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# MO Pick-6 predictions

Topic closed. 282 replies. Last post 2 years ago by Hans.

 Page 18 of 19
Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 21, 2014, 8:55 pm - IP Logged

MO Pick6 Sat, Nov 22, 2014 Prediction

9 numbers

10 20 08 21 44 41 40 28 33

16 tickets=8 dollars

10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44
20 40 28 21 41 44
10 20 40 08 21 41
10 20 40 08 28 44
10 20 40 08 28 21
10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44

If the next drawing will not have a match3,I will play those lines until they hit.

cumulative prize ratio:(89+2.5)/(22.5+9+9)=225.93%

3 drawings have been played.I will not post prediction until the cumculative prize ratio drops below 100%.

Playing each drawing 16 tickets=8 dollars,I still have 5 drawings to go to try some match4,or match5 to improve the prize ratio.

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Horwood NL
Member #70613
February 6, 2009
297 Posts
Offline
 Posted: November 21, 2014, 9:45 pm - IP Logged

I can see that, but how did you determine that you should use

07 01 08  12 10 04

I don't see a relationship to the converted results. You say they are the 6 last digits prediction of the converted results.

12 & 10 can't be a last digit.

GW

United States
Member #59354
March 13, 2008
3986 Posts
Offline
 Posted: November 22, 2014, 2:56 am - IP Logged

Hans

The sets I posted here are not generated using a wheel.  The predictor never even looks at a single number

past or present.  The predictor first calculates a seed value based on so many previous lines lexicographical

index values which are averaged together.  Next the program uses a algorithm which tries to calculate a series

of steps needed so that one of these values converted will match a 5 of 6.  The program's only purpose is to

hit a 5 of 6, all other prize matches are a not intended and are just a by-product of the algorithm.  The program

hit 1ea 5of6 in 90 games and the overall odds of doing this is 1 in 30,961 so from that perspective it performed

as designed.  My hopes were that it would also show a profit.

Did you even read the the post where I explained in detail what the test was all about.   If the seed value is correct

then the program will match a 5of6 every time.  The seed value is not limited to just one value as there are 228 that

will work for any game.  I plan to do more work on the method used to calculate the seed value that is used in the first

step which is the only thing needed to make the program a success.

The program generates lexicographical index values which are converted into number sets in the last stage.  As I said

many post back I have no control over the numbers that make up the actual lines and no number is excluded.  This has

been proven to be the best betting strategy for any lottery game.

Totally different method being used here.  The only time I see actual numbers is when I feel out the bet slips.  The systems

I actual play don't require analyzing numbers at all.  They build lines based on the mathematical probabilities gotten from

analysis of the entire matrix.  Such as the number of digits needed to maximize the lines overall chances of showing in the

next draw.

If the history of the game can be analyzed to give up the numbers that will show in the next draw then we would have no

lotteries.  Short term analysis will sometimes provide good results but after a while they all fail because they are built around

analysis taken from a few past games and the trends change.   This is why we see a few so called super systems that show

a few good hits only to fail later.  From what you have said of you methods I suspect this will be your downfall unless you

continually find short term trends within the data.  Nothing wrong with those methods but I don't use them.  Wheeling so many

numbers only works if one can select the correct numbers to wheel and the fewer numbers used, the fewer matches one will

trap.  My methods have made me enough that I will never drop into the red in my lifetime.  I average a 3 to one return over

the course of a year.  I do have failures but overall I have shown a profit of at least 3 to 1 for over 10 years in a row.  My DMP

software gives me many different options to generate my lines to play but they all work off the same principles and I have

stuck to these like glue for over 20 years now.  This test has nothing to do with my actual play but I will keep working on it

until I am convinced it will never work just like the all the other ideas I test.

RL

P.S.  The only value one needs to know when making a bet is the overall odds for winning a prize.  The overall odds

for my 6-44 are 1 in 39.32751 if counting 3of6 and 1 in 655.1932 for a cash prize.

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

United States
Member #59354
March 13, 2008
3986 Posts
Offline
 Posted: November 22, 2014, 3:16 am - IP Logged

MO Pick6 Sat, Nov 22, 2014 Prediction

9 numbers

10 20 08 21 44 41 40 28 33

16 tickets=8 dollars

10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44
20 40 28 21 41 44
10 20 40 08 21 41
10 20 40 08 28 44
10 20 40 08 28 21
10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44

If the next drawing will not have a match3,I will play those lines until they hit.

cumulative prize ratio:(89+2.5)/(22.5+9+9)=225.93%

3 drawings have been played.I will not post prediction until the cumculative prize ratio drops below 100%.

