United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 7:59 am - IP Logged

Quote: Originally posted by CalifDude on May 20, 2006

Seems that things keep changing. Am I the only one that senses that? At one point I thought that this method produced 640 combinations and there was a guarantee of 100% hit rate. It has gone through a few mutations and now Kola says that when it is all said and done there are 200-220 combinations which possibily have a straight. Well the same can be said for the 220 combinations I listed!!

Now I am told (maybe it was said before and I missed it) that it works mid to eve and eve to mid, so my example of only 3 hits in 7 draws was wrong because I was using mid to mid in my example.

Sorry forgot to address your puzzlements.

There is a guarantee of 100% hit rate. The only things I have mentioned that may

interfere with it is, if a state has practice runs before the actual draw. Those kind of

game mechanincs or rather machinations can interfere with the results. I have to

do more testing with those states that practice , but what I have observed so far is

that it has no impact. As for computerized drawing the same accuracy holds, for

now. I stll have to do so more sniffing, becauseof the nature of computers. Its

interesting, my feeling is that an old computer is infinitely more lottery friendly than

a new computer. There's a reason for that. Its just my speculation though.

The above reasons will affect a number. I'm still looking for how much. In

mechanical drawings, its easy. The number will fall, maybe box maybe straight but it

will fall.

Another thing I alluded to about the rarity of a number not being in the pool

is the significance of a triple on the on the outcome of a game. I'll talk about that

later, ecause its rare that they fall. But when they do its like hail all over the

country. Triples I believe have super-high enrgy signatures, and i have seen them

as the only numbers that can impact a game. But pi can come to the rescue. I'm

refining that as well

Califdude the DSUM method does produce 640 combination, but at least half of

those will be eliminated. And in my experience more than that. You will endup

between 200-240 combos that includes all the doubles, the possible triple, and

lastly unique digit combos. I have not find the way to find the specific straights that

will hit. The DSUM method will always provide you with the winning number.In my

experience the straight form of the winning number is always there, but because

of fitering to reduce duplicates it will often be filtered out. Remember I know that

the number will always be there in boxed and straight form. I have found this too

be true based on the numbers I have done. It would very prudent to rigourously

test this statement before playing. .

And yes, the games are from draw to draw. Sometimes one can leave the same

workout in there, for the next drawing but you have to look at the pattern of how

the numbers are falling to dtermine if your workout would still be valid. It often is,

but sometimes a new energy comes in and your lost. So draw to draw is best. Hope

United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 8:33 am - IP Logged

Quote: Originally posted by mybolade on May 20, 2006

I have checked the last 17 draws for MI. The number has been there 100% of the time. It is not always straight, but it is straight approximaately 30% of the time. You said you looked at the 4 digit, can you post what the D string is for that. I did create a spreadsheet for the 3 digit and would like to do the same for the four. I think I would just create every possible combination from DSUM is this correct?

Ah Bolade, Thank you for testing that, as all my testing as been by hand, and

somtimes inefficient. Yes I will post the Pick 4 D string, and your right in your

assumption that it would create every possible DSUM expression from the previous

draw. I will do it sometime today. Its a monster though, but considering the

possible combos its just as manageable as DSUM for pick 3.

In essence, with Pick 4 you will have just 2, 320 combos. This is before taking out

the duplicates. But no bother, because when all is said and done, there will be so

many duplicates, your playable numbers will relatively speaking, be a small pool. I

think i have also found a way to get the correct string or pointer to the correct.

number. Its testing more accurate then Pick 3. Still crunching though, Stay tuned...

Yes bolade...was the straight 30% of the time seen after removing duplicates or before?

Tx United States Member #4570 May 4, 2004 5180 Posts Offline

Posted: May 20, 2006, 8:48 am - IP Logged

Now this is how things really are:

On the 460 straight combos the winning number will be there only from 40 to 50 percent (%) of the time and no more than that average in the long run.

But the winning number will be among those straight combos boxed 95% of the time, make no mistake about it, so when the 460 numbers are boxed to 210 boxed combos the winning number will be there an average in the long run of about from 94 to 96 percent of the time (95%), But much more likely will be there boxed and not straight.

The trick if it can be done at all is to be able to have the straight winning number there among the 210 boxed combos 40 to 50 percent of the time as it always is on the 460 straight combos.

Kola or somebody else needs to find a way of trapping the winning number straight among the 210 boxed combos 40 to 50 percent of the time as it is always on the 460 straight combos.

