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# Need help with system for Pick-3

80 replies. Last post 27 days ago by lottolot.

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United States
Member #164727
March 12, 2015
2527 Posts
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 Posted: November 1, 2016, 8:34 pm - IP Logged

I just saw a video on You tube which was interesting. Did not know that If I were to pick one number that I thought will NOT show in the next drawing, and no doubles or triples, there would be only 84 combinations boxed.

What this person demonstrates is how to reduce those 84 combinations by eliminating the pairs from your last three draws. In the person's example, he ended up with 39 combinations.

My question is, does LP have a tool that will generate the combos I want for this scenario, meaning all combos excluding the one number I don't want, plus no doubles and triples?

BASICALLY YOU ARE GUARANTEED TO WIN IF THAT ONE NUMBER DOES NOT SHOW, AND NO DOUBLES OR TRIPLES.

Below is the video. Just fast forward it to get the info faster.

United States
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March 12, 2015
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 Posted: November 1, 2016, 8:36 pm - IP Logged

How about eliminating two numbers?  Yowza !!!

u\$a
United States
Member #106665
February 22, 2011
19888 Posts
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 Posted: November 2, 2016, 1:45 am - IP Logged

Well gives you something to think about.

Let it Snow

Member #90040
April 20, 2010
473 Posts
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 Posted: November 2, 2016, 5:01 am - IP Logged

I just saw a video on You tube which was interesting. Did not know that If I were to pick one number that I thought will NOT show in the next drawing, and no doubles or triples, there would be only 84 combinations boxed.

What this person demonstrates is how to reduce those 84 combinations by eliminating the pairs from your last three draws. In the person's example, he ended up with 39 combinations.

My question is, does LP have a tool that will generate the combos I want for this scenario, meaning all combos excluding the one number I don't want, plus no doubles and triples?

BASICALLY YOU ARE GUARANTEED TO WIN IF THAT ONE NUMBER DOES NOT SHOW, AND NO DOUBLES OR TRIPLES.

Below is the video. Just fast forward it to get the info faster.

You can generate pairs from multiple draws as shown in the video or you can break multiple draws into pairs by P2gen then copy/paste those pairs into P3gen and select only "2 of group digits".

The result will be the same, 66 box combinations.

At the end just filter them out with previously stored 84 combos in the green panel by "FInd green in white" button and you get 39 no matching combinations.

United States
Member #41846
June 23, 2006
460 Posts
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 Posted: November 2, 2016, 9:34 am - IP Logged

How about eliminating two numbers?  Yowza !!!

because you have eliminated all comb with the first number , a second number will only give roughly half the reduction the first number gave.  with a second number you should end up with approximately 55-60 comb.  and this can vary a little with the selected numbers

United States
Member #164727
March 12, 2015
2527 Posts
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 Posted: November 2, 2016, 10:50 am - IP Logged

Thank you helpmewin, mmx1 and phileight. So are you saying there's no tool on LP?

New Jersey
United States
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June 28, 2005
49813 Posts
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 Posted: November 2, 2016, 11:03 am - IP Logged

I just saw a video on You tube which was interesting. Did not know that If I were to pick one number that I thought will NOT show in the next drawing, and no doubles or triples, there would be only 84 combinations boxed.

What this person demonstrates is how to reduce those 84 combinations by eliminating the pairs from your last three draws. In the person's example, he ended up with 39 combinations.

My question is, does LP have a tool that will generate the combos I want for this scenario, meaning all combos excluding the one number I don't want, plus no doubles and triples?

BASICALLY YOU ARE GUARANTEED TO WIN IF THAT ONE NUMBER DOES NOT SHOW, AND NO DOUBLES OR TRIPLES.

Below is the video. Just fast forward it to get the info faster.

Systems Tab: Positional Wheel: Pick 3 & Gold or Platinum Membership (Depending on Filtering Capabilities Desired)!

A mind once stretched by a new idea never returns to its original dimensions!

Zaperlopopotam
Belgium
Member #173932
March 26, 2016
971 Posts
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 Posted: November 2, 2016, 11:07 am - IP Logged

a) You eliminate one digit that isn't in the last two drawings.

Count: 729
1 digit: 9
2 digits: 216
3 digits: 504

b) Suppose 6 different boxed pairs in the last three drawings and you eliminate those.
.
Count: 465
1 digit: 9
2 digits: 180
3 digits: 276

c) You castrate the straight combinations to boxed combinations.

Count: 115
1 digit: 9
2 digits: 60
3 digits: 46

That is what you get!

emuis.be/syst
emuis.be/pick3

I'm working on a central pick 3 page. More is in transformation and make. It is very good.

The video should be removed. It is not good work and seems to be stuffed with adds.

.
ORLANDO, FLORIDA
United States
Member #4924
June 3, 2004
5912 Posts
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 Posted: November 2, 2016, 11:22 am - IP Logged

a) You eliminate one digit that isn't in the last two drawings.