Playing each drawing 16 tickets=8 dollars,I still have 5 drawings to go to try some match4,or match5 to improve the prize ratio.

Hans

Hans

You again played 3ea digit zeros in almost every line.  If digit zero does not show at all then none of

your lines will have much chance at winning anything.  The three numbers can be broken down to cover

any 2 in 3 lines.

Example

10-20

10-40

20-40

Each of these could be played 6 times in 18 lines.   My analysis shows that digit zero will show fewer than 2

in the next draw.  Just my humble analysis.  Your total digit count is 4 -> 0-1-4-8 and many of the sets only

have 3ea base digits.  While this won't keep you from hitting a low level prize the probability for hitting a

prize better than a 3of6 is almost null.

Here are your numbers wheeled using the 3if3of6in9 built using CM

Randomized = 28 08 10 33 41 20 40 21 44

08 10 20 28 33 41
08 10 21 28 40 44
20 21 33 40 41 44
08 21 28 33 40 41
10 20 28 33 40 44
08 10 20 21 41 44
08 10 28 33 41 44
08 10 20 21 28 33
08 10 20 28 40 41

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

United States
Member #59354
March 13, 2008
3986 Posts
Offline
 Posted: November 22, 2014, 3:55 am - IP Logged

Hans

Here is another tip for what it's worth.  Digit placement for digit zero is best played as the 5th numbers

second digit.  This placement is almost 50,000 lines better than the second best position as the 3rd

number's second digit.   This is not a sure thing but it can make a difference overall.  There are 758,826

lines in the matrix where the 5th number second digit = 0.  The overall is 1 in 7059052/758826=8.30

and is out 13 games.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 7:13 am - IP Logged

I can see that, but how did you determine that you should use

07 01 08  12 10 04

I don't see a relationship to the converted results. You say they are the 6 last digits prediction of the converted results.

12 & 10 can't be a last digit.

GW

I choose one digit or number from 01 and 11 for digit 1,and from 02 and 12 for digit 2.

It's like a 6/12 lottery.

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 7:14 am - IP Logged

Hans

Here is another tip for what it's worth.  Digit placement for digit zero is best played as the 5th numbers

second digit.  This placement is almost 50,000 lines better than the second best position as the 3rd

number's second digit.   This is not a sure thing but it can make a difference overall.  There are 758,826

lines in the matrix where the 5th number second digit = 0.  The overall is 1 in 7059052/758826=8.30

and is out 13 games.

RL

05 was predicted in my prediction steps,so if I were to replace digit 0 numbers,05 is the best choice.

But I have no idea which number shall be replaced.There are three numbers in my prediction with digit 0.

any clue?

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 7:16 am - IP Logged

Hans

You again played 3ea digit zeros in almost every line.  If digit zero does not show at all then none of

your lines will have much chance at winning anything.  The three numbers can be broken down to cover

any 2 in 3 lines.

Example

10-20

10-40

20-40

Each of these could be played 6 times in 18 lines.   My analysis shows that digit zero will show fewer than 2

in the next draw.  Just my humble analysis.  Your total digit count is 4 -> 0-1-4-8 and many of the sets only

have 3ea base digits.  While this won't keep you from hitting a low level prize the probability for hitting a

prize better than a 3of6 is almost null.

Here are your numbers wheeled using the 3if3of6in9 built using CM

Randomized = 28 08 10 33 41 20 40 21 44

08 10 20 28 33 41
08 10 21 28 40 44
20 21 33 40 41 44
08 21 28 33 40 41
10 20 28 33 40 44
08 10 20 21 41 44
08 10 28 33 41 44
08 10 20 21 28 33
08 10 20 28 40 41

RL

Thanks for your 9 line wheel.Here is what I suggested for 9 numbers wheel

9 line wheel for 9 numbers

01 02 03 05 06 07
01 02 03 05 06 08
01 02 03 04 06 07
01 02 03 05 06 07
01 03 04 05 08 09
01 02 04 05 06 07
01 03 04 05 06 08
01 02 03 07 08 09
01 02 03 06 07 09

