Stone Mountain*Georgia United States Member #828 November 2, 2002 10491 Posts Offline

Posted: October 14, 2007, 9:24 am - IP Logged

Many years ago I noticed that most groups of numbers would all take turns going away for a time then return.

Some groups hit on average just like clock work. OK ...maybe a sloppy clock. LOL Never the less they do hit on a pretty dependable time frame.

Different groups have different hit rates depending on their size of course ...etc.

The question is this....

Why do most all of the number groups return ....in or around 6 times their normal math average hit rate?

What is it about approaching 6 times over the normal return rate.....that causes these groups to snap back..... no matter how large or small a particular group's average return is?

Sure ....there are many "stinkers" out there going 7,8,or 10 times over their expected hit rate averages but they are certainly the exceptions. Most follow the game plan and do return before they get to their 6 x times average out time.

I still use my6x magic mark with good success ....... but.... I do not know what the Math is behind that presumption.

Does anyone want to give it a shot? It's really the basis of almost everything I do in my PICK 3 game and yet I still don't understand. I know how .....just don't know why. LOL

Is it a....... Math or is it a Probability question ?

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

LAS VEGAS United States Member #47729 November 22, 2006 4508 Posts Online

Posted: October 15, 2007, 7:29 pm - IP Logged

Quote: Originally posted by WIN D on October 14, 2007

Many years ago I noticed that most groups of numbers would all take turns going away for a time then return.

Some groups hit on average just like clock work. OK ...maybe a sloppy clock. LOL Never the less they do hit on a pretty dependable time frame.

Different groups have different hit rates depending on their size of course ...etc.

The question is this....

Why do most all of the number groups return ....in or around 6 times their normal math average hit rate?

What is it about approaching 6 times over the normal return rate.....that causes these groups to snap back..... no matter how large or small a particular group's average return is?

Sure ....there are many "stinkers" out there going 7,8,or 10 times over their expected hit rate averages but they are certainly the exceptions. Most follow the game plan and do return before they get to their 6 x times average out time.

I still use my6x magic mark with good success ....... but.... I do not know what the Math is behind that presumption.

Does anyone want to give it a shot? It's really the basis of almost everything I do in my PICK 3 game and yet I still don't understand. I know how .....just don't know why. LOL

Is it a....... Math or is it a Probability question ?

@ Win D, et al-

Thanks for this sharing this discovery-

I know this response doesn't exactly fit your game plan discription but many bluw moons back I discovered that a repeating number (or expected number) in roulette would hit very often by the 4th, 5th or 6th spins after the original occurance.

And also agreed not exactly each and every time but above the expected odds.

LAS VEGAS United States Member #47729 November 22, 2006 4508 Posts Online

Posted: October 15, 2007, 8:39 pm - IP Logged

Quote: Originally posted by eddessaknight on October 15, 2007

@ Win D, et al-

Thanks for this sharing this discovery-

I know this response doesn't exactly fit your game plan discription but many bluw moons back I discovered that a repeating number (or expected number) in roulette would hit very often by the 4th, 5th or 6th spins after the original occurance.

And also agreed not exactly each and every time but above the expected odds.

Beyond Coincidence???

EddessaKnight

Nota Bene;

Additionally I have ben successful with 6th Choice $$$ Selections with thoroughbred racing (for those interested, see the record my past performance post sin gaming forum)

Findlay, Ohio United States Member #4855 May 28, 2004 400 Posts Offline

Posted: October 15, 2007, 8:54 pm - IP Logged

Event

Odds

6 Times Due

7 Times Due

Root Sum (1-9): 111/1000

1 in 9.09

0.9984526204

0.9994633233

Digit (Position Specific): 1/10

1 in 10

0.9982029897

0.9993734213

Straight Pairs: 1/100

1 in 100

0.9975949907

0.9991196888

Straights: 1/1000

1 in 1000

0.9975286779

0.9990913062

Boxed Pair (no-match) 54/1000

1 in 18.52

0.9980056229

0.9992657436

Boxed Pair (Double) 28/1000

1 in 35.72

0.9977702973

0.9991978926

Boxed No-Match

1 in 166.67

0.9975802484

0.9991089325

Boxed Double

1 in 333.33

0.9975435008

0.9990994673

Hey Win D - How Are Ya?

Heres my take on it.....

