United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: July 7, 2012, 10:02 pm - IP Logged

Can RJ (or anyone) please tell me how many groups of 28 numbers there are in the MM game, and which group (or groups) have the highest winning percentages??

mid-Ohio United States Member #9 March 24, 2001 19817 Posts Offline

Posted: July 8, 2012, 12:50 am - IP Logged

Quote: Originally posted by Ronnie316 on July 7, 2012

Mathematically there should only be 38.4 distinct groups (of 28).........

but I cant find a way to create the groups.

MegaMillions has 56 numbers. If you group those numbers in groups of 28 starting with 1-28, 2-29, 3-30 and etc...., you would have 28 groups when you reach 29-56. If you go back and change the last number in the first group of 1-28 to 29, 30, 31 and etc...to 56, you would have an addition 27 groups which makes 55 distinct groups of 28 which is a lot more than 38.4. Doing that to just the 28 groups you started out with will give you more than 400 groups of 28. You are just getting started and you haven't included the groups of 28 odd or even numbers yet.

According to a Keno calculator I saw on the web, there are more than 7 trillions distant groups of 28 numbers in 56 numbers. I don't know if that's right or not but I suspect it's closer to being right than 38.4.

* you don't need to buy more tickets, just buy a winning ticket *

Kentucky United States Member #32652 February 14, 2006 7297 Posts Offline

Posted: July 8, 2012, 12:51 am - IP Logged

Quote: Originally posted by Ronnie316 on July 7, 2012

Can RJ (or anyone) please tell me how many groups of 28 numbers there are in the MM game, and which group (or groups) have the highest winning percentages??

Considering we're using 56 numbers, the number of 28 number groups is astronomical. It starts with almost 4 million groups of five numbers and each group uses 51 numbers to create a six number group. There are 7,575,968,400 nine number groups and then multiple that by 47 to get the number of ten number groups and that times 46 to get the number eleven number groups and so on. Continue to multiple until you get to 29.

The number is the same as the number of combos in a 28/56 lotto game. Another way is to multiply 56x55x54x53x52x51x50x49x48x47x46x45x44x43x42x41x40x39x38x37x36x35x34x33x32x31x30x29.

Don't know any shortcuts but when you find that total, divide it by 30,488,834,461,171,386,050,150,400,000 (30 Octillion?) to get the total number of 28 number groups.

By the way, all five PB numbers and the bonus number were odd tonight.

MegaMillions has 56 numbers. If you group those numbers in groups of 28 starting with 1-28, 2-29, 3-30 and etc...., you would have 28 groups when you reach 29-56. If you go back and change the last number in the first group of 1-28 to 29, 30, 31 and etc...to 56, you would have an addition 27 groups which makes 55 distinct groups of 28 which is a lot more than 38.4. Doing that to just the 28 groups you started out with will give you more than 400 groups of 28. You are just getting started and you haven't included the groups of 28 odd or even numbers yet.

According to a Keno calculator I saw on the web, there are more than 7 trillions distant groups of 28 numbers in 56 numbers. I don't know if that's right or not but I suspect it's closer to being right than 38.4.

It's similar to the math question, "if you save $1 on the first day of the month, $2 on the second day, $4 on the third, $8 on the fourth day, doubling each day, how much will you have by the end of the month"?

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: July 8, 2012, 1:03 am - IP Logged

Quote: Originally posted by Stack47 on July 8, 2012

Considering we're using 56 numbers, the number of 28 number groups is astronomical. It starts with almost 4 million groups of five numbers and each group uses 51 numbers to create a six number group. There are 7,575,968,400 nine number groups and then multiple that by 47 to get the number of ten number groups and that times 46 to get the number eleven number groups and so on. Continue to multiple until you get to 29.

The number is the same as the number of combos in a 28/56 lotto game. Another way is to multiply 56x55x54x53x52x51x50x49x48x47x46x45x44x43x42x41x40x39x38x37x36x35x34x33x32x31x30x29.

Don't know any shortcuts but when you find that total, divide it by 30,488,834,461,171,386,050,150,400,000 (30 Octillion?) to get the total number of 28 number groups.

By the way, all five PB numbers and the bonus number were odd tonight.

Thanks Stack, I just cant bring myself to be active in predicting PB as the cost is double to actually play. I do play 2 PB lines and 4 MM lines on every draw and pay the same for each.

mid-Ohio United States Member #9 March 24, 2001 19817 Posts Offline

Posted: July 8, 2012, 1:06 am - IP Logged

Quote: Originally posted by Stack47 on July 8, 2012

Considering we're using 56 numbers, the number of 28 number groups is astronomical. It starts with almost 4 million groups of five numbers and each group uses 51 numbers to create a six number group. There are 7,575,968,400 nine number groups and then multiple that by 47 to get the number of ten number groups and that times 46 to get the number eleven number groups and so on. Continue to multiple until you get to 29.

