Lexicographic Numbers and a little mathPrev TopicNext Topic

• adamcustom

  

  Poland
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  February 2, 2010
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  Apr 27, 2011, 9:08 am

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  In response to RL-RANDOMLOGIC

  Quote: Originally posted by RL-RANDOMLOGIC on Apr 27, 2011

  Adam

  I am hoping through discussion that we can find something that will make this easier.  I still have much to

  add about how this can be used but as you know if we can't pick the correct values then it is all for nothing.

  I was thinking that if a person could set up for 2 or 3 tight  runs and then select maybe 5 sets from each 

  that it might pay off.  I also think that the field can be narrowed down for most draws without much work.

  The second number will normally be in a very small group so it should not take too many sets to produce a

  3 of 5.  The reverse Lexi can be used to range the 4th number but I have not included it yet but will add it

  as this moves along.  Hitting the ranges for both foward and reverse could yeild a 4 of 5 with very few sets 

  but only if you get close in the settings.  I was not offended by your reply I was just making it known what 

  what we were doing here is not easy and much more work needs to be done.  This works just like the DOS

  version of Anom but with a different interface.  Several setups will work even if you miss both the ranges

  depending on the matrix.  For my 5-39 game setting the first digit to 0 or 1 can produce the number 2 so

  it does have some room for error on the part of the user.  My main goal is to range the third number into

  a small group using both the FL and RL values togeather.  So far this has eluded me but I have data that

  makes me believe it can be done.  I normaly work alone on my projects but with this I hope others will input

  a few new ideas, otherwise it will not be worth my time to continue.  The code I posted to calculate the lexi

  from the set or the set from the lexi took a lot of hard work and I thought that someone out there would

  have commented on it.   When I first wrote it several years ago I had to work out the formulas because I

  had never heard of anyone getting the set from the lexi and was told by many that it could not be done. 

  Without this the and the reverse lexi then this whole post would not be possible.  Oh well, I guess the old

  saying that "one man's treasure is another man's junk" is spot on here. 
  

  RL

  RL,

   

  Thanks for your understanding. I think that some pick-3 or pick-4 players could contribute a bit with their experience with what actually works.

  Some strategies of playing are based on worst/best pairings of digits in some ranges. Does it work, I do not know.

   

  Adam
• garyo1954

  

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  Apr 27, 2011, 9:53 am

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  In response to adamcustom

  Quote: Originally posted by adamcustom on Apr 27, 2011

  RL,

   

  Thanks for your understanding. I think that some pick-3 or pick-4 players could contribute a bit with their experience with what actually works.

  Some strategies of playing are based on worst/best pairings of digits in some ranges. Does it work, I do not know.

   

  Adam

  Interesting that you mention best/worst pairings by range. Yesterday I ran the back digit pairings by position for any 5/39 game to see what came up. (In Texas we have a 5/37). Might need to run a 5/39 to compare the overall results. I highlighted the first and fifth back digits to get some idea. From the overall totals one would expect these to be true since 1 to 9 contain the largest spread. I haven't taken the time to carefully go through this yet, but it appears that digits 9, 8, 7, 6, (5) have a greater chance of hitting in the highest number. The more you close the gap in the second and fifth and thrid and fifth, the more likely a 9 will appear in the fifth digit. As I say I'll have to run a 5/39 to see if this holds true before jumping off the deep end.

  
  
• RL-RANDOMLOGIC

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  Apr 27, 2011, 11:21 am

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  In response to garyo1954

  Quote: Originally posted by garyo1954 on Apr 27, 2011

  Interesting that you mention best/worst pairings by range. Yesterday I ran the back digit pairings by position for any 5/39 game to see what came up. (In Texas we have a 5/37). Might need to run a 5/39 to compare the overall results. I highlighted the first and fifth back digits to get some idea. From the overall totals one would expect these to be true since 1 to 9 contain the largest spread. I haven't taken the time to carefully go through this yet, but it appears that digits 9, 8, 7, 6, (5) have a greater chance of hitting in the highest number. The more you close the gap in the second and fifth and thrid and fifth, the more likely a 9 will appear in the fifth digit. As I say I'll have to run a 5/39 to see if this holds true before jumping off the deep end.

