Hello everyone

I am starting a new topic on lexicographic number selection in hopes of gaining some new ideas.

I have been working with lexi's for several years and will be posting links to download software

as this moves along. I hope to pull in a few pick-3 pick-4 players along the way as I think that

they may have much to say or add to this post. This might be a way for pick3/4 players to put

there skills to use for the big games and also help big-game players improve their play at the same

time.

In a 5-39 game there are 575757 sets that can be numbered from 1 to 57575 but if you pad this

value with (0's) you can then divide it into two pick-3's. To start with we would have 000,001 to

575,757 the front-3 with odds of 1 in 575 and The back 3 have odds of 1 in 757. I have the software

that can make all the conversions and I will be posting this in a few days for anyone interested. The

good thing about this is that it is possible to miss all the selections and still end up with lower prizes

so to start of with I want to show a few tricks.

LV = Lexicographic Value

Last nights drawing = [01 04 07 11 24] LV =016012 front 3 = [016] back-3 = [012]

If a person could hit these both then they could hit a 5 of 5 with one set but that would not be easy to do.

This next information is a little hard to understand so you may need to read it a few times to understand

what I am doing. Because the back 3 could be any value from 000 to 999 depending on the front-3 digits

I use a little trick to help reduce the field. The set 10-16-19-35-37 = LV 446999 but above I said that the

back-3 has a range of 000 to 757. Here is a simple trick to give the back 3 the same conditions as the

front-3.

Example

first add 1 to the greatest value in the matrix in this case it is 39. 39 + 1 = 40 now using 40 subtract the

numbers from the set like this. set = 01-04-07-11-24

40-24 = 16

40-11 = 29

40-7 = 33

40-4 = 36

40-1 = 39

You now have the set 16-29-33-36-39 LV = 541875. Note, remember the first 3 cannot be greater then 575

You may be asking how can this help. remember above that I said the range for the first three digits were

000 to 575 by using this trick the back-3 have the same odds. You now have two pick-3 games with odds

of 1 in 575. In simple you use the converted data to analyze thrn the software reverses the process and gives

you the numbers. Without this conversion the each digit in the back-6 could be 0 to 9 and with the conversion

the first digit has a range of 0 to 5. The second digits in the back-3 range is limited by the first digit selection

because the 3 digits combined cannot exceed 575. So if the first digit in the B-3 is 5 then the second digit must

not be graeter then 7. If the second B-3 digit = 7 then the third digit cannot be greater then 5. I have been toying

with this for years to help me set a range for the first and fifth numbers that I use with my digit system. The way

I use it now is to range the first 2 digits in both the F-3 and B-3 to within a 2 digit span. This gives me a very small

range for the first and last numbers in my sets. Many times using this method I can end up with two first numbers

and two fifth numbers thus truning the Pick-5 into a keyed wheel assigning 2 numbers to the 1st and 2 numbers to

the 5th position. Many times using only the first lexi digit for F-3 and B-3 will determind the first and fifth numbers in

the set. I am hoping that someone might probe this a little more and see what falls out. The math behind this has not

been worked out completely and I invite anyone to pitch in. I posted this in the math forum because I think most of

the replies will be in terms of odds and that is what I am interested in.

RL