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# Ok here is what I promised. :)

Topic closed. 107 replies. Last post 11 years ago by Raven62.

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The Carolinas - Charlotte
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 Posted: February 2, 2006, 10:01 am - IP Logged

Raven - that is correct. That is kind of what I am looking for with the Pick 4. Except instead of straight combinations, I want the number of boxed combos.

MD
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 Posted: February 2, 2006, 10:21 am - IP Logged

i can say I see possibilities for using cashmans idea to win pick 4.... do a little back testing with your pick 3 numbers and compare the results in your states pick 4 games.

New Jersey
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 Posted: February 2, 2006, 10:36 am - IP Logged

Raven - that is correct. That is kind of what I am looking for with the Pick 4. Except instead of straight combinations, I want the number of boxed combos.

OK! Let me get this right: You have 4 numbers (1234) in Pick-4 its a 24-way box, and since you know 1234 already, you want the other 23 combinations in the 24-way box.

New Jersey
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 Posted: February 2, 2006, 10:40 am - IP Logged

i can say I see possibilities for using cashmans idea to win pick 4.... do a little back testing with your pick 3 numbers and compare the results in your states pick 4 games.

Are you seeing a correlation between Pick-3 and Pick-4 in Maryland using Cashmans Methods?

The Carolinas - Charlotte
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 Posted: February 2, 2006, 10:58 am - IP Logged

Raven - no, what I am saying is that say you wheel 7 numbers in a Pick 3 game. The number of TOTAL combinations for that is 343.

Now, take away the 7 triples, and you are left with 336 combinations, of which 126 are doubles and 210 are singles. So, that brings me to:

42 boxed doubles and

35 boxed singles

So this is what I am looking for with the Pick 4....

When you wheel 4 numbers, 5 number, 6 numbers, 7 numbers and 8 numbers, what are the total number of BOXED combinations that each wheel comprises, including singles, doubles & triples, but excluding quads.

MD
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 Posted: February 2, 2006, 11:00 am - IP Logged

Raven I didn't get real extensive just played with his idea and I saw a bunch of times when using his pick 3 idea that 3 digits in the workout were also in the next drawings pick 4 numbers. I venture to say if I had time I might find doing a lil back testing that the pick 3 results for his idea will yield the pick 4 digits that hit in the next draw.

Finding the 4th digit to go with the pick 3 digits that are made from his idea might require adding the longest digit out in pick 4 or the hottest digit. I think the idea for his method is to use a limited amount of numbers not making more than 5 pick 4 numbers. If I get some free time today/tomorrow I'll try and post some examples of what I found.

The Carolinas - Charlotte
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 Posted: February 2, 2006, 11:07 am - IP Logged

If you could, please post that here too, four4me

New Jersey
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 Posted: February 2, 2006, 11:44 am - IP Logged

Raven I didn't get real extensive just played with his idea and I saw a bunch of times when using his pick 3 idea that 3 digits in the workout were also in the next drawings pick 4 numbers. I venture to say if I had time I might find doing a lil back testing that the pick 3 results for his idea will yield the pick 4 digits that hit in the next draw.

Finding the 4th digit to go with the pick 3 digits that are made from his idea might require adding the longest digit out in pick 4 or the hottest digit. I think the idea for his method is to use a limited amount of numbers not making more than 5 pick 4 numbers. If I get some free time today/tomorrow I'll try and post some examples of what I found.

Sounds good: New ideas keep the blood flowing. Looking forward to what you discover.

New Jersey
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 Posted: February 3, 2006, 2:02 pm - IP Logged

Thanks a lot! As you can see, I am trying to figure out the total number of combinations (single/double/triple/quad) for the amount of numbers I would like to wheel. I guess if I wanted to wheel 4 numbers, that would be:

4x4x4x4 = 256 combinations (although I don't know the breakdown and would also need them boxed, so that would probably lower it to 10-20 total boxed combos.

I've been looking for a Program which would do just that, but so far I have found nothing. How's it going with the back testing?

The Carolinas - Charlotte
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 Posted: February 3, 2006, 2:15 pm - IP Logged

It's going okay. So far NJ has passed, and Georgia has not busted me out yet. So that leaves me with TX and a couple others.

