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# If you can pick one number you can win P3

Topic closed. 64 replies. Last post 13 years ago by Clipper.

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Dump Water Florida
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 Posted: April 27, 2004, 3:32 am - IP Logged

There is a Pick-3 system being sold all over the web and on ebay where if you can correctly pick one of the three Pick-3 digits they guarantee you can win Pick-3.  Of course it's just the digit you picked along side the remaining nine digits in all their possible pairings.  Lotto-Logix gives that part of the system away free here: http://www.lotto-logix.com/txthouse/lottodojo2.html

The trouble with the system is you have to get the single digit correct almost every time or you are guaranteed to lose.

What I'd like to know from anyone who has seen one of these systems is what the sellers recommed for picking the one digit that must be correct?  I wrote to one system seller and they claimmed a 70% success rate with no explination.

What's the system(s) for picking the one digit?  Anyone?  Thanks. BobP

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 Posted: April 27, 2004, 1:43 pm - IP Logged

I don't know bobp, but that system is risky. I am aware of it by once discovering it when i was analyzing the game. Basically you figure out which 1 digit will likely be drawn. That's all u need. Play all the combinations w/ that 1 digit. It comes out to be 36 all different combinations boxed (251 straight). So basically, it's like having a 1 in 10 chance of winning (for the drawings that doubles/ triples don't hit). It's risky. \$36 to get a 1 in 10 chance + 1 in 3 chance of automatically losing when doubles/ triples hit (boxed play). Just sharing the info that i know. I personally woulnd't use that method of playing. Even if you're good at avoiding the days when double/ triples hit, 1 in ten alone is a risky figure. \$36 to win \$80-\$85 (in most states-boxed play) w/ less than a 1 in 10 chance. I suppose this would be a better simple system to use 4 people who use qwick pick/random/lucky numbers who play 4 fun not expecting to win much. If i were able to predict 1 digit correctly in 8 or 9 times out of ten drawings then i would use the system (it would still be profitably even if the doubles/triples were to hit).

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 Posted: April 27, 2004, 1:52 pm - IP Logged

Whoops, sorry bobp. I waystalkin bout a different system fron the 1 u were. I just checked out the site u posted. After actually reading through that site, i will get back to again.

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 Posted: April 27, 2004, 2:01 pm - IP Logged

Ok bobp, i read through that site. It actually is the same system that i was referring to. Only difference is that Robert Perkins (is that u by the way?) included doubles and the triple for the 1 key digit chosen on top of the other remaining combos. Do the math of probablity to determine which system is better. If u're good at avoiding double/triple hitting days, try the one i mentioned. If u like to have more winning days, try the one from that site.

"Use the odds against itself"

Dump Water Florida
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 Posted: April 27, 2004, 4:16 pm - IP Logged

You can buy the system for \$29.99 or there are eight hours remaining to buy the entire web site system selling business on ebay for \$99.99 which would make good sense if you couldn't buy the system for \$6.95 elsewhere on ebay.

http://cgi.ebay.com/ws/eBayISAPI.dll?ViewItem&category=46687&item=3811281951&rd=1

Don't mention it. ;-) BobP

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 Posted: April 28, 2004, 10:02 pm - IP Logged

BobP = perhaps I can shed a little light on this because it is something that I came across 10 years ago when I first started tracking digits.

The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down.

Dump Water Florida
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 Posted: April 29, 2004, 1:51 am - IP Logged
Quote: Originally posted by Clipper on April 28, 2004

BobP = perhaps I can shed a little light on this because it is something that I came across 10 years ago when I first started tracking digits.

The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down.

Hmmm, it takes 100 combinations to Straight play a digit positionally (in one position) against all the others in their various possible paired positions.  Is that what you meant to say?

There are 36 possible all different combinations with a specific digit in any position.  Three of these collections with the single digit located in each of the three postions would be 108 combinations and still be only box plays.

There are 55 possible  combinations with a specific digit in any position if we include triples, doubles and all different and still only box plays excluding the triple which can only be played straight.  I'm too tired to figure how many combinations this makes moving the selected digit around as doing so wouldn't help anything unless the goal is to have multiple box wins.

For Straight play there are 271 combinations with a selected digit in all three possible positions and the remaining digits in all of theirs.  Obviously ten times 271 is more then 1,000 there is redundency because the same formed combination can be made in more then one set.

Anyhow, none of this helps select the digit to play.  Even if we had 80% draws with one or more repeats, the losses would far exceed the wins.

The system is 100% fool proof once the specific winning digit is selected, if it wins the system must produce a winner when all the combinations are played. What we need is a way to select that winning digit almost every time.

BobP

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 Posted: April 29, 2004, 2:57 am - IP Logged

Exactly Bob.  Clipper, r u sure u know that u're talkin bout. Bobp knows what he's talkin bout.