  
  

  Gary

  Nice chart, My 5-39 the digits 4 & 0 are the worst hitters, I never checked them as a pair but I always 

  start with them to see if they can be blocked.   Digit 5 has the best hit rate followed by 6.  Base digits 1-2-3

  are almost always put in play and in the old dos version there is an option that allows you to select decade

  dights for each number.  This reduces sets very quickly but I did not include this option in the 64 bit version. 

  My old bayes predictor use to go through every filter and digit and try to match all the settings but it seemed

  to stop working one day and I have yet to figure out why.  It also used the lexi option to range the groups, 

  when it worked it was dead on but for some unknown reason it just quit working.  What I have found is that

  almost all the back digit configurations seen to run through cycles and the longer they don't show the more

  likely they are to hit.  Right now I have been working with the group settings, I normaly can hit 4 of the digits

  and then set 2 or 3 more to the 0/1 option and then try to set the ID to control the totals.  I can on most days

  hit all the side bar filters if I don't try and set them too tight.  I played 13 lines last night and hit 5ea 2 of 5 

  so I lost $8.00, I got to get back on my game, I have only played around 10 times this year and my bigggest

  win has been around $30.00.   I have so many projects going that I don't have the time to do a proper workup.

  I have been working on some stuff that Josephus sent me but don't have enough time to really test it.  Let me

  know if you find anything for the 5-39 game.  I can send you a drawfile if you need it.  Just let me know what

  format you want it in. Also don't forget to do a base digit total count, my game runs in the 5 to 6 range for most

  draws.

  RL
• garyo1954

  

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  Apr 27, 2011, 12:01 pm

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  In response to RL-RANDOMLOGIC

  Quote: Originally posted by RL-RANDOMLOGIC on Apr 27, 2011

  Gary

  Nice chart, My 5-39 the digits 4 & 0 are the worst hitters, I never checked them as a pair but I always 

  start with them to see if they can be blocked.   Digit 5 has the best hit rate followed by 6.  Base digits 1-2-3

  are almost always put in play and in the old dos version there is an option that allows you to select decade

  dights for each number.  This reduces sets very quickly but I did not include this option in the 64 bit version. 

  My old bayes predictor use to go through every filter and digit and try to match all the settings but it seemed

  to stop working one day and I have yet to figure out why.  It also used the lexi option to range the groups, 

  when it worked it was dead on but for some unknown reason it just quit working.  What I have found is that

  almost all the back digit configurations seen to run through cycles and the longer they don't show the more

  likely they are to hit.  Right now I have been working with the group settings, I normaly can hit 4 of the digits

  and then set 2 or 3 more to the 0/1 option and then try to set the ID to control the totals.  I can on most days

  hit all the side bar filters if I don't try and set them too tight.  I played 13 lines last night and hit 5ea 2 of 5 

  so I lost $8.00, I got to get back on my game, I have only played around 10 times this year and my bigggest

  win has been around $30.00.   I have so many projects going that I don't have the time to do a proper workup.

  I have been working on some stuff that Josephus sent me but don't have enough time to really test it.  Let me

  know if you find anything for the 5-39 game.  I can send you a drawfile if you need it.  Just let me know what

  format you want it in. Also don't forget to do a base digit total count, my game runs in the 5 to 6 range for most

  draws.

  RL

  Sounds like me at the moment. We had major storms here the last two evenings. Emptied the boat yesterday. More in it today. At least I we know if it holds water it won't leak!

  Working on getting the three digit patterns as well. Thinking first three, mid three, back three to see if/where the ties are. Might work. Might be nothing more than more data that tells a lot of data things.

  At one time I thought the back 5 would be worth chasing, but since we both agree they only repeat once every 100 draws, that went belly up.

  YES! I would love to get a 5/39. You know how I write, so whatever form suits you. I can adapt the code to read it. 

  I'll be back. I had to go get a thermocouple for the hot water heater. NO hot water for a shower! Makes waking up fun.

   

  G
• RL-RANDOMLOGIC

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  In response to garyo1954

  Quote: Originally posted by garyo1954 on Apr 27, 2011

  Sounds like me at the moment. We had major storms here the last two evenings. Emptied the boat yesterday. More in it today. At least I we know if it holds water it won't leak!

