United States Member #164727 March 12, 2015 2509 Posts Offline

Posted: October 25, 2015, 9:43 pm - IP Logged

The numbers 0 through 4 as the lowest number will show most often in any State's Pick-3 Game winning numbers. As long as the number 0,1,2,3, or 4 is the lowest digit and no doubles, you win. Just take a look at your State's last 30 days mid and eve winners.

Do you see what I see? This is just the current pattern, always watch out for a new pattern to emerge, that's the key.

After two zeros show in a row, a one appears. Tonight's Florida hit was 781. See the 1 in 781? The number 1 was the lowest digit as I would have predicted.

OKC, OK United States Member #120575 December 22, 2011 811 Posts Offline

Posted: October 25, 2015, 10:45 pm - IP Logged

Quote: Originally posted by amber123 on October 25, 2015

The numbers 0 through 4 as the lowest number will show most often in any State's Pick-3 Game winning numbers. As long as the number 0,1,2,3, or 4 is the lowest digit and no doubles, you win. Just take a look at your State's last 30 days mid and eve winners.

Do you see what I see? This is just the current pattern, always watch out for a new pattern to emerge, that's the key.

After two zeros show in a row, a one appears. Tonight's Florida hit was 781. See the 1 in 781? The number 1 was the lowest digit as I would have predicted.

bel air maryland United States Member #90251 April 24, 2010 4855 Posts Offline

Posted: October 25, 2015, 11:33 pm - IP Logged

Quote: Originally posted by amber123 on October 25, 2015

The numbers 0 through 4 as the lowest number will show most often in any State's Pick-3 Game winning numbers. As long as the number 0,1,2,3, or 4 is the lowest digit and no doubles, you win. Just take a look at your State's last 30 days mid and eve winners.

Do you see what I see? This is just the current pattern, always watch out for a new pattern to emerge, that's the key.

After two zeros show in a row, a one appears. Tonight's Florida hit was 781. See the 1 in 781? The number 1 was the lowest digit as I would have predicted.

Texas United States Member #150797 December 31, 2013 815 Posts Offline

Posted: October 26, 2015, 7:15 am - IP Logged

Excellent strategy!

Zero is the most frequent low digit in the game with 28% of hits.

One is the second most frequent low digit at 21% of hits. With just these two digits you will be correct in 49% of draws.

Two hits as low digit 17% of the time.

Three hits as the low digit 13% of the time, but is actually slightly more common in the Middle position at 14% of combos.

As Grwurston pointed out, with 0,1,2,3 in the low position you have covered almost 80% of possible combinations. With just 0,1,2 at low you will cover 66% of the total combinations.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

Texas United States Member #150797 December 31, 2013 815 Posts Offline

Posted: October 26, 2015, 7:27 am - IP Logged

If neither of the 0 or 1 digits have shown in a draw the probability is 0.74 for one to show in the next game. This means that if you don't have a 0 or a 1 in a draw, 74% of the time one or both of these digits will show up in the next game.

After 2 absences in a row the probability is 0.86. The probability rises to 0.92 after three absences in a row, and is 0.96 after neither 0 nor 1 shows for 4 games in a row.

BTW, these statistics are the same for 8 or 9 in the high position.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

ORLANDO, FLORIDA United States Member #4924 June 3, 2004 5893 Posts Online

Posted: October 26, 2015, 8:37 am - IP Logged

Quote: Originally posted by Tialuvslotto on October 26, 2015

If neither of the 0 or 1 digits have shown in a draw the probability is 0.74 for one to show in the next game. This means that if you don't have a 0 or a 1 in a draw, 74% of the time one or both of these digits will show up in the next game.

After 2 absences in a row the probability is 0.86. The probability rises to 0.92 after three absences in a row, and is 0.96 after neither 0 nor 1 shows for 4 games in a row.

BTW, these statistics are the same for 8 or 9 in the high position.

Tia, leave it to you, to show very valuable stats. Thank you. I noticed Fl has a digit 9 at 5 overall skips. Have to keep my eyes that one.

United States Member #164727 March 12, 2015 2509 Posts Offline

Posted: October 26, 2015, 8:40 am - IP Logged

Thanks everyone who responded.

I know this is taboo, but after I make some venture capital money, I'm going big-time playing all 110 combinations all-six ways online in that place I can't mention. That's where the big money will be.

In Florida, from Oct. 4 to Oct. 24, my account would have been $4,140 richer had I played all 110 combinations all six ways offshore.

110 X 6 = $660.00

$660.00 X 42 draws= $27,720 -This would be the total cost for the 21 days.

In those 21 days, there were 8 doubles and 1 winner which was above 4. So 9 X 660= $5,940 lost.

42 X 900 = 37,800--this is how much I would've won.

37,800-won

-27,720-cost

=10,080-net

- 5,940-8 doubles lost and one winner above 4

= 4,140-net gain

Not bad for 3 weeks.

There will be months that will have more doubles and ruin your day. I tested 4 months in Florida, July was the only month that was a disaster, the rest were profitable.

EDIT: Of course that's too much to start off unless you have a hefty bankroll, so I plan to start playing boxed only.