16 line wheel for 9 numbers

01 02 03 05 06 07
01 02 03 05 06 08
01 02 03 04 06 07
01 02 03 05 06 07
01 03 04 05 08 09
01 02 04 05 06 07
01 03 04 05 06 08
01 02 03 07 08 09
01 02 03 06 07 09
01 03 04 05 07 09
02 04 05 06 07 08
01 02 03 04 06 07
02 03 04 05 06 09
01 02 03 05 07 08
01 02 03 04 07 08
01 02 06 07 08 09

If you could post results after randomizing process,and compare to your 9 line and 16 line wheel,we could check after the drawing to see which one has a higher prize ratio.

or simply give a random set of 6 in 9 ,and test to see which one has a better chance of a match5 or jackpot as you mentioned your goal is for match5  instead of small match3 and match4 wins.

let's take an example.

I also noticed you changed my 9 number order

Randomized = 28 08 10 33 41 20 40 21 44

That would make a great difference on the prize ratio.

worst condition for 3 in 9 :If 40 21 44 were drawn among 9,there would be only 2 match3 in 9 tickets.prize ratio:22.22%

best condition for 3 in 9,if 28 08 10 were drawn,5 match3 in 9 tickets,the prize ratio is 55.56%

prize ratio:1/4.5=22.22%

08 10 20 28 33 41
08 10 21 28 40 44
20 21 33 40 41 44
08 21 28 33 40 41
10 20 28 33 40 44
08 10 20 21 41 44
08 10 28 33 41 44
08 10 20 21 28 33
08 10 20 28 40 41

Here is my results

9 numbers

10 20 08 21 44 41 40 28 33

16 tickets=8 dollars

10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44
20 40 28 21 41 44
10 20 40 08 21 41
10 20 40 08 28 44
10 20 40 08 28 21
10 20 40 08 41 44
10 20 08 28 41 44
10 20 40 08 28 21
10 20 40 08 28 41
10 20 40 21 41 44
10 08 28 21 41 44

worst condition for 3 in 9 :If 40 28 33  were drawn among 9,no win,worse than yours.

best condition for 3 in 9,if 10 20 08 were drawn,11 match3 in 9 tickets,the prize ratio is 5.5/8=68.75%,better than yours.

we have different approach to the prize ratio for small wins,which you believed not much meaning as the goal is for match5 or jackpot.

But let's check  which one has a better chance for match5 or jackpot.

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 7:37 am - IP Logged

I can see that, but how did you determine that you should use

07 01 08  12 10 04

I don't see a relationship to the converted results. You say they are the 6 last digits prediction of the converted results.

12 & 10 can't be a last digit.

GW

I can see that, but how did you determine that you should use

I predict using past 10 drawing converted results the 6 digit from 01 to 12.

I usually choose one number from 01 and 11,or from 02 and 12

so that turned 6/12 lottery to 6/10 lottery.

This part is what I am still improving

when 6 digits were correctly predicted,shall it have listed about 21 numbers with all 6 winning numbers from all numbers.

The next steps are choosing 9 numbers from 21 numbers abouts.This is the core part of my system and is what really matters.

Usually 9 numbers would have 3-4 winning numbers,as I have done for the first and last time under this thread,

but who knows when 9 numbers have 5 or 6 winning numbers?

That's the time to win big in my 16 tickets.

even if I don't have all 5 or 6 winning numbers,let's say  3-4 winning numbers,I can still win something than losing all by wheeling more than 9 numbers.

I do think prediction shall be reduced to a very limited pool,like 9-12 numbers,rather than more than 20 or 30 numbers.Because that is where filters are needed and involved,which is completely out of  control from human side.This time you are right and the next time you are wrong.

If we do need to use more numbers,I suggest using 16 numbers max.

The final wheeling part is still under test and discussion with RL.

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 8:25 am - IP Logged

Hans

The sets I posted here are not generated using a wheel.  The predictor never even looks at a single number

past or present.  The predictor first calculates a seed value based on so many previous lines lexicographical

index values which are averaged together.  Next the program uses a algorithm which tries to calculate a series

of steps needed so that one of these values converted will match a 5 of 6.  The program's only purpose is to

hit a 5 of 6, all other prize matches are a not intended and are just a by-product of the algorithm.  The program

hit 1ea 5of6 in 90 games and the overall odds of doing this is 1 in 30,961 so from that perspective it performed

as designed.  My hopes were that it would also show a profit.