The Carolinas - Charlotte
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 Posted: February 3, 2006, 2:16 pm - IP Logged

AND Missouri...

Michigan
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 Posted: February 4, 2006, 11:43 am - IP Logged
Need math help
Cashman
also cps10 because I'd like to know how you handled these in your tests
As I got involved, I see the possibility of different digits coming up, depending on the math.  Since math is unforgiving, I need a definitive answer.
First I need to know exactly what you do, Cashman.  Looking at your original description in the 1st post, I see the following:
Ex.  78+12 = 90......85+12=97
78-12=66    85-12=73
It appears to me that you simply added 78+12.  Which is fine.  But how do you add numbers when they come out like this:
Say the 3-digit number is: 899
So you have 89 +12 = 101
and         99 +12 = 111
following the normal math as you used to add in your example (78+12=90)
Also the question of negative numbers coming up.  Applying regular math, when you subtract, you end up with negative numbers.
Use 100 as the 3-digit number for this second example:
10 -12 =  -2
00 -12 = -12
-OR-
Following the "wrap around" lottery math, as was suggested by a few people. Which seems to be the proper way to "add" or "subtract" because lottery numbers are limited to 000 thru 999.
So in my examples, we would have:
First example 899
89 +12 = 91
99 +12 = 01
Second example 100
subtraction
10 -12 = 08
00 -12 = 98
So, cashman, how have you been handling those kind of situations?
I might also point out using your example of 78+12=90.
Using wrap around, you would get this:
78 +12 = 80  NOT 90.

Michigan
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 Posted: February 4, 2006, 12:15 pm - IP Logged

Sorry about the previous post being one giant paragraph. I edited it 4 times and it looks fine, until it actually gets posted. And now it won't let me edit it again.   It refuses to break everything into paragraphs!

Maybe Todd knows why? Also, for Todd...how come line breaks are formatted this way
<br/>
</br>
? And when I used them in previous posts the line break resulted is a huge space between lines rather than a space the size of the font. Why is that?

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 Posted: February 4, 2006, 3:40 pm - IP Logged
Need math help
Cashman
also cps10 because I'd like to know how you handled these in your tests
As I got involved, I see the possibility of different digits coming up, depending on the math.  Since math is unforgiving, I need a definitive answer.
First I need to know exactly what you do, Cashman.  Looking at your original description in the 1st post, I see the following:
Ex.  78+12 = 90......85+12=97
78-12=66    85-12=73
It appears to me that you simply added 78+12.  Which is fine.  But how do you add numbers when they come out like this:
Say the 3-digit number is: 899
So you have 89 +12 = 101
and         99 +12 = 111
following the normal math as you used to add in your example (78+12=90)
Also the question of negative numbers coming up.  Applying regular math, when you subtract, you end up with negative numbers.
Use 100 as the 3-digit number for this second example:
10 -12 =  -2
00 -12 = -12
-OR-
Following the "wrap around" lottery math, as was suggested by a few people. Which seems to be the proper way to "add" or "subtract" because lottery numbers are limited to 000 thru 999.
So in my examples, we would have:
First example 899
89 +12 = 91
99 +12 = 01
Second example 100
subtraction
10 -12 = 08
00 -12 = 98
So, cashman, how have you been handling those kind of situations?
I might also point out using your example of 78+12=90.
Using wrap around, you would get this:
78 +12 = 80  NOT 90.

I don't follow the "wrap around" method, as most do, which is ofcourse part of lottery math.

But, when using the power number 12, I ignore it.

In case with 899, I would just add the 2 together....101+111= 1111.

10-12=-2, which I would list as 02.

0-12=-12 which I would list as 12.

78+12=80....not 90.  :)

This method, though a very simple, and basic use of the power number 12, is useless without "mixing".

By mixing, I mean, by knowing what every number's "familiars" are.

Ex.  1=6, 0, 2  And at times 1=8,4

Michigan
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 Posted: February 4, 2006, 3:45 pm - IP Logged

Thanks cashman, clears up the issue.

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