Welcome Guest
You last visited January 17, 2017, 8:34 pm
All times shown are
Eastern Time (GMT-5:00)

# System Question

Topic closed. 19 replies. Last post 12 months ago by Tialuvslotto.

 Page 1 of 2
Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 28, 2016, 4:12 pm - IP Logged

A formula or process, produces a number or a second formula that equals a number.  If that process is only successful 10% of the time is it 90% capable of predicting the number will not be next?  Could a few of these eliminate numbers from the next draw effectively"

I know the process of formula is anchored in the past.  The next draw has no anchor; but, if you could add this negative prediction to your other process results could you weed out losers?

United States
Member #35335
March 16, 2006
116 Posts
Offline
 Posted: January 28, 2016, 4:26 pm - IP Logged

A formula or process, produces a number or a second formula that equals a number.  If that process is only successful 10% of the time is it 90% capable of predicting the number will not be next?  Could a few of these eliminate numbers from the next draw effectively"

I know the process of formula is anchored in the past.  The next draw has no anchor; but, if you could add this negative prediction to your other process results could you weed out losers?

Let's take the daily 3.  Typically, one may try to find the 3 most likely numbers to hit.  Are you asking for a formula to find the 7 least likely numbers to hit?  Or, are you asking to eliminate one unlikely number which leaves you to pick 3 out of 9 with some confidence?

Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 28, 2016, 4:47 pm - IP Logged

The Later.  I'm trying to eliminate some numbers by a series of eliminations.  Not much different than just picking a number at random that won't hit, but with a system that calculates the miss by a consistent formula or process.

Member #90040
April 20, 2010
487 Posts
Online
 Posted: January 28, 2016, 7:12 pm - IP Logged

You're in CA and here is one of my elimination / winning methods.

In the last 188 combined SINGLES draws it happened that a max two consecutive times 2 or 3 of digits 034579  were not in the draw. After two consecutive skips they have always showed up again. This evening we have this situation where 2 or 3 of these digits didn't show up in the last two consecutive SINGLES draws.

This wheel has 80 of 120 total SINGLES (every combo here has 2 or 3 of digits 034579):

013 014 015 017 019 023 024 025 027 029 034 035 036 037 038 039 045 046 047 048 049 056 057 058 059 067 069 078 079 089 134 135 137 139 145 147 149 157 159 179 234 235 237 239 245 247 249 257 259 279 345 346 347 348 349 356 357 358 359 367 369 378 379 389 456 457 458 459 467 469 478 479 489 567 569 578 579 589 679 789

Only 20 combinations if you bet on all 3 of them (every combo here has 3 of digits 034579):

034 035 037 039 045 047 049 057 059 079 345 347 349 357 359 379 457 459 479 579

When Doubles and Triples show up you don't win, but if you play only once when this situation occurs you would be still making a money.

Another important thing, if you always play 3 of 6 digits after 2nd skip you have to use a progressive (but no too much aggressive) betting.

Just bet enough to cover recent losses. It'll be other times where you make money from the more frequent winnings.

This is the analysis result in only one line for the last 140 Singles in CA:

M      C L                                      T      D  C
T    M a      u a                               T      o      i  u
o    a x      r s                       T       o      t      g  r
t    x S      r t          D            o       t                r
k                   i            t              S      O
H    S p      S S          g                    C      c      c  S
i    k Q      k k          i            W       o      o      c  k
t    i t      i i          t            i       s      r      u  i
s    p y      p p          s            n       t      e      r  p    <<--Recent skip pattern<<--

2.  92    2(13)          034579  view  13800  -11200   2600    251    1   2  1 1 0 0 0 2  0 1 0 1 1 1.

Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 28, 2016, 8:13 pm - IP Logged

You're in CA and here is one of my elimination / winning methods.

In the last 188 combined SINGLES draws it happened that a max two consecutive times 2 or 3 of digits 034579  were not in the draw. After two consecutive skips they have always showed up again. This evening we have this situation where 2 or 3 of these digits didn't show up in the last two consecutive SINGLES draws.