Count: 729
1 digit: 9
2 digits: 216
3 digits: 504

b) Suppose 6 different boxed pairs in the last three drawings and you eliminate those.
.
Count: 465
1 digit: 9
2 digits: 180
3 digits: 276

c) You castrate the straight combinations to boxed combinations.

Count: 115
1 digit: 9
2 digits: 60
3 digits: 46

That is what you get!

emuis.be/syst
emuis.be/pick3

I'm working on a central pick 3 page. More is in transformation and make. It is very good.

The video should be removed. It is not good work and seems to be stuffed with adds.

How much you plan on charging for this\$\$\$\$?

United States
Member #164727
March 12, 2015
2527 Posts
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 Posted: November 2, 2016, 11:58 am - IP Logged

Systems Tab: Positional Wheel: Pick 3 & Gold or Platinum Membership (Depending on Filtering Capabilities Desired)!

Thank you for the information. Waiting for Gold Membership to kick in and will post my predictions for today. I will be eliminating the number 4 for Florida for today.

United States
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March 12, 2015
2527 Posts
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 Posted: November 2, 2016, 12:15 pm - IP Logged

Okay, here's the list for Florida. Started with 84 combinations which excludes the number 4.

Then I filtered by eliminating the the pairs from the last three draws. And then I added another filter of no all highs, all lows, all evens, and all odds.

The pairs eliminated are 93 90 30 46 48 68 56 53 57 37

Total: 33 combos for mid draw today.

1. 0-1-5
2. 0-1-6
3. 0-1-7
4. 0-1-8
5. 0-2-5
6. 0-2-7
7. 0-2-8
8. 0-5-8
9. 0-6-7
10. 0-7-8
11. 1-2-5
12. 1-2-6
13. 1-2-7
14. 1-2-8
15. 1-2-9
16. 1-3-6
17. 1-3-8
18. 1-5-8
19. 1-6-7
20. 1-6-9
21. 1-7-8
22. 1-8-9
23. 2-3-5
24. 2-3-6
25. 2-3-8
26. 2-5-8
27. 2-5-9
28. 2-6-7
29. 2-6-9
30. 2-7-8
31. 2-7-9
32. 2-8-9
33. 3-5-8

Dallas, Texas
United States
Member #4549
May 2, 2004
1730 Posts
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 Posted: November 2, 2016, 2:02 pm - IP Logged

You can eliminate the first step completely by making a chart like this......

Eliminating one digit will not change the list of 84 you start with, i.e., every time you eliminate 0 you will get the same 84 results. Every time you eliminate 1, you get the same 84 to start with, etc. From there all you need do is go through that 84 and eliminate the pairs.

My greatest accomplishment is teaching cats about Vienna Sausage. When I need a friend, all I need do is walk outside, pop open a can, and every little critter in the neighborhood drops by to say "Hi!"

United States
Member #41846
June 23, 2006
460 Posts
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 Posted: November 2, 2016, 2:12 pm - IP Logged

here is an Excel file . I only provided for 6 pairs. advise if more are needed.

it does use macros so macros have to be enabled.

https://www.dropbox.com/s/krn5j6y1hc88qhz/amber123.xlsm?dl=0

United States
Member #164727
March 12, 2015
2527 Posts
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 Posted: November 2, 2016, 2:20 pm - IP Logged

Okay, here's the list for Florida. Started with 84 combinations which excludes the number 4.

Then I filtered by eliminating the the pairs from the last three draws. And then I added another filter of no all highs, all lows, all evens, and all odds.

The pairs eliminated are 93 90 30 46 48 68 56 53 57 37

Total: 33 combos for mid draw today.

1. 0-1-5
2. 0-1-6
3. 0-1-7
4. 0-1-8
5. 0-2-5
6. 0-2-7
7. 0-2-8
8. 0-5-8
9. 0-6-7
10. 0-7-8
11. 1-2-5
12. 1-2-6
13. 1-2-7
14. 1-2-8
15. 1-2-9
16. 1-3-6
17. 1-3-8
18. 1-5-8
19. 1-6-7
20. 1-6-9
21. 1-7-8
22. 1-8-9
23. 2-3-5
24. 2-3-6
25. 2-3-8
26. 2-5-8
27. 2-5-9
28. 2-6-7
29. 2-6-9
30. 2-7-8
31. 2-7-9
32. 2-8-9
33. 3-5-8

Winner was 918, a winner...yay.

I'll be betting at that imaginary place, although it won't be imaginary for me...

Won: \$150

Cost: \$33.00

Net: \$117.00

I'll do tonight's soon.

United States
Member #164727
March 12, 2015
2527 Posts
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 Posted: November 2, 2016, 2:21 pm - IP Logged

You can eliminate the first step completely by making a chart like this......

Eliminating one digit will not change the list of 84 you start with, i.e., every time you eliminate 0 you will get the same 84 results. Every time you eliminate 1, you get the same 84 to start with, etc. From there all you need do is go through that 84 and eliminate the pairs.

Nice chart, one glance, but where do I get it? Thanks.

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