ALL $1.00 bet only

July-21 days test-lost $300.00....(two numbers above 4) (16 doubles)---TOO MANY DOUBLES I LOST MONTH OF JULY

Aug. 21 days test-won $250.00...(one number above 4) (12 doubles)...Good profit

Sept.-21 days test-won$360.00....(no high numbers above 4) (12 doubles)...good profit

Oct.-21 days test-won $690.00...(one number above 4) (8 doubles)...very good profit

Now remember, this is only at $1.00 bet. Let's see after many months we move to $10.00 bets for each number.

July - LOST $3,000

Aug - WON $2,500

Sept - WON $3,600

Oct - WON $6,900

Total won- $13,000

Lost- $3,000

Net win- $10,000

Net win every week average for four months= $625.00, not bad for one week.

Texas United States Member #150797 December 31, 2013 815 Posts Offline

Posted: October 26, 2015, 9:34 am - IP Logged

"There will be months that will have more doubles and ruin your day. I tested 4 months in Florida, July was the only month that was a disaster, the rest were profitable."

Unfortunately, the odds will catch up with you in the end...

Lets look at the averages over 100 games:

Play: 100 games cost 660 x $100 = $66,000

Doubles: 27 games (on average)

Results with low digit higher than 4: 12% (12 games in this case)

So, on average, you would win 100-27-12=61 of your 100 games

Cost to play: $66,000

Win: $54,900

Net: -$11,100.

To make this system break-even you would have to correctly predict about half of the losing games (doubles and results of 567 and higher) and not play on those days.

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

New Mexico United States Member #86099 January 29, 2010 11116 Posts Offline

Posted: October 26, 2015, 12:33 pm - IP Logged

Quote: Originally posted by amber123 on October 25, 2015

The numbers 0 through 4 as the lowest number will show most often in any State's Pick-3 Game winning numbers. As long as the number 0,1,2,3, or 4 is the lowest digit and no doubles, you win. Just take a look at your State's last 30 days mid and eve winners.

Do you see what I see? This is just the current pattern, always watch out for a new pattern to emerge, that's the key.

After two zeros show in a row, a one appears. Tonight's Florida hit was 781. See the 1 in 781? The number 1 was the lowest digit as I would have predicted.

I just looked at FL mid and saw alot of high digits 5,6,7,8,9 and perhaps a program to track front pair and back pair sums which could alert to when to play high low digits. Percentages are fine but the betting process eliminates the certainty of what percentage will hit.

I'm not understanding your process of your example.

United States Member #164727 March 12, 2015 2509 Posts Offline

Posted: October 26, 2015, 1:10 pm - IP Logged

Quote: Originally posted by lakerben on October 26, 2015

I just looked at FL mid and saw alot of high digits 5,6,7,8,9 and perhaps a program to track front pair and back pair sums which could alert to when to play high low digits. Percentages are fine but the betting process eliminates the certainty of what percentage will hit.

I'm not understanding your process of your example.

Example

456

239

710

238

444

934

Would the order be:

456239017238444349 ?

The 0123456789 could be analyzed as

1=9

2=8

3=7

4=6

5=5

6=4

7=3

8=2

9=1

456-lowest is 4

239- lowest is 2

710- lowest is 0

238- lowest is 2

444- excluded

934- lowest is 3

Remember, we're only looking at lowest digit in each combination, doubles and triples excluded.

So the example numbers above would read, 4-2-0-2-3

United States Member #1987 August 5, 2003 8968 Posts Offline

Posted: October 26, 2015, 1:24 pm - IP Logged

Amber123, this is a nice spin on looking at the lowest digit. The thread in my signature The One Hundred Twenty Combinations Strategy,deals with the lowest digit as well.

United States Member #164727 March 12, 2015 2509 Posts Offline

Posted: October 26, 2015, 1:51 pm - IP Logged

Quote: Originally posted by Tialuvslotto on October 26, 2015

"There will be months that will have more doubles and ruin your day. I tested 4 months in Florida, July was the only month that was a disaster, the rest were profitable."

Unfortunately, the odds will catch up with you in the end...

Lets look at the averages over 100 games:

Play: 100 games cost 660 x $100 = $66,000

Doubles: 27 games (on average)

Results with low digit higher than 4: 12% (12 games in this case)

So, on average, you would win 100-27-12=61 of your 100 games

Cost to play: $66,000

Win: $54,900

Net: -$11,100.

To make this system break-even you would have to correctly predict about half of the losing games (doubles and results of 567 and higher) and not play on those days.

How do you come up with 12% as the lowest number above 4?

I get about 4.3%.

Looking back at Florida's p-3 from January, mid and eve, to Oct. 25, this is what tally I got. That's 298 days

Oct. 1

Sept. 0

Aug. 1

Jul. 3

Jun. 0

May. 3

Apr. 7

Mar. 2

Feb. 2

Jan. 4

Total: 26

Say about 300 days, or 600 draws.

So only 26 numbers above 4 out of 600 draws. That's more like 4.3% of the time.

27% of 600 -162 doubles lost=$17,820 lost

$4.3% of 600= 26 numbers that are above 4=$2,860 lost

So out of 600 draws I lost 162 to doubles and 26 to numbers above 4= 188 times=$20,680

600 X 660 =396,000-cost _remember we're playing all six ways per number, per draw.