(u're quote clipper)--->"The 1 digit idea is simply this.....there are exactly 100 combinations with any specific digit in any specific position.  There is also a 60% repeat rate for a digit playing from a previous game.  That's where you look first for the "1" digit to play.  Then figure out what position it will play in, use other criteria to eliminate and reduce the 100 possible combinations down." <- (your statement clipper)

Exactly 100 combinations? Did u forget to calculate the combinations by abiding with the law of thirds. Didn't look like it. You're way off.  Doesn't matter if u're talkin bout boxed combo's, straight, triples, doubles, etc. 100 combinations is incorrect no matter what u apply it to.

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 Posted: April 29, 2004, 12:43 pm - IP Logged

QWEST =Yes...I know what Im talking about.  There are exactly 100 EXACT combinations with any specific digit (0-1-2-3-4-5-6-7-8-9) in any specific position (1st-2nd-3rd).  This means there are 100 EXACT combinations with the 0 in the 1st, with the 1 in the 1st, with the 2 in the 1st, 3, 4, 5, 6, 7, 8 and 9 in the 1st position.

Just as there are 100 EXACT combinations with a digit in the 1st position there are 100 EXACT combinations with each digit in the 2nd position and each digit in the 3rd position.  Each group of 100 contains 3 different digits, Doubles and Triples.

This system is not taking "the one digit" and playing all possible combinations that have "the one digit" but determing which group of EXACTS to use.  Again, the repeat rate generally runs about 60% and that is where you look for "the one" digit to work with.

QWEST = now re-read what I said.....100 EXACT combinations with any specific number in any specific position.

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 Posted: April 29, 2004, 12:51 pm - IP Logged

Bobp=I hope I've answered your question as well?  When I first started tracking the Pick 3 I analyzed the 1000 EXACT combinations.

When I tell people they need to have a thorough understanding of the 1000 combinations this is what I am speaking about.  If one has a thorough understanding of the numbers they will realize that each of the 10 digits will appear in 100 EXACT combinations in the 1st, 2nd and 3rd position.  If a Double is involved in will not only be in whatever position you are anticipating, it will also be one of the other positions.  That is immaterial because you are concentrating on the "position' of choice.

Dump Water Florida
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 Posted: April 29, 2004, 4:33 pm - IP Logged

Clipper:

Maybe there are 100 combinations with a specific digit in each of the three positions, but isn't that simply redundent boxing as the remaining two digits aren't fixed?  Sorry, I can't get my head around what you're saying, is an example possible?  Visit here, using the 0 as an example where is the system going wrong? Still need ideas how to pick the magical digit. Thanks. BobP

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 Posted: April 29, 2004, 4:46 pm - IP Logged

Picking the "magical number" is looking at the most recent game that played in anticipation of a Repeat Digit to go forward to the next game.  Usually it is a 1 in 3 shot unless you are coming off a Doubles game which gives you a 50/50 shot at the "magical  number".

The "redundant boxing" is simply shooting for the EXACT combination to play whereby you rule out the "magical number" from playing in any other position.  This is not for "boxed" game playing.

There are considerations you can make to reduce those 100 exacts down the about 28 or 30 EXACTS and it doesnt matter what the other two digits are.

Dump Water Florida
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 Posted: April 30, 2004, 1:42 am - IP Logged
Quote: Originally posted by Clipper on April 29, 2004

Picking the "magical number" is looking at the most recent game that played in anticipation of a Repeat Digit to go forward to the next game.  Usually it is a 1 in 3 shot unless you are coming off a Doubles game which gives you a 50/50 shot at the "magical  number".

The "redundant boxing" is simply shooting for the EXACT combination to play whereby you rule out the "magical number" from playing in any other position.  This is not for "boxed" game playing.

There are considerations you can make to reduce those 100 exacts down the about 28 or 30 EXACTS and it doesnt matter what the other two digits are.

We're talking about a guaranteed win when one digit is correctly predicted.

There are only two kinds of three digit plays, Box and Straight.  If "Exact" has meaning in Pick-3 I'd take it to mean Straight.  It takes 271 numbers to cover all positions a specific digit can be in with the remaining nine digits in all their possible positions for a guaranteed Straight win when one correctly selects one digit.  Here are the numbers to play if the zero is your chosen digit:

When your selected number is "0" Zero play . . .