  Working on getting the three digit patterns as well. Thinking first three, mid three, back three to see if/where the ties are. Might work. Might be nothing more than more data that tells a lot of data things.

  At one time I thought the back 5 would be worth chasing, but since we both agree they only repeat once every 100 draws, that went belly up.

  YES! I would love to get a 5/39. You know how I write, so whatever form suits you. I can adapt the code to read it. 

  I'll be back. I had to go get a thermocouple for the hot water heater. NO hot water for a shower! Makes waking up fun.

   

  G

  Gary

  I had to laugh about the boat because it reminded me of the three stooges when curly shot a hole in the

  bottom of the boat so the water would drain, Problem was they were on the lake at the time.

  RL
• garyo1954

  

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  Apr 28, 2011, 1:47 am

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  In response to RL-RANDOMLOGIC

  Quote: Originally posted by RL-RANDOMLOGIC on Apr 27, 2011

  Gary

  I had to laugh about the boat because it reminded me of the three stooges when curly shot a hole in the

  bottom of the boat so the water would drain, Problem was they were on the lake at the time.

  RL

  It's all good. I laughed too. I even had a thought to put shampoo in the boat, throw the dog in and wash both at the same time.
• RL-RANDOMLOGIC

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  Apr 28, 2011, 2:39 am

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  Next part.  I am assuming that everyone understands so far so I will add a little more. If something

  does not make since then please ask.  Any question is a good question and I often miss steps so

  if your having a problem then others might also.

   

  Watch for typo's as I make many mistakes
  
  FL / RL codes. 
  Remember that the software adds (0)'s to the end of the Low range
  and (9)'s to the end of the high range so "000" = 000001 to 000999
  for any matrix with a 6 digit lexi value. If both Low and HI are
  set to "000" then 001 is added to LOw and 999 is added to High.
  This allows a full range to be covered without the need to adjust
  all 6 digits because 3-digit resolution is all that is needed to
  range the first and last number of a set.  It can be done with as
  few as 1 but 3 are needed to cover everything.
  
  
  ##   code  Low to Hi 
  #1 = LLL = x00 TO x12
  #2 = LLH = x13 TO x24
  #3 = LHL = x25 TO x37
  #4 = LHH = x38 TO x50
  #5 = HLL = x51 TO x62
  #6 = HLH = x63 TO x74
  #7 = HHL = x75 TO x86
  #8 = HHH = x87 TO x99
  
  These 8 ranges will work for any matrix but X will be different for each.
  
  a 5-32 game has 142506 sets so the x range = 0-1          Random selection = 1 in 2 =50%
  
  a 5-36 game has 376992 sets so the x range = 0-1-2-3      Random selection = 1 in 4 =25% 
  
  a 5-37 game has 435897 sets so the x range = 0-1-2-3-4    Random selection = 1 in 5 =20%
  
  a 5-39 game has 575757 sets so the x range = 0-1-2-3-4-5  Random selection = 1 in 6 = 17% "rounded"
  
  
  The first digit selection is the most important but in certain drawings it does
  not need to be correct.  The 2nd/3rd digit selection is even less critical.
  
  Example 5-39 matrix.
  Look at set 02 16 27 32 35. Lexi = 130760.  Any setting between 073816 to 139860
  would produce a number 02 as the first number. This means that for this draw all
  the below selections would have worked.
  
  X   code
  0 + LLL
  0 + LLH
  0 + LHL
  0 + LHH
  0 + HLH
  0 + HHL
  
  1 + HHL
  1 + HHH
  
  If you don't understand this then please ask for more instructions because it is
  improtant to using this.  A simple way to check the times each number in the matrix
  appears as the first number in a set is shown below. Lets say that you want to calc
  the starting lexi value for number 3 meaning set 03-04-05-06-07.
  
  Simple method 5-39 matrix
  
  since you are moving past all the sets that start with 01 or 02 then you are now working
  with a 5-37 matrix. using the nCr function calculate the total sets which are 435897. Now

  using the sets in the origional 5-39 subtract. 575757 - 435897 = 139860 Then add 1 so
  the first set with number 3 falls on lexi value 136861. Now to calc the last set with
  number 03 as a first number calculate as a 5-36 game = 376992.  Now subtract again
  575757 - 376992 = 198765 which is the lexi for the highest set that starts with the
  number 03. Next subtract 198765 - 139860 = 58905 which is the number of sets that start
  with the number 03. If you have downloaded the LexiCalc program then you could calculate
  this using it's [Conv] option and enter in the numbers 3-4-5-6-7 and get the lexi value
  139861 and then redue and enter 3-36-37-38-39 to get lexi value 198765 now sub
  198765 - 139861 = 58904 + 1 = 58905   
  
  I hope this makes since butif it does not then please ask.  You should really understand
  this before you move on.
  