Since average skips usually approximate the odds over the long term, then six times the average skip is close to being out six times the odds. Look at the probabilities of events out at 6 times their odds...then look at the probabilities for events out 7 time their odds. While the difference in chance seems small, it's enough to make 63 to 65 percent of those six-times-outers hit before making it to 7...and then some maybe. lol

Stone Mountain*Georgia United States Member #828 November 2, 2002 10491 Posts Offline

Posted: October 16, 2007, 5:46 am - IP Logged

Quote: Originally posted by Thoth on October 15, 2007

Event

Odds

6 Times Due

7 Times Due

Root Sum (1-9): 111/1000

1 in 9.09

0.9984526204

0.9994633233

Digit (Position Specific): 1/10

1 in 10

0.9982029897

0.9993734213

Straight Pairs: 1/100

1 in 100

0.9975949907

0.9991196888

Straights: 1/1000

1 in 1000

0.9975286779

0.9990913062

Boxed Pair (no-match) 54/1000

1 in 18.52

0.9980056229

0.9992657436

Boxed Pair (Double) 28/1000

1 in 35.72

0.9977702973

0.9991978926

Boxed No-Match

1 in 166.67

0.9975802484

0.9991089325

Boxed Double

1 in 333.33

0.9975435008

0.9990994673

Hey Win D - How Are Ya?

Heres my take on it.....

Since average skips usually approximate the odds over the long term, then six times the average skip is close to being out six times the odds. Look at the probabilities of events out at 6 times their odds...then look at the probabilities for events out 7 time their odds. While the difference in chance seems small, it's enough to make 63 to 65 percent of those six-times-outers hit before making it to 7...and then some maybe. lol

Thanks for your post eddessaknight .... I appreciate it.

and Mr Thoth ..... where have you been fella? If I had your skills ......life sure would be a lot more fun! LOL

Man .... just look at that chart. What nice work you produce..... Thank you very much Thoth.

This sort of research will grow and morph into a whole new game strategy and "Alert" system ...... but it sure as the devil won't come from me or any of my crude attempts . I am just holding on by my fingernails here... LOL

Using this to track and trap groups in P-3 such as the ....... All ODD/All EVENAll High/LowConsecutive Straights and the like sure would have winning along the way as a research incentive ! LOL

Much Thanks.....

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

Stone Mountain*Georgia United States Member #828 November 2, 2002 10491 Posts Offline

Posted: October 16, 2007, 6:54 am - IP Logged

Here's a queston....

If you had deep enough pockets.... and were armed with the fact that NO DOUBLES would hit the next day...... and be right 90% of the time ....do you think you could make a living at the PICK -3 game ?

By the way....

After several years of watching and over hearing several things over time..... I believe that there is a man in Atlanta actually making a living based on Doubles that he uses in Pick- 3 to make a good wage here. He plays so many numbers each day...the Store actually lets him enter his own tickets!

He is an older man .... he drives a brand new Mercedes every year and lives in a monster house and owns a lot of real estate around the area. I do know he went to GA Tech many years ago....but that still doesn't mean he couldn't have found a working system anyway. LOL

I may be on the verge of getting to see some of this System pretty soon. I'm keeping my fingers crossed.

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

South Carolina United States Member #6 November 4, 2001 8790 Posts Online

Posted: October 16, 2007, 8:11 am - IP Logged

Quote: Originally posted by WIN D on October 16, 2007

Here's a queston....

If you had deep enough pockets.... and were armed with the fact that NO DOUBLES would hit the next day...... and be right 90% of the time ....do you think you could make a living at the PICK -3 game ?

By the way....

After several years of watching and over hearing several things over time..... I believe that there is a man in Atlanta actually making a living based on Doubles that he uses in Pick- 3 to make a good wage here. He plays so many numbers each day...the Store actually lets him enter his own tickets!

He is an older man .... he drives a brand new Mercedes every year and lives in a monster house and owns a lot of real estate around the area. I do know he went to GA Tech many years ago....but that still doesn't mean he couldn't have found a working system anyway. LOL

I may be on the verge of getting to see some of this System pretty soon. I'm keeping my fingers crossed.

Numbers in groups works well. Just a matter of the right group(s) at the right time.

