurons in that layer is the mean of the neurons in the input and output layers.The ANN in perceplotron has 2 input neurons (and 1 hidden layer) and 1 output neuron. So the number of neurons in the hidden layershould be (2+1) / 2  = 2 (when round up)  according this rule.2One additional rule of thumb for supervised learning networks, the upperbound on the number of hidden neurons that won't result in over-fitting is:Nh=Ns(alpha∗(Ni+No))Ni = number of input neurons. No = number of output neurons. Ns = number of samples in training data set. alpha = an arbitrary scaling factor usually 2-10.Others recommend setting alpha to a value between 5 and 10, but I find a value of 2 will often work without overfitting. As explained by this excellent NN Design text, you want to limit the number of free parameters in your model (its degree or number of nonzero weights) to a small portion of the degrees of freedom in your data. The degrees of freedom in your data is the number samples * degrees of freedom (dimensions) in each sample or Ns∗(Ni+No) (assuming they're all independent). So alpha is a way to indicate how general you want your model to be, or how much you want to prevent overfitting.For an automated procedure you'd start with an alpha of 2 (twice as many degrees of freedom in your training data as your model) and work your way up to 10 if the error for training data is significantly smaller than for the cross-validation data set. For example you train the ANN with the (latest) 80 draw results (= samples in training data set)For this training set the number of neurons in your hidden layer should be :  80 / (2*(2+1))  = 80/6 = 13.333 = 13  (for alpha = 2 in this example) source:  http://stats.stackexchange.com/questions/181/how-to-choose-the-number-of-hidden-layers-and-nodes-in-a-feedforward-neural-netw Good luck!
 jlg69LyonFranceMember #136716December 17, 201294 PostsOffline October 23, 2015, 6:46 pmHi stoopendalI have done some tests with your new version, and I may say sorry but it does not work.I don't get the same set than the previous one even with hidden neurones with 2 and keep repeating almost the same set.with the F+ I can just have a 2/4 and more, if I go over up to 20 it does not change anythingit seems that only 1 and 2 are working and 1 gives better backup.By exemple :Old versionF 7 , Use Lat 89 , HN 2gives : 46 7 32 57New one (same settings, same file)It gives 7 27 57 6 HN 2And 7 27 62 46 HN1  over it does not change anything 7 27 57 4  HN3 5 7 10 ....20but more the F + keep giving the same numbers all the time without changing the NN output.
Lyon
France
Member #136716
December 17, 2012
94 Posts
Offline

Sorry

6 Next  draws with latest = 83 by tomorrow mid. (previous version of Percep-Lotron)

 F=7 70 7 38 46 F=9 38 41 5 70 F=11 6 56 46 41 F=13 7 56 26 41 F=15 7 8 46 38 F=17 38 5 41 56 F=19 6 36 43 64 F=21 8 36 43 6

Good night.

 MillionsWantedNorwayMember #9517December 10, 20041836 PostsOffline October 24, 2015, 5:23 amQuote: Originally posted by stoopendaal on October 23, 2015Hi winnerlotto,I see you have put a lot of effort testing the application .In the latest version of the tool  (1.5) you have the option to adjust the number of neurons in the hidden layer (with a maximum of 20 neurons). Perceplotron version 1.5 ANN2 (64 bit version):  http://intelbet.somee.com/tools/perceplotron_64.rar or http://intelbet.somee.com/tools/perceplotron_64.exePerseplotron version 1.5 ANN2 (32 bit version): http://intelbet.somee.com/tools/perceplotron_32.rar or http://intelbet.somee.com/tools/perceplotron_32.exe Good luck!Thanks. Testing the new function now.

 Page 21 of 138