  RL
• RL-RANDOMLOGIC

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  Apr 28, 2011, 3:02 am

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  Another calculation that may be needed as we move along.

  To calculate how many sets contain any one number from the matrix. first calculate the sets in the matrix

  5-39 = 575757 now subtract 39-1 = 38. 

  Now calculate sets in a 5-38 = 501942. 

  Now subtract, 575757 - 501942 = 73815

  Each number in a 5-39 game appears 73815 times

  Another method.  575757 * 5 = 2878785 / 39 = 73815   Note! the 5 here is the numbers in each set.

  RL
• RL-RANDOMLOGIC

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  In response to RL-RANDOMLOGIC

  Quote: Originally posted by RL-RANDOMLOGIC on Apr 28, 2011

  Next part.  I am assuming that everyone understands so far so I will add a little more. If something

  does not make since then please ask.  Any question is a good question and I often miss steps so

  if your having a problem then others might also.

   

  Watch for typo's as I make many mistakes
  
  FL / RL codes. 
  Remember that the software adds (0)'s to the end of the Low range
  and (9)'s to the end of the high range so "000" = 000001 to 000999
  for any matrix with a 6 digit lexi value. If both Low and HI are
  set to "000" then 001 is added to LOw and 999 is added to High.
  This allows a full range to be covered without the need to adjust
  all 6 digits because 3-digit resolution is all that is needed to
  range the first and last number of a set.  It can be done with as
  few as 1 but 3 are needed to cover everything.
  
  
  ##   code  Low to Hi 
  #1 = LLL = x00 TO x12
  #2 = LLH = x13 TO x24
  #3 = LHL = x25 TO x37
  #4 = LHH = x38 TO x50
  #5 = HLL = x51 TO x62
  #6 = HLH = x63 TO x74
  #7 = HHL = x75 TO x86
  #8 = HHH = x87 TO x99
  
  These 8 ranges will work for any matrix but X will be different for each.
  
  a 5-32 game has 142506 sets so the x range = 0-1          Random selection = 1 in 2 =50%
  
  a 5-36 game has 376992 sets so the x range = 0-1-2-3      Random selection = 1 in 4 =25% 
  
  a 5-37 game has 435897 sets so the x range = 0-1-2-3-4    Random selection = 1 in 5 =20%
  
  a 5-39 game has 575757 sets so the x range = 0-1-2-3-4-5  Random selection = 1 in 6 = 17% "rounded"
  
  
  The first digit selection is the most important but in certain drawings it does
  not need to be correct.  The 2nd/3rd digit selection is even less critical.
  
  Example 5-39 matrix.
  Look at set 02 16 27 32 35. Lexi = 130760.  Any setting between 073816 to 139860
  would produce a number 02 as the first number. This means that for this draw all
  the below selections would have worked.
  
  X   code
  0 + LLL
  0 + LLH
  0 + LHL
  0 + LHH
  0 + HLH
  0 + HHL
  
  1 + HHL
  1 + HHH
  
  If you don't understand this then please ask for more instructions because it is
  improtant to using this.  A simple way to check the times each number in the matrix
  appears as the first number in a set is shown below. Lets say that you want to calc
  the starting lexi value for number 3 meaning set 03-04-05-06-07.
  