This wheel has 80 of 120 total SINGLES (every combo here has 2 or 3 of digits 034579):

013 014 015 017 019 023 024 025 027 029 034 035 036 037 038 039 045 046 047 048 049 056 057 058 059 067 069 078 079 089 134 135 137 139 145 147 149 157 159 179 234 235 237 239 245 247 249 257 259 279 345 346 347 348 349 356 357 358 359 367 369 378 379 389 456 457 458 459 467 469 478 479 489 567 569 578 579 589 679 789

Only 20 combinations if you bet on all 3 of them (every combo here has 3 of digits 034579):

034 035 037 039 045 047 049 057 059 079 345 347 349 357 359 379 457 459 479 579

When Doubles and Triples show up you don't win, but if you play only once when this situation occurs you would be still making a money.

Another important thing, if you always play 3 of 6 digits after 2nd skip you have to use a progressive (but no too much aggressive) betting.

Just bet enough to cover recent losses. It'll be other times where you make money from the more frequent winnings.

This is the analysis result in only one line for the last 140 Singles in CA:

M      C L                                      T      D  C
T    M a      u a                               T      o      i  u
o    a x      r s                       T       o      t      g  r
t    x S      r t          D            o       t                r
k                   i            t              S      O
H    S p      S S          g                    C      c      c  S
i    k Q      k k          i            W       o      o      c  k
t    i t      i i          t            i       s      r      u  i
s    p y      p p          s            n       t      e      r  p    <<--Recent skip pattern<<--

2.  92    2(13)          034579  view  13800  -11200   2600    251    1   2  1 1 0 0 0 2  0 1 0 1 1 1.

Thank You.  I will study this and add it as a step in my elimination-inclusion process.

I have been looking at the average of the last 3 picks for each position of the next draw.  In about 90% of draws this average number is not selected.  The results show the percentages for the difference between the average and the actual draw.  0 means a match.  I am also tracking when this match occurs to try to use it either as an inclusion or as the selection.

Member #90040
April 20, 2010
487 Posts
Online
 Posted: January 28, 2016, 8:20 pm - IP Logged

Thank You.  I will study this and add it as a step in my elimination-inclusion process.

I have been looking at the average of the last 3 picks for each position of the next draw.  In about 90% of draws this average number is not selected.  The results show the percentages for the difference between the average and the actual draw.  0 means a match.  I am also tracking when this match occurs to try to use it either as an inclusion or as the selection.

Can you clarify your method by posting an example?

Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 28, 2016, 9:09 pm - IP Logged

Can you clarify your method by posting an example?

Table Showing Average of 3 Previous picks by position compared to next draw

0 in the Dif column is a match.  Percentages of no match is 84% to 85%.

 Average over Previous N1 N2 N3 N4 3 Dif + - Dif + - Dif + - Dif + - * 0 15% * 0 16% * 0 14% * 0 16% Games 1 16% 15% 1 16% 18% 1 16% 11% 1 12% 14% 200 2 10% 14% 2 13% 9% 2 15% 12% 2 12% 13% * 3 12% 9% 3 9% 8% 3 12% 11% 3 11% 11% * 4 4% 3% 4 5% 3% 4 3% 5% 4 4% 3% * 5 2% 3% 5 1% 3% 5 1% 2% 5 4% 4% * 6 0% 0% 6 0% 1% 6 0% 1% 6 0% 1% * 7 0% 0% 7 0% 0% 7 0% 0% 7 0% 0% * 8 0% 0% 8 0% 0% 8 0% 0% 8 0% 0% * 9 0% 0% 9 0% 0% 9 0% 0% 9 0% 0% B C D E Game N1 AVG DIF N2 AVG DIF N3 AVG DIF N4 AVG DIF 2809 9 7 2 3 4 -1 8 4 4 4 7 -3 2808 5 6 -1 4 4 0 1 3 -2 8 5 3 2807 6 6 0 6 4 2 2 4 -2 8 5 3 2806 6 6 0 2 3 -1 6 4 2 0 5 -5 2805 7 6 1 5 3 2 3 3 0 7 7 0 2804 4 6 -2 1 4 -3 4 3 1 9 5 4 2803 7 5 2 4 6 -2 3 4 -1 4 5 -1 2802 6 3 3 6 5 1 2 4 -2 2 5 -3 2801 1 2 -1 8 4 4 8 5 3 8 5 3 2800 1 2 -1 2 2 0 2 4 -2 6 4 2 2799 5 4 1 2 3 -1 5 4 1 1 3 -2 2798 0 5 -5 1 4 -3 6 5 1 4 4 0 2797 6 5 1 7 7 0 2 5 -3 3 3 0 2796 8 6 2 4 6 -2 7 4 3 6 3 3 2795 2 3 -1 9 5 4 6 3 3 0 3 -3 2794 7 5 2 6 5 1 0 3 -3 3 5 -2 2793 0 3 -3 1 6 -5 3 5 -2 6 4 2 2792 8 5 3 8 7 1 7 6 1 5 2 3 2791 2 4 -2 9 5 4 5 6 -1 0 1 -1
Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 28, 2016, 9:29 pm - IP Logged