Did you even read the the post where I explained in detail what the test was all about.   If the seed value is correct

then the program will match a 5of6 every time.  The seed value is not limited to just one value as there are 228 that

will work for any game.  I plan to do more work on the method used to calculate the seed value that is used in the first

step which is the only thing needed to make the program a success.

The program generates lexicographical index values which are converted into number sets in the last stage.  As I said

many post back I have no control over the numbers that make up the actual lines and no number is excluded.  This has

been proven to be the best betting strategy for any lottery game.

Totally different method being used here.  The only time I see actual numbers is when I feel out the bet slips.  The systems

I actual play don't require analyzing numbers at all.  They build lines based on the mathematical probabilities gotten from

analysis of the entire matrix.  Such as the number of digits needed to maximize the lines overall chances of showing in the

next draw.

If the history of the game can be analyzed to give up the numbers that will show in the next draw then we would have no

lotteries.  Short term analysis will sometimes provide good results but after a while they all fail because they are built around

analysis taken from a few past games and the trends change.   This is why we see a few so called super systems that show

a few good hits only to fail later.  From what you have said of you methods I suspect this will be your downfall unless you

continually find short term trends within the data.  Nothing wrong with those methods but I don't use them.  Wheeling so many

numbers only works if one can select the correct numbers to wheel and the fewer numbers used, the fewer matches one will

trap.  My methods have made me enough that I will never drop into the red in my lifetime.  I average a 3 to one return over

the course of a year.  I do have failures but overall I have shown a profit of at least 3 to 1 for over 10 years in a row.  My DMP

software gives me many different options to generate my lines to play but they all work off the same principles and I have

stuck to these like glue for over 20 years now.  This test has nothing to do with my actual play but I will keep working on it

until I am convinced it will never work just like the all the other ideas I test.

RL

P.S.  The only value one needs to know when making a bet is the overall odds for winning a prize.  The overall odds

for my 6-44 are 1 in 39.32751 if counting 3of6 and 1 in 655.1932 for a cash prize.

Hans

The sets I posted here are not generated using a wheel.  The predictor never even looks at a single number

past or present.  The predictor first calculates a seed value based on so many previous lines lexicographical

index values which are averaged together.  Next the program uses a algorithm which tries to calculate a series

of steps needed so that one of these values converted will match a 5 of 6.  The program's only purpose is to

hit a 5 of 6, all other prize matches are a not intended and are just a by-product of the algorithm.

This is about prize winning power.You can check a list of wheels using 9-53 numbers at lotto-logix website.The chance of different match is calculated already.

That pretty much saves your work.

BALANCED ECONOMY WHEEL

For 42 Numbers In 55 Combinations

Prize Winning Power

3 if 3 = 09.40% ... 4 if 4 = 00.74% ... 5 if 5 = 00.04%
3 if 4 = 33.54% ... 4 if 5 = 03.50% ... 5 if 6 = 00.23%
3 if 5 = 65.41% ... 4 if 6 = 09.92%
3 if 6 = 88.99%

5if5=00.04% and 5if6 is 00.23% by playing 42 numbers 55  combinations.

Even if you play 55 combinations for 1000 times,the chance of 5if5 is 40%,and by playing 100 times,the chance of 5if6 is 23%

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 9:01 am - IP Logged

BALANCED ECONOMY WHEEL

For 42 Numbers In 55 Combinations

Prize Winning Power

3 if 3 = 09.40% ... 4 if 4 = 00.74% ... 5 if 5 = 00.04%
3 if 4 = 33.54% ... 4 if 5 = 03.50% ... 5 if 6 = 00.23%
3 if 5 = 65.41% ... 4 if 6 = 09.92%
3 if 6 = 88.99%

5if5=00.04% and 5if6 is 00.23% by playing 42 numbers 55  combinations.

correction:Even if you play 55 combinations for 10000 times,the chance of 5if5 is 40%,and by playing 1000 times,the chance of 5if6 is 23%

Also refer to

` v k t m `
` 44,6,5,5    204785 `
` 204785 tickets for a guaranteed match5 paid out less than 1000 bucks. `
` from http://rbelic.home.xs4all.nl/imp.htm `

Hans

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

United States
Member #59354
March 13, 2008
3986 Posts
Offline
 Posted: November 22, 2014, 10:21 am - IP Logged

Hans

You wrote.