  Simple method 5-39 matrix
  
  since you are moving past all the sets that start with 01 or 02 then you are now working
  with a 5-37 matrix. using the nCr function calculate the total sets which are 435897. Now

  using the sets in the origional 5-39 subtract. 575757 - 435897 = 139860 Then add 1 so
  the first set with number 3 falls on lexi value 136861. Now to calc the last set with
  number 03 as a first number calculate as a 5-36 game = 376992.  Now subtract again
  575757 - 376992 = 198765 which is the lexi for the highest set that starts with the
  number 03. Next subtract 198765 - 139860 = 58905 which is the number of sets that start
  with the number 03. If you have downloaded the LexiCalc program then you could calculate
  this using it's [Conv] option and enter in the numbers 3-4-5-6-7 and get the lexi value
  139861 and then redue and enter 3-36-37-38-39 to get lexi value 198765 now sub
  198765 - 139861 = 58904 + 1 = 58905   
  
  I hope this makes since butif it does not then please ask.  You should really understand
  this before you move on.
  
  RL

  The above should read

  X   code

  0 + HLH
  0 + HHL
  0 + HHH

  1 + LLL
  1 + LLH
  1 + LHL
  1 + LHH
   

  From hereon out I will refer to the 3-letter code by the digits 1 to 8

  ##   code  Low to Hi 
  #1 = LLL = x00 TO x12
  #2 = LLH = x13 TO x24
  #3 = LHL = x25 TO x37
  #4 = LHH = x38 TO x50
  #5 = HLL = x51 TO x62
  #6 = HLH = x63 TO x74
  #7 = HHL = x75 TO x86
  #8 = HHH = x87 TO x99

   

  Write this down and save it for reference
  ________________
  ##    Low to Hi       
  #1 = x00 TO x12
  #2 = x13 TO x24
  #3 = x25 TO x37
  #4 = x38 TO x50
  #5 = x51 TO x62
  #6 = x63 TO x74
  #7 = x75 TO x86
  #8 = x87 TO x99
  ________________

   

  So now a 2 digit code will be used to range the Low/HI range

  0 + #6
  0 + #7
  0 + #8

  1 + #1
  1 + #2
  1 + #3
  1 + #4

  RL
• dr san

  

  bgonçalves
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  June 9, 2010
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  Apr 28, 2011, 9:00 am

  ▲▼

  Rl randonic Hello, good job on these three filters, one could calculate a closed combination
    Up to 64% mathematically and the other 36% random, the lower percentage of random
    Seems to work better together with conbinçao mathematics, then see having frequencies
    Higher, lower and middle of each column but the calculation is for each vertical column, as
    The study of the lexicon could help in the calculation of repetitions, ie the interval between repetitions
  Each lottery number?
• RL-RANDOMLOGIC

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  Apr 28, 2011, 10:53 am

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  This is a after the fact setup for MO 5-39 last nights draw to demonstrate how to use the code.  It does not

  attempt to explain how to select the values.
  

  

  WED  04/27/11   03 09 14 18 27   FL=168   RL=507 

  ##    Low to Hi       
  #1 = x00 TO x12
  #2 = x13 TO x24
  #3 = x25 TO x37
  #4 = x38 TO x50
  #5 = x51 TO x62
  #6 = x63 TO x74
  #7 = x75 TO x86
  #8 = x87 TO x99

  The FL value that hit was 168 so we would have needed to select (1) as the first value.  This is the X value

  in the list above.  Looking at #6 we see that this range covers the last two digits needed for last nights draw.

  which was 68 so x63 to x74 would have been the best choice.  Now using these two values we would replace

  the (x) with (1) and add the digits 63 giving us a value of [163] for the foward Lexi Low value.  Next we again

  replace the (x) in the second set with (1) giving us [174] for the high range.  Running the program returns 03 

  as the only first number using this range.  Notice that in the the results above that the second number for the

  starting set = 8 and then ending set second number is 10.  This means that the second number will be 08-09-10.

  We now have 1 first number and 3 second numbers to play which gives us three possible pairs for the first and

  second numbers and using the RL value returns we know that the fifth number will be 26 or 27. 

  03-08-xx-xx-26 = 1 of 5

  03-08-xx-xx-27 = 2 of 5

  03-09-xx-xx-26 = 2 of 5

  03-09-xx-xx-27 = 3 of 5

  03-10-xx-xx-26 = 1 of 5

  03-10-xx-xx-27 = 2 of 5

  If our reverse lexi settings would have produced only one number then we would only need 3 sets to cover the

  combinations to this point and have 2ea 2 of 5's and 1ea 3 of 5's in 3 lines. We now have 12 numbers to fill in

  to complete the 6 lines.  Our second lowest number = 8 and the highest fifth number is 27 so we have 09-10-11

  12-13-14-15-16-17-18-19-20-21-22-23-24-25-26 or 18 numbers to put into play to cover all the in-range numbers.