Another possible eliminator.  The Percentage of hits for a difference from -3 to +3 is 90%.  Probably because most averages are in the middle part of the numbers (0-9).  Adding or subtracting 4 or 5 to the average may also be an effective eliminator.

United States
Member #116344
September 8, 2011
3941 Posts
Offline
 Posted: January 28, 2016, 10:25 pm - IP Logged

A formula or process, produces a number or a second formula that equals a number.  If that process is only successful 10% of the time is it 90% capable of predicting the number will not be next?  Could a few of these eliminate numbers from the next draw effectively"

I know the process of formula is anchored in the past.  The next draw has no anchor; but, if you could add this negative prediction to your other process results could you weed out losers?

Why not find a process that generates N-string based on current draw?. N is the size of the string.

If the next draw has 'no anchor', then find a process to simulate  the pool(0 through 9) for forward-testing.

United States
Member #164727
March 12, 2015
2656 Posts
Online
 Posted: January 28, 2016, 11:12 pm - IP Logged

A formula or process, produces a number or a second formula that equals a number.  If that process is only successful 10% of the time is it 90% capable of predicting the number will not be next?  Could a few of these eliminate numbers from the next draw effectively"

I know the process of formula is anchored in the past.  The next draw has no anchor; but, if you could add this negative prediction to your other process results could you weed out losers?

The only issue I see right now is that ALL of the pick-3 numbers have to be wrong for this to work. Speaking for myself, I can predict two out of three numbers correctly, a good portion of the time for Florida. Mybe it's that elusive third digit we should track.

Maryland
United States
Member #162434
January 2, 2015
939 Posts
Online
 Posted: January 29, 2016, 6:49 am - IP Logged

The only issue I see right now is that ALL of the pick-3 numbers have to be wrong for this to work. Speaking for myself, I can predict two out of three numbers correctly, a good portion of the time for Florida. Mybe it's that elusive third digit we should track.

Great discussion and idea! I agree with amber123 as I often JUST miss by one digit. But when I go 'all in' on a 2 digit chase, it still doesn't work.

Texas
United States
Member #150797
December 31, 2013
821 Posts
Offline
 Posted: January 29, 2016, 7:26 am - IP Logged

This is an interesting question, AllenB, and one worth pursuing.  The problem for me is that all my spreadsheets are set up "backwards", i.e. looking for what will hit!

One place that I would look for a number that will not show is among numbers that have not been hitting recently.  If a digit has not hit for 7 games there is a 73% chance that it will not hit in the next game and a 27% chance that it will hit.  These streaks continue to decay at 27% per game, with the average streak being 2 games (2 out after the criterion of 7 no-hits is met).  But, half the time these digits will continue to miss for protracted periods, up to a maximum of 20 or more games.  When you find one of these digits you are truly playing a Pick 3 of 9 game.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

~Robert A. Heinlein

Member #90040
April 20, 2010
487 Posts
Online
 Posted: January 29, 2016, 8:34 am - IP Logged

This is an interesting question, AllenB, and one worth pursuing.  The problem for me is that all my spreadsheets are set up "backwards", i.e. looking for what will hit!