`204785 tickets for a guaranteed match5 paid out less than 1000 bucks. The total lines generated over the full test was less than 3,150.  The odds for a 5of6 hit in a  6-44 game are 1 in 30,961.  The predictor managed a 5of6 in  < 3150 so 30961/3150 = 9.8  times better than expected.  This is still not good enough to come out ahead.  3150/2=\$1575  so even with all other prizes combined it still lost money.  To come out ahead for this game the  predictor needs to hit a 5of6 around once in every 45 games.  I believe the predictor can be  coded do this without much work.  The more lines one plays the better the chances for a  JP level  prize.  35 lines can be played for less than \$20.00 per game or \$40.00 per week.  If the predictor  can be made to function at the one 5of6 for every 45 games played then I could play it for ever  without it ever costing me a penny.  The only mathematically sound way to increase our chances  of a JP level prize is to play more lines.  Winning once every 45 games would meet the break-even  level needed to play without any risk as all tickets will require no out of pocket expense.  The perfect system.RL`

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 10:33 am - IP Logged

Hans

You wrote.

`204785 tickets for a guaranteed match5 paid out less than 1000 bucks. The total lines generated over the full test was less than 3,150.  The odds for a 5of6 hit in a  6-44 game are 1 in 30,961.  The predictor managed a 5of6 in  < 3150 so 30961/3150 = 9.8  times better than expected.  This is still not good enough to come out ahead.  3150/2=\$1575  so even with all other prizes combined it still lost money.  To come out ahead for this game the  predictor needs to hit a 5of6 around once in every 45 games.  I believe the predictor can be  coded do this without much work.  The more lines one plays the better the chances for a  JP level  prize.  35 lines can be played for less than \$20.00 per game or \$40.00 per week.  If the predictor  can be made to function at the one 5of6 for every 45 games played then I could play it for ever  without it ever costing me a penny.  The only mathematically sound way to increase our chances  of a JP level prize is to play more lines.  Winning once every 45 games would meet the break-even  level needed to play without any risk as all tickets will require no out of pocket expense.  The perfect system.RL`

sound nice.how many numbers have you wheeled in 35 lines? all 44 numbers or less than 44 numbers?

If your system could manage to have 5-6 winning numbers in 35 lines(winning numbers do not have to be on one line) using less than 44 numbers,there are some ways around I know to make profitable 16 lines.

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

United States
Member #59354
March 13, 2008
3986 Posts
Offline
 Posted: November 22, 2014, 10:39 am - IP Logged

Hans

Reconfigure you lines using pairs of second digit zeros so that each combo will show 6 times in

18 lines.  Then use the 05 in place of the the third.  This is based on banking digit zero as most

likely to show > 1 in the next draw.   Personally I think digit zero will show less than 2 and maybe

not at all in the next game.  Just my best guess, I could be wrong as I am just stating the most

probable.

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

Monte Carlo
France
Member #55589
October 9, 2007
1181 Posts
Offline
 Posted: November 22, 2014, 10:45 am - IP Logged

Hans

Reconfigure you lines using pairs of second digit zeros so that each combo will show 6 times in

18 lines.  Then use the 05 in place of the the third.  This is based on banking digit zero as most

likely to show > 1 in the next draw.   Personally I think digit zero will show less than 2 and maybe

not at all in the next game.  Just my best guess, I could be wrong as I am just stating the most

probable.

RL

we will see after the drawing if it works ;)

but I wanna bet on 10 41 21 44 40 20 one ticket~~

so if it has one match4,and by playing 16 times=16 tickets,that strategy will have 16*29=464 dollars!

Prize ratio:464/8=5800%.

That equals to half match5 prize.so I dont need to play 35 lines to have a match5 prize less than 1000,I need to play 32 times one match4 ticket and can just make it.

And if it's a match3 ticket,its free play so no loss.

match5 or jackpot would be the best as 16 times match5 prize can be around 15000,and almost all jackpot prize would be mine.

when will you post your 35 lines?

Strive to predict 8 tickets for 12 numbers with Max ROI for Pick6!

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