mid-Ohio United States Member #9 March 24, 2001 19891 Posts Offline

Posted: August 30, 2012, 11:39 am - IP Logged

Quote: Originally posted by Ronnie316 on August 30, 2012

I suppose my biggest question RJOh is what percentage of wins are found within the past 8 draws??

There has been 742 periods of 8 drawing in the 750 drawings since the last MM matrix change of which 31 or 4% had all 5 winning numbers, 126 or 16% had 4 winning numbers and 258 or 34% had 3 winning numbers. These drawings included 23-36 numbers.

Picking strings of 5 numbers which never repeat which the graphic shows could have included 45 04 09 and 50 but not 40 is a strategy I've used which automatically eliminate numbers and is likely to have 3 of the winning numbers on the same line if you play enough lines.

* you don't need to buy more tickets, just buy a winning ticket *

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: August 30, 2012, 11:50 am - IP Logged

Quote: Originally posted by RJOh on August 30, 2012

There has been 742 periods of 8 drawing in the 750 drawings since the last MM matrix change of which 31 or 4% had all 5 winning numbers, 126 or 16% had 4 winning numbers and 258 or 34% had 3 winning numbers. These drawings included 23-36 numbers.

Picking strings of 5 numbers which never repeat which the graphic shows could have included 45 04 09 and 50 but not 40 is a strategy I've used which automatically eliminate numbers and is likely to have 3 of the winning numbers on the same line if you play enough lines.

Interesting RJOh because thats only slightly better than the odds I was getting on all even/all odd wins.

mid-Ohio United States Member #9 March 24, 2001 19891 Posts Offline

Posted: August 30, 2012, 11:59 am - IP Logged

Quote: Originally posted by Ronnie316 on August 30, 2012

Interesting RJOh because thats only slightly better than the odds I was getting on all even/all odd wins.

Since both groups averages about 28 numbers, it shouldn't be surprising that their odds of winning are similar. I thought you were trying to define/find a group who's winnings exceeded the odds.

* you don't need to buy more tickets, just buy a winning ticket *

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: August 30, 2012, 12:00 pm - IP Logged

Have you found a way to go back by number total instead of line total??

Im only asking because I noticed in the example above that 21 draws back represents 48 numbers in this instance but can represent a smaller or larger group of numbers in other instances.

mid-Ohio United States Member #9 March 24, 2001 19891 Posts Offline

Posted: August 30, 2012, 12:25 pm - IP Logged

Quote: Originally posted by Ronnie316 on August 30, 2012

Have you found a way to go back by number total instead of line total??

Im only asking because I noticed in the example above that 21 draws back represents 48 numbers in this instance but can represent a smaller or larger group of numbers in other instances.

As I've mention many times my programs are written in GWBasic which is a MS-DOS language that won't work on any OS newer than XP.

It could be done by looking at the position of the winning number in the sorted combination and subtracting the difference minus the combination length from the line total but adding that routine would just add more lines to a program that has almost reached its memory limits. I'm making a note of it and if/when I rewrite the program in a newer/different language I may change it. Until I spend some time learning a newer language, I'm stucked using GWBasic and Windows XP.

* you don't need to buy more tickets, just buy a winning ticket *

Sorry if I keep asking the same question, Its not intentional.

The objective is to improve upon the 2.6% win rate that 28 numbers gives overall. 4% will certainly do that but as Stack has stated, wining every 15 draws should be a reasonable objective which I believe is 6.6%

I would think 7.5% would be needed overall to overcome losses due to bad elimination numbers and still get close to the objective on a consistent basis.

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: August 30, 2012, 4:37 pm - IP Logged

Ok, each draw will be a different number total......

but, for tomorrow nights draw I can go back a full 12 draws and use a total of 38 different number. To play a group of 28 I need to eliminate 10 numbers, and to play a group of 12...... I need to eliminate 26 numbers.

mid-Ohio United States Member #9 March 24, 2001 19891 Posts Offline

Posted: August 30, 2012, 6:21 pm - IP Logged

Quote: Originally posted by Ronnie316 on August 30, 2012

Sorry if I keep asking the same question, Its not intentional.

The objective is to improve upon the 2.6% win rate that 28 numbers gives overall. 4% will certainly do that but as Stack has stated, wining every 15 draws should be a reasonable objective which I believe is 6.6%

I would think 7.5% would be needed overall to overcome losses due to bad elimination numbers and still get close to the objective on a consistent basis.

Since 28 numbers can generate 98280 combinations of fives and the odds of matching 5/56 with that many combinations is 1:39 or 2.6% which is about a third of 7.5%, I wouldn't have any idea how to go about trying to develop a strategy to accomplishes that on my budget.

The only strategies I've ever considered were picking 10-30 combinations that had never come up with popular distribution patterns of previous drawings.

* you don't need to buy more tickets, just buy a winning ticket *

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: August 30, 2012, 7:01 pm - IP Logged

Quote: Originally posted by RJOh on August 30, 2012

Since 28 numbers can generate 98280 combinations of fives and the odds of matching 5/56 with that many combinations is 1:39 or 2.6% which is about a third of 7.5%, I wouldn't have any idea how to go about trying to develop a strategy to accomplishes that on my budget.

The only strategies I've ever considered were picking 10-30 combinations that had never come up with popular distribution patterns of previous drawings.

I actually like the sound of that strategy very very much RJOh, I have always been of the belief that a human can perceive and detect popular distribution patterns BETTER than any program will ever come close to.

But as I have heard you state... you have never had the winner to throw out.... much less pick.

The best I have seen is what Stack did by reducing my 98,280 down to 4931 and still retaining the winner.

I believe he used the 4 if 4 of 28 and the winner was on line 1115?