rcbbuckeye - Have to agree on that ( She does seem to have a bone to pick with TLC?) but she offers up some good info when not trying to catch them doing something wrong. True. Conspiracy to ME means that an entity is purposely trying to deceive, but TLC is one of few Lotto's that post up reports, winners on Scratch tix, etc, so I don't think they are doing anything underhanded. However - that being said - I am one who believes in Math, numbers and my biggest, singular belief is that of questionable definitions of 'randomness'. If any game has been programmed in any way - as to affect how numbers are arrived at - then that IMO, is not random. I do not believe that our Texas Lotto draw games are 100% random. I have reasons that are concrete (enough that I can SHOW you) and I'm not wanting to start-restart debate over this. It's something I believe so much, that I base my selections on this. Pseudo-Randomness is closer to correct, where the definition states: "Not 100% random, but good enough for some utility." (Wiki)
I think it is fairly safe to go ahead and mention some aspects of this, as I don't think anything would change (over the opinion of ONE player, even IF I were correct), the TLC would just say "Oh, ok - you figured it out, good." I will say this. With the larger number games? Pick 5, Texas Lotto, (in TX games, I know zero about other State games outside of TX), the DRAW # is key to the process of getting numbers, that you can work with i.e. totals for each number then there are TWO numbers derived from the DRAW # that are, essentially, a L-R with a decimal in the middle. Say the first two numbers of the draw# were 23 then 89, DRAW #2489. 2+3 is 5, then where the harder part is, the 2nd number (a single digit). So, 89 on the surface looks like 17, but it is not. Most people, as expected, poo-poo my alt-value reasoning, which by the way, I messed up last night due to the side-by-side number RULE - (you can NOT have side-by-side EXACT numbers anywhere), so if 89 =17, 1+7 would equal 8. So, 5.8, right? But, that is wrong. 5 is right, but from doing literally thousands of configurations.
I know that the reason for these alt-values are to get MORE single digits for all the games. So, when you know that 8's = 3 and 9s = 4, you can see the logic. 3+4=7, so it would appear you have 5.7 to use in two ways: 1. As the 'dividers' for your totals (I am aware I haven't explained this yet), so if either of these are wrong? You will not be able to arrive at the 'number'. Almost all will be wrong since you started off wrong. And, even when you DO get the right totals, then divide correctly? You then have to keep applying what I call 'rules' to determine the number - an example is if number 2 came up as 19 - now, you have to always be moving toward 'single digits', but if your 'divider is 5.6, then 19, if reduced to 14 (9s are 4s), it would give you the 1 and then the 4 which is LESS than the .6, and that wouldn't count (4<6) so you would stay with the 9 and start looking at 1+9, OR 19 - just not 14 or 5. If you had 5.3 as divider from Draw#? Then (4>3), so you could look at 19 being 14, 14 or 1+4=5. Now, this would be where you needed to look at the 1st number AND the 3rd number to see IF a 14 or 5 'fit in', so if first number was 2 and 3rd number you figured as 13? Then, technically you would be looking at only '5', since 14 > 13, so '5' would seem to be your play. Now change to 5.6 and you get 19, you would be looking at '10' as the logical possibility with 1st number 2, then '10', and 3rd number 13. And 9 > .6 (4 <6, and would leave a remainder. This happens more naturally when you get into the larger numbers of spots 4-6 in 6/49 or 6/54.
I messed up last night by failing to see a side-by-side situation. And, realized that I missed making two number adjustments and it was a knee-jerk assumption from the last drawing. Last draw was 5.3 and I just saw 85 and said "ok 8+5=13, 1+3=4. Wrong. Why? Because of the preceding 23, the THREE, then an 8, so I didn't factor in side-by-side number, which says you get 33, the first 3 makes the next 3 a "1", so It SHOULD have been 5.6 and I was using 5.4. <snip>. Why was it wrong? 85 was 1+5=6 because of the 23 preceding the 8 (8's are 3's) and I jumped at the 4 because last drawing was 5.3 and I just immediately moved to next number since 8+5=13 and 1+3=4. In reality, the DRAW# was 2385, supposed to find the 'alt-value' of any number, and would have if I had slowed down and written it out. 23(3)5, then adjust the 3's - 23 15, so 5.6. <snip>.
I'll be explaining this with illustration later this week. 2385 should have been 2+3=5 and 8=3, but side-by-side with 3, so it should have been 8=3=1 and 1+5=6, so 5.6 was right. I re-ran the six totals with this and, of course it was right. I knew after the first number, 2. After getting the total, then applying the 5.6 division, got 22 which are identicals and result in '2'. And, 2nd number resulted in 21 = 3. My 5.4 had 4 and 8 (which I played) and it fubared the remaining numbers.
Sorry to get off subject. No, there isn't conspiracy at work, not even collusion, but perhaps if anything an RNG programmed to generate numbers based on some Math or C++ or Matrix (all of this is over my head) but, if I can apply the things I've learned and don't make dumb mistakes, then maybe if I stay with it, a favorable DRAW# will pop up (or one that I don't F up). Can only work on it. I don't have empirical evidence - yet - showing this works for the Pick 3 and Pick 4, but I'm headed in that direction. As is often found, sometimes a little knowledge is dangerous - so I'm careful to try and post what has WORKED, before just winning even once - consistency IMHO is more important than anything. But, if there were one thing I would say is that the alternative values of numbers DO figure in to all the games. And 7s and 0s are where the most mistakes are made. BTW - if you use the decimal division, your results should be = on BOTH sides of the decimal, so if you get 4.076, then add two more 0s to the left side. If you have the right number, each side will end up being the same number! And, this can be broken down once more - if you ended up with 10 numbers totaling 50.34. you can then take 50 and do the same using 5.0, then 3.4, and they would result in being = on each side. In other words, 5.0 and 3.4.
A great program to help with your math (in addition and adding decimal spots) is Cymath.com. It also catches mistakes and shows you ALL the numbers on either side of a problem, so when 12.3456 shows up, you know to go back to top, and add in two more zero's. The only thing Cymath cannot do is change the 'alt-values' of numbers, side-by-sides, and this is up to you to do. So, once again, my error last night was MINE, not anything to do with the Lotto drawing. I simply missed something i should have caught.
Cash Crown
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