The number is the same as the number of combos in a 28/56 lotto game. Another way is to multiply 56x55x54x53x52x51x50x49x48x47x46x45x44x43x42x41x40x39x38x37x36x35x34x33x32x31x30x29.

Don't know any shortcuts but when you find that total, divide it by 30,488,834,461,171,386,050,150,400,000 (30 Octillion?) to get the total number of 28 number groups.

By the way, all five PB numbers and the bonus number were odd tonight.

I suspect the Keno calculation is correct when you plug in 56 numbers to draw from, 28 numbers drawn and 28 played when it comes out 7 trillions or the next value 3 places to the left. It takes about 20 seconds to check the last 734 MM drawings with one group of 28 numbers using a program I wrote using GWBasic and complied with a QB compiler, I wouldn't even attempt to do it with 7 trillion groups.

* you don't need to buy more tickets, just buy a winning ticket *

MegaMillions has 56 numbers. If you group those numbers in groups of 28 starting with 1-28, 2-29, 3-30 and etc...., you would have 28 groups when you reach 29-56. If you go back and change the last number in the first group of 1-28 to 29, 30, 31 and etc...to 56, you would have an addition 27 groups which makes 55 distinct groups of 28 which is a lot more than 38.4. Doing that to just the 28 groups you started out with will give you more than 400 groups of 28. You are just getting started and you haven't included the groups of 28 odd or even numbers yet.

According to a Keno calculator I saw on the web, there are more than 7 trillions distant groups of 28 numbers in 56 numbers. I don't know if that's right or not but I suspect it's closer to being right than 38.4.

LOL. Thanks RJ, I saw the same Keno numbers and it just confused me. I'm not trying to get all 28 numbers right obviously.

If 28 numbers covers 98,820 of the 3.8 million total combinations there should be 38.4 groups in there somewhere that cover all the possible combinations.... There has to be... lol. lol.

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: July 8, 2012, 1:18 am - IP Logged

Quote: Originally posted by Stack47 on July 8, 2012

It's similar to the math question, "if you save $1 on the first day of the month, $2 on the second day, $4 on the third, $8 on the fourth day, doubling each day, how much will you have by the end of the month"?

I know that one Stack. I dream of hitting the craps table with $20. and walking away with $20,000. after 10 passes. Too bad things almost never turn out the way we expect them to.

mid-Ohio United States Member #9 March 24, 2001 19817 Posts Offline

Posted: July 8, 2012, 1:27 am - IP Logged

Quote: Originally posted by Ronnie316 on July 8, 2012

LOL. Thanks RJ, I saw the same Keno numbers and it just confused me. I'm not trying to get all 28 numbers right obviously.

If 28 numbers covers 98,820 of the 3.8 million total combinations there should be 38.4 groups in there somewhere that cover all the possible combinations.... There has to be... lol. lol.

If 28 numbers covers 98,820 of the 3.8 million total combinations there should be 38.4 groups in there somewhere that cover all the possible combinations.... There has to be...

That's like saying 5 numbers must have 1.25 combinations of fours in it since 5/4=1.25 when we know there are 5 combinations of fours in five numbers.

* you don't need to buy more tickets, just buy a winning ticket *

If 28 numbers covers 98,820 of the 3.8 million total combinations there should be 38.4 groups in there somewhere that cover all the possible combinations.... There has to be...

That's like saying 5 numbers must have 1.25 combinations of fours in it since 5/4=1.25 when we know there are 5 combinations of fours in five numbers.

No, because 3.8 million is a distinct and limited number of lines. And that number divided by 38.4 = 98,820.

So there may not be a way to go 1-28.... 2-29.... and so on, But a full 56 number wheel could be divided into 38.4 parts easily enough.

Whiskey Island United States Member #90216 April 24, 2010 12729 Posts Offline

Posted: July 8, 2012, 2:13 am - IP Logged

It's not the number combinations that has better odds . The System/Method analyzing the the right Data from Previous draws is the only way to WIN . But , you must use the right Data Regression Analysis to generate the number string it could be the last 5 draws or 500 draws you will need .

United States Member #124493 March 14, 2012 7023 Posts Offline

Posted: July 8, 2012, 3:03 am - IP Logged

Quote: Originally posted by CajunWin4 on July 8, 2012

It's not the number combinations that has better odds . The System/Method analyzing the the right Data from Previous draws is the only way to WIN . But , you must use the right Data Regression Analysis to generate the number string it could be the last 5 draws or 500 draws you will need .

D R A does have valid uses and improves chance as you have shown CW4...but its more about the right skip mix... which is always in flux...thats is what really improves the odds...and allows consistent winning...