  If the run above in the Pic had only produced 1 fifth number then we could range the 4th number the same way

  we did the 2nd number.  Because we have two 5th numbers this would give several to choose form so we will use

  the option of using all 18 of the unused numbers to fill in the blanks.  Next look at the 3rd number in the starting

  set which is 03-08-09-17-30 for last nights draw this would not help much because the 2nd and 3rd numbers were

  08-09.  If the numbers in the start set would have been something like 03-08-15 then we could discard all the unused

  numbers below 15 for the 3rd number.  Being that we have only 12 empty or missing numbers in our six lines we need

  to use 3 of the lines twice.

  03-08-09-10-26 = 2 of 5

  03-08-11-12-27 = 2 of 5

  03-09-13-14-26 = 3 of 5

  03-09-15-16-27 = 3 of 5

  03-10-17-18-26 = 2 of 5

  03-10-19-20-27 = 2 of 5

  + the 3 top lines

  03-08-21-22-26 = 1 of 5

  03-08-23-24-27 = 2 of 5

  03-09-25-26-26 = we cannot use 26 twice so I finish this line out below and discard this line

  03-09-25-26-27 = 3 of 5

   

  We now have 9 lines which produced 3ea. 3 of 5's,  5ea. 2 of 5's and 1ea. 1 of 5.  My game 

  pays $1.00 for a 2 of 5 so my $9.00 investment returned $35.00. or $26.00 profit.  Now I will do this again 

  simulating getting one number to play for the 5th number. Remember that one 5th number would return

  only 3 lines

  03-08-09-10-27 = 3 of 5

  03-09-11-12-27 = 3 of 5

  03-10-13-14-27 = 3 of 5

   + 6 lines to use all the numbers

  03-08-15-16-27 = 2 of 5

  03-09-17-18-27 = 4 of 5

  03-10-19-20-27 = 2 of 5

  03-08-21-22-27 = 2 of 5

  03-09-23-24-27 = 3 of 5

  03-10-25-26-27 = 2 of 5

  We now have 4ea. 2 of 5's, 4ea. 3 of 5's,  1ea. 4 of 5 for $294.00 or $285.00 profit.   All I needed to do this

  is to select two digit values for the foward lexi and  2 digit values for the reverse lexi.  My choices are 0 to 5

  for the first and #1 to #8 for the last range digits.  Some days it will take a few more lines to cover and some

  days it could take less.  I am working on a way to range the 3rd number and if successful then many of the

  numbers can be taken out of play and of the remaining numbers, they will be position specific.  I will be providing

  a means for you to build a database thinking this might help select the values needed for each run.  I also hope

  that others will share what they find in the process.  Again watch for mistakes because I write this without any

  editing. Well almost no editing, If I see something before the time limit to edit then I will fix it.

   

  RL
• RL-RANDOMLOGIC

  United States
  Member #59,352
  March 13, 2008
  5,626 Posts
  Offline
  Apr 28, 2011, 11:14 am

  ▲▼

  Here's the download link again for anyone new that's interested

  http://www.box.net/shared/7d5sf6jmpx

  RL
• dr san

  

  bgonçalves
  Brasil
  Member #92,560
  June 9, 2010
  3,781 Posts
  Offline
  Apr 28, 2011, 11:54 am

  ▲▼

  Hello all possible conbinaçoes pick4 provided no repeat digits or a lottery of 39 / 5 to hit the endings (last digit of the number) since that does not repeat
    Terminations =