West Concord, MN United States Member #21 December 7, 2001 3675 Posts Offline

Posted: October 26, 2007, 5:26 am - IP Logged

WIN D,

There is a mathematical way to express what you are seeing across these different events. This also relates to two different topics I posted a while back a topic called the Potential Reoccurrence Probability and the Potential Occurrence Probability. Both of these are related, but to show how they are and how this relates to your problem, we'll need to do a little Calculus. The Potential Reoccurrence Probability is the following equation:

y = e^{-(x / m)}

x is the difference between the last draw and the current draw and m is the average rate reoccurrence of these differences. y tells what is the probability that an event will reoccur given its average rate of reoccurrence and the draws since its last event. As the number draws increase without a reoccurrence of the event, there is also another probability that the event will occur. This probability is the measure of the work already done by its potential reoccurrence relative by proportion to its average rate of reoccurrence. Every time an event does not occur, it builds up a potential of occurrence by integrating these values through its draw difference. The basic definite integral looks like this.

y = m^{-1} [a to b] òe^{-(x / m)} dx

This then becomes

y = m^{-1} (-me^{-(x / m)}½ [a to b])

The limits of the integral are then a = 0 and b = x. b is equal to x because we are looking for the occurrence for the same draw difference as our original equation. This works out to the following.

y = m^{-1} (-me^{-(x / m)}½ [0 to x])

y = m^{-1} ((-me^{-(x / m)}) - (-me^{-(0 / m)})

y = m^{-1} (-me^{-(x / m)} + me^{-(0 / m)})

y = (m / m) (- e^{-(x / m)} + e^{-(0 / m)})

y = - e^{-(x / m)} + e^{-(0 / m)}

y = e^{-(0 / m)} - e^{-(x / m)}

y = 1 - e^{-(x / m)}

This equation shows the probability an event will occur relative to its last draw and in proportion to the total possible reoccurrences since then to its average rate of reoccurrence. This equation can explain why you are seeing this phenomena of proportion by 6 in most everything. We need to convert this equation into a percentage by multiplying by 100%. Also, when evaluating the equation it's best to round the values to an integer value. In your case, will be looking for when does x by proportion to m is the value of y in percent equal to 100% first and only first to be 100%. In addition, we'll give this proportion an integer value to keep in line with the integer measure of y. The proportion you are looking at is as follows.

x = n · m

n is an integer factor that you are looking at and when n = 6 is the phenomena point you are observing. If we substitute in to the potential occurrence equation we get this.

y = 100% · (1 - e^{-((n · m) / m)})

This reduces down...

y = 100% · (1 - e^{-n})

This is the general equation that fits for any phenomena because the average rate of reoccurrence factored out and is now relative to your observations in terms of n. n is the number of times the phenomena's average rate of reoccurrence has happened. Now we can apply it to some values and see what happens for any kind of phenomena. Below is a table showing the percentage of total occurrences that have happen since the last draw.

n

Percent

0

0%

1

63%

2

86%

3

95%

4

98%

5

99%

6

100%

7

100%

8

100%

9

100%

10

100%

As you can see, by time we get to the 6th n value, there will be in every phenomena an integer percentage of 100% occurrence. This is exactly what you are seeing, the magic #6.

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

West Side of Sunny Florida United States Member #55048 September 8, 2007 3371 Posts Offline

Posted: October 30, 2007, 5:28 pm - IP Logged

Quote: Originally posted by JADELottery on October 26, 2007

WIN D,

There is a mathematical way to express what you are seeing across these different events. This also relates to two different topics I posted a while back a topic called the Potential Reoccurrence Probability and the Potential Occurrence Probability. Both of these are related, but to show how they are and how this relates to your problem, we'll need to do a little Calculus. The Potential Reoccurrence Probability is the following equation:

y = e^{-(x / m)}

x is the difference between the last draw and the current draw and m is the average rate reoccurrence of these differences. y tells what is the probability that an event will reoccur given its average rate of reoccurrence and the draws since its last event. As the number draws increase without a reoccurrence of the event, there is also another probability that the event will occur. This probability is the measure of the work already done by its potential reoccurrence relative by proportion to its average rate of reoccurrence. Every time an event does not occur, it builds up a potential of occurrence by integrating these values through its draw difference. The basic definite integral looks like this.

y = m^{-1} [a to b] òe^{-(x / m)} dx

This then becomes

y = m^{-1} (-me^{-(x / m)}½ [a to b])

The limits of the integral are then a = 0 and b = x. b is equal to x because we are looking for the occurrence for the same draw difference as our original equation. This works out to the following.