One place that I would look for a number that will not show is among numbers that have not been hitting recently.  If a digit has not hit for 7 games there is a 73% chance that it will not hit in the next game and a 27% chance that it will hit.  These streaks continue to decay at 27% per game, with the average streak being 2 games (2 out after the criterion of 7 no-hits is met).  But, half the time these digits will continue to miss for protracted periods, up to a maximum of 20 or more games.  When you find one of these digits you are truly playing a Pick 3 of 9 game.

A single digit longest out is the most interesting to me too besides longest out doubles.

In this table are longest outs ready for today. If 1 dig has been out for more than 20 draws the chances are very high, but be aware that it could take up to 40 draws to show up.

Mor(xx1)  Mid(xx2)

State1 DigPairsDoublePos1Pos2Pos3ShortΣRootΣ
CT2 57-182
IL2   4-61
NC2      1-582-67
TX1   4-71

Eve(xx3) Ngt(xx4)

State1 DigPairsDoublePos1Pos2Pos3ShortΣRootΣ
CA4  17
DC4       9-59
IA4 24-117     6-59
MD4    8-65
MO4       7-59
NE4   0-61
NJ4 18-121
NY4      3-58
OK47-17     8-70
ON43-17
PA41-16
PR4      9-67
WA4      9-79

Combined

State1 DigPairsDoublePos1Pos2Pos3ShortΣRootΣ
IA5 24-133
MD5      1-55
NJ5    9-62
NY55-17
OH5      2-88
ON53-19
PA5  13
PR5  16
TN52-16    7-61
TX5 04-122
Economy class
Belgium
Member #123700
February 27, 2012
4035 Posts
Offline
 Posted: January 29, 2016, 9:25 am - IP Logged

Anything can happen.

All you could do is create some rule that you want to follow.

Flip a coin, what will be the next side up? Do you have a formula? - :)

Lincoln, California
United States
Member #167130
June 27, 2015
256 Posts
Offline
 Posted: January 29, 2016, 11:51 am - IP Logged

Why not find a process that generates N-string based on current draw?. N is the size of the string.

If the next draw has 'no anchor', then find a process to simulate  the pool(0 through 9) for forward-testing.

Interesting.  Not sure what you mean by N-String.  My original question on this post was looking for an elimination processes.  My example is just to illustrate one method.  Any Process or formula can be used.  The real question for me is when a process is only 10-15% successful in predicting a draw, is it also 85%-90% successful in predicting a number will not hit?

I know that just picking a number in a position has a 10% chance of being correct.  The idea makes me think about a process where you pick a number, declare it 90% likely not to hit, pick a second number (1-9) and so on.  By the idea you could get to the number by about the 4th or 5th pick.   I know this does not work any better than just picking a number.  Each selection has the same odds.  The only difference is that a formula or process produces a number based on a set of criteria that we track.  We all look for hits.  If a process is hits a number in a column 15% of the time vs the actual odds of the number hitting (10%) do you use it as a predictor or an eliminator.

I see the elimination process as another tool to work into the Steps for Number predictions.  Lets say you have 4 or 5 processes or formulas that you use in your workout.  You back test them and determine their hit percentages.  We mostly look for hits; but most of the time they miss.  So why not track your results and start looking for trends with your success and failure rates.  Then change your predictions based on a combination of success and failure.

Successful Elimination of  just 1 number from each position still does not give you a winning formula, just slightly better odds of winning.

I have talked about a comprehensive workout using many different formulas, combinations, Ranking, Repeats, ......?  I always looked for hits.  I have seen that I never get them all using a 1 criteria for each number even if the criteria for each number is different, 1 is not enough.  I envision a setup that brings the various systems or formulas into a matrix with on-off switches that are flipped based on prediction from my previous success / failure.

 Page 1 of 2