A-A-A
0-0-0

A-A-B
0-0-1 0-0-2 0-0-3 0-0-4 0-0-5 0-0-6 0-0-7 0-0-8 0-0-9
A-B-A
0-1-0 0-2-0 0-3-0 0-4-0 0-5-0 0-6-0 0-7-0 0-8-0 0-9-0
B-A-A
1-0-0 2-0-0 3-0-0 4-0-0 5-0-0 6-0-0 7-0-0 8-0-0 9-0-0

A-B-B
0-1-1 0-2-2 0-3-3 0-4-4 0-5-5 0-6-6 0-7-7 0-8-8 0-9-9
B-A-B
1-0-1 2-0-2 3-0-3 4-0-4 5-0-5 6-0-6 7-0-7 8-0-8 9-0-9
B-B-A
1-1-0 2-2-0 3-3-0 4-4-0 5-5-0 6-6-0 7-7-0 8-8-0 9-9-0

A-B-C
0-1-2 0-1-3 0-1-4 0-1-5 0-1-6 0-1-7 0-1-8 0-1-9
0-2-3 0-2-4 0-2-5 0-2-6 0-2-7 0-2-8 0-2-9
0-3-4 0-3-5 0-3-6 0-3-7 0-3-8 0-3-9
0-4-5 0-4-6 0-4-7 0-4-8 0-4-9
0-5-6 0-5-7 0-5-8 0-5-9
0-6-7 0-6-8 0-6-9
0-7-8 0-7-9
0-8-9

A-C-B
0-2-1 0-3-1 0-4-1 0-5-1 0-6-1 0-7-1 0-8-1 0-9-1
0-3-2 0-4-2 0-5-2 0-6-2 0-7-2 0-8-2 0-9-2
0-4-3 0-5-3 0-6-3 0-7-3 0-8-3 0-9-3
0-5-4 0-6-4 0-7-4 0-8-4 0-9-4
0-6-5 0-7-5 0-8-5 0-9-5
0-7-6 0-8-6 0-9-6
0-8-7 0-9-7
0-9-8

B-A-C
1-0-2 1-0-3 1-0-4 1-0-5 1-0-6 1-0-7 1-0-8 1-0-9
2-0-3 2-0-4 2-0-5 2-0-6 2-0-7 2-0-8 2-0-9
3-0-4 3-0-5 3-0-6 3-0-7 3-0-8 3-0-9
4-0-5 4-0-6 4-0-7 4-0-8 4-0-9
5-0-6 5-0-7 5-0-8 5-0-9
6-0-7 6-0-8 6-0-9
7-0-8 7-0-9
8-0-9

C-A-B
2-0-1 3-0-1 4-0-1 5-0-1 6-0-1 7-0-1 8-0-1 9-0-1
3-0-2 4-0-2 5-0-2 6-0-2 7-0-2 8-0-2 9-0-2
4-0-3 5-0-3 6-0-3 7-0-3 8-0-3 9-0-3
5-0-4 6-0-4 7-0-4 8-0-4 9-0-4
6-0-5 7-0-5 8-0-5 9-0-5
7-0-6 8-0-6 9-0-6
8-0-7 9-0-7
9-0-8

B-C-A
1-2-0 1-3-0 1-4-0 1-5-0 1-6-0 1-7-0 1-8-0 1-9-0
2-3-0 2-4-0 2-5-0 2-6-0 2-7-0 2-8-0 2-9-0
3-4-0 3-5-0 3-6-0 3-7-0 3-8-0 3-9-0
4-5-0 4-6-0 4-7-0 4-8-0 4-9-0
5-6-0 5-7-0 5-8-0 5-9-0
6-7-0 6-8-0 6-9-0
7-8-0 7-9-0
8-9-0

C-B-A
2-1-0 3-1-0 4-1-0 5-1-0 6-1-0 7-1-0 8-1-0 9-1-0
3-2-0 4-2-0 5-2-0 6-2-0 7-2-0 8-2-0 9-2-0
4-3-0 5-3-0 6-3-0 7-3-0 8-3-0 9-3-0
5-4-0 6-4-0 7-4-0 8-4-0 9-4-0
6-5-0 7-5-0 8-5-0 9-5-0
7-6-0 8-6-0 9-6-0
8-7-0 9-7-0
9-8-0

If there is a way to reduce these 271 lines to 100 without giving up the GUARANTEE of a STRAIGHT WIN I'd like to see it done. BobP

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 Posted: April 30, 2004, 9:59 am - IP Logged

Exact does mean Straight.....And ...if you do get the "magical number" AND the position it will be in then you ARE guaranteed to win with 100 possible combinations to play.  There are ways to reduce that 100 down to even less by applying the 12 Facts.

Dump Water Florida
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 Posted: April 30, 2004, 1:25 pm - IP Logged
Quote: Originally posted by Clipper on April 30, 2004

Exact does mean Straight.....And ...if you do get the "magical number" AND the position it will be in then you ARE guaranteed to win with 100 possible combinations to play.  There are ways to reduce that 100 down to even less by applying the 12 Facts.

Right you are, isn't that what I said eight posts back?  Guess I was confused by your way of saying it would take 300 numbers to play all three positions.

Any ideas for selecting the magical number besides picking one of three or two from the prior draw?  I'd like to make a profit rather then lose two times out of three or worse if I guess wrong every time.

One of the reports selling this system said to use the coldest digit from the last 60 days, just doesn't sound right to me.

BobP

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