y = m^{-1} (-me^{-(x / m)}½ [0 to x])

y = m^{-1} ((-me^{-(x / m)}) - (-me^{-(0 / m)})

y = m^{-1} (-me^{-(x / m)} + me^{-(0 / m)})

y = (m / m) (- e^{-(x / m)} + e^{-(0 / m)})

y = - e^{-(x / m)} + e^{-(0 / m)}

y = e^{-(0 / m)} - e^{-(x / m)}

y = 1 - e^{-(x / m)}

This equation shows the probability an event will occur relative to its last draw and in proportion to the total possible reoccurrences since then to its average rate of reoccurrence. This equation can explain why you are seeing this phenomena of proportion by 6 in most everything. We need to convert this equation into a percentage by multiplying by 100%. Also, when evaluating the equation it's best to round the values to an integer value. In your case, will be looking for when does x by proportion to m is the value of y in percent equal to 100% first and only first to be 100%. In addition, we'll give this proportion an integer value to keep in line with the integer measure of y. The proportion you are looking at is as follows.

x = n · m

n is an integer factor that you are looking at and when n = 6 is the phenomena point you are observing. If we substitute in to the potential occurrence equation we get this.

y = 100% · (1 - e^{-((n · m) / m)})

This reduces down...

y = 100% · (1 - e^{-n})

This is the general equation that fits for any phenomena because the average rate of reoccurrence factored out and is now relative to your observations in terms of n. n is the number of times the phenomena's average rate of reoccurrence has happened. Now we can apply it to some values and see what happens for any kind of phenomena. Below is a table showing the percentage of total occurrences that have happen since the last draw.

n

Percent

0

0%

1

63%

2

86%

3

95%

4

98%

5

99%

6

100%

7

100%

8

100%

9

100%

10

100%

As you can see, by time we get to the 6th n value, there will be in every phenomena an integer percentage of 100% occurrence. This is exactly what you are seeing, the magic #6.

SNAP... Crackle ... POP.....

That was my brain exploding while I attempted to follow Jades math!!!!

D.C./MD. United States Member #44103 July 30, 2006 5583 Posts Online

Posted: November 26, 2007, 6:34 pm - IP Logged

Quote: Originally posted by JADELottery on November 18, 2007

Me too, and just think... they teach this at the high school level too.... OH-NO!

Advanced high school! Solving an integral brings back headaches! The notation you use for the limits of the integral is a bit different than what I remember, but still will produce headaches. Thanks for writing it out.

West Concord, MN United States Member #21 December 7, 2001 3675 Posts Offline

Posted: November 27, 2007, 1:13 pm - IP Logged

Quote: Originally posted by jarasan on November 26, 2007

Advanced high school! Solving an integral brings back headaches! The notation you use for the limits of the integral is a bit different than what I remember, but still will produce headaches. Thanks for writing it out.

Actually, I wouldn't know anything about 'advanced high school', I'm a dropout. I learned Calculus myself. My son is learning Calculus in high school, he's a senior and doing ok. The notation you see is what the Lottery Post allows you to see, in order to correctly see the notation the LP would have to implement something like MathPlayer in its web programming. I just formatted it as close as possible the way the LP would allow.

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

Honduras Member #20982 August 29, 2005 4715 Posts Offline

Posted: December 19, 2007, 10:43 pm - IP Logged

Quote: Originally posted by WIN D on October 16, 2007

Here's a queston....

If you had deep enough pockets.... and were armed with the fact that NO DOUBLES would hit the next day...... and be right 90% of the time ....do you think you could make a living at the PICK -3 game ?

By the way....

After several years of watching and over hearing several things over time..... I believe that there is a man in Atlanta actually making a living based on Doubles that he uses in Pick- 3 to make a good wage here. He plays so many numbers each day...the Store actually lets him enter his own tickets!

He is an older man .... he drives a brand new Mercedes every year and lives in a monster house and owns a lot of real estate around the area. I do know he went to GA Tech many years ago....but that still doesn't mean he couldn't have found a working system anyway. LOL

I may be on the verge of getting to see some of this System pretty soon. I'm keeping my fingers crossed.

Whao that is something WinD...In my town of Columbus, GA, there is an older man who drives a purple nissan pick up truck...I used to always see him redeeming cash3 tickets....Like everyday...

"The Lotto Truth is Out There" taken from context of the movie "The X-Files"