  1234
  1235
  1236
  1237
  1238
  1239
  1230
  1245
  1246
  1247
  1248
  1249
  1240
  1256
  1257
  1258
  1259
  1250
  1267
  1268
  1269
  1260
  1278
  1279
  1270
  1289
  1280
  1290
  1345
  1346
  1347
  1348
  1349
  1340
  1356
  1357
  1358
  1359
  1350
  1367
  1368
  1369
  1360
  1378
  1379
  1370
  1389
  1380
  1390
  1456
  1457
  1458
  1459
  1450
  1467
  1468
  1469
  1460
  1478
  1479
  1470
  1489
  1480
  1490
  1567
  1568
  1569
  1560
  1578
  1579
  1570
  1589
  1580
  1590
  1678
  1679
  1670
  1689
  1680
  1690
  1789
  1780
  1790
  1890
  2345
  2346
  2347
  2348
  2349
  2340
  2356
  2357
  2358
  2359
  2350
  2367
  2368
  2369
  2360
  2378
  2379
  2370
  2389
  2380
  2390
  2456
  2457
  2458
  2459
  2450
  2467
  2468
  2469
  2460
  2478
  2479
  2470
  2489
  2480
  2490
  2567
  2568
  2569
  2560
  2578
  2579
  2570
  2589
  2580
  2590
  2678
  2679
  2670
  2689
  2680
  2690
  2789
  2780
  2790
  2890
  3456
  3457
  3458
  3459
  3450
  3467
  3468
  3469
  3460
  3478
  3479
  3470
  3489
  3480
  3490
  3567
  3568
  3569
  3560
  3578
  3579
  3570
  3589
  3580
  3590
  3678
  3679
  3670
  3689
  3680
  3690
  3789
  3780
  3790
  3890
  4567
  4568
  4569
  4560
  4578
  4579
  4570
  4589
  4580
  4590
  4678
  4679
  4670
  4689
  4680
  4690
  4789
  4780
  4790
  4890
  5678
  5679
  5670
  5689
  5680
  5690
  5789
  5780
  5790
  5890
  6789
  6780
  6790
  6890
  7890
• mindtab

  

  California
  United States
  Member #26,498
  November 18, 2005
  94 Posts
  Offline
  Apr 28, 2011, 2:09 pm

  ▲▼

  Hello everyone. 

  Still reading info on the thread.  Just wanted to add a tidbit here, maybe not necessarily related to the post, however, it is in relation to the Lexico.

  What I have also done in my software is to divide the Lexico number, eg 575757 into groups. I divided mine into 5 groups.

  Example

  Groups:     
   1 )  1 to 115151  2 )  115152 to 230302  3 )  230303 to 345453  4 )  345454 to 460604  5 )  460605 to 575757
  
  Subgroups:   
   1 )  23030    2 )  46060    3 )  69090    4 )  92120    5 )  115150 
  
  Sub-Subgroups:
   2 )  4606     2 )  9212     3 )  13818    4 )  18424    5 )  23030 
  
  sub-sub-subgrp
  3 )  921      2 )  1842     3 )  2763     4 )  3684     5 )  4605   
  
   1             380171        4  2  3  3  4
   2             487780        5  2  1  5  3
   3             196652        2  4  3  4  3
   4             169336        2  3  2  4  5
   5             343027        3  5  5  3  2
   6             347832        4  1  1  3  3
   7              097726       1  5  2  2  1
   8             409500        4  3  4  5  3

  380171--from main group 4  -->345454 to 460604

   

      stepper=INT(lexico/rowmax*2)  'group step through lexico 115151 (max lexico for 5/39=575757)
      stepper1=INT(stepper/rowmax)  'subgroup step 23030 through each group
      substepper1=INT(stepper1/rowmax) 'sub-subgroup step 4606 through each subgroup
      substepper2=INT(substepper1/rowmax) 'sub-sub-subgroup step 921 through each sub-subgroup
    '  substepper3=INT(substepper2/rowmax) 'sub-sub-sub-subgroup step 84
• mindtab

  

  California
  United States
  Member #26,498
  November 18, 2005
  94 Posts
  Offline
  Apr 28, 2011, 2:13 pm

  ▲▼

  In subgroups section, all first numbers are 1) 

  Subgroups:   
    1 )  23030    2 )  46060    3 )  69090    4 )  92120    5 )  115150 
  
  Sub-Subgroups:
    1 )  4606     2 )  9212     3 )  13818    4 )  18424    5 )  23030 
  
  sub-sub-subgrp
  1 )  921      2 )  1842     3 )  2763     4 )  3684     5 )  4605     

  sub-sub-sub-subgrp

  1) 84  ..........

  The main group gives you position 1 Range of the Lexico, while the subgroups cover the ranges with this Range  (like a breakdown)  Even if gauging odd/even for each (I'll call it IndexMatch) IM position can help in reducing sets.