When the 450 straight combos are boxed, you might be keeping a boxed version of the winning number among them and filtering out the straight version of the winning number as singles are 6 way numbers and doubles are 3 way numbers, when you box straight numbers, more often than not you will also filter out the straight version of the winning number and get instead a boxed version and more so ifthe straight version is only among the 460 from 40 to 50 percent of the time anyway, among the 460 strraight combos you might have the winning number from 2 to 4 times, 3 times average of those 3 winning numbers, 40 to 50 percent of the time 1 of them will be straight and 2 boxed the other 60 to 50 percent of the time all 3 versions of the winning number among the 460 straight combos will be there boxed only.

That is all.

Your job is to trap the winning number straight and not boxed among the 210 boxed combos 40 to 50 percent of the time or as often as possible.

United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 9:05 am - IP Logged

Quote: Originally posted by paurths on May 20, 2006

Width 1: 210 numbers (always a double) Width 3: 190 numbers, and 200 numbers if a double Width 4: 180 or 210 numbers (190 if a double) ... so it seems...

Yes Thank you paurths. My manual workouts have always yielded these numbers.

the berry/louisiana United States Member #16351 May 29, 2005 571 Posts Offline

Posted: May 20, 2006, 9:09 am - IP Logged

well i trapped a straight Kola using youre method and Desteny200f's method.night before was 549 so i did (UDU)- up down up (5 becomes a 6) (4 becomes a 3) and (9 becomes a 0). i took the pairs 49 form night before and went up and theirs the 03 thats how i got my straight. bought 10 tickets of 036 won 5,000.00 dollarsi played it straight on all tickets. after i did your method and looked at desteny's chart i said that had to be it so i took a chance. Thanks Kola and Desteny i will use your system because ive back tested and they work together for Louisiana!!!!!

United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 9:21 am - IP Logged

Quote: Originally posted by paurths on May 20, 2006

Okay, one simple question; do the numbers have to be played straight or boxed?

Without answering this question there really is no telling how te begin a workout...

you wrote:"The most number of combos that can com up, is approxiamately 240 numbers.

TOPS. Granted I have never permutated every active number. But I have

donemany, and the nature of the pick 3 is such that a number will have 240

expression as an upper limit"

I don't understand this at all... Where is the 240 coming from? And what is "the nature of the pick3 is such that a number will have 240 expression as an upper limit"?

Hey Paurths,

As far as the numbers having to be played straight or boxed....I don't know. Its up

to you.It wouldn't matter if there were a good strong pointer to help guide the

way. With some kind of progressive wagering you would come out ahead.

Some immediate possible pointers that comes to mind are V-tracs, Lottery Queen's

list, lotterbraker's method, Black Apple digit out method. Pick one and merge with

DSUM, and hopefully you'll find something there.

My comments about the "240 upper limit," and "the nature of the pick 3", are just

really personal thoughts and ideas that I let out of the bag. I was in stream of

conciousness. What I said won't add or take away to using DSUM and playing the

Pick 3 in general. Please don't concern yourself with them. Chalk it up to the

Switching between Fairfax, VA and Belgium Belgium Member #19287 July 29, 2005 2254 Posts Offline

Posted: May 20, 2006, 9:27 am - IP Logged

Quote: Originally posted by Kola on May 20, 2006

Quote: Originally posted by paurths on May 20, 2006

Width 1: 210 numbers (always a double) Width 3: 190 numbers, and 200 numbers if a double Width 4: 180 or 210 numbers (190 if a double) ... so it seems...

Yes Thank you paurths. My manual workouts have always yielded these numbers.

Ofcourse they did, those numbers go by certain laws, and the result is always the same, which, in short, means that your workout will always be the same too! It will pretty much always produce all the possible combo's!!! Ofcourse the winning number is there all the time. The problem is, with 220 numbers, one can only win if a double hits, and by playing online-odds.

I can write code in about 25 seconds to produce the 1000 straight picks, and the winner will be there every time. And not boxed, but straight up. I would just need to tweak my code a little bit so i can find out where the winning numbers is about in the output.... LOL To me it seems you have developed an extremely difficult workout to only produce pretty much all the possible boxed combo's.

240????? I have the feeling that something is not very clear..............

you keep hammering on this 200 to 240 numbers.

You also state that the winning number is always there.

You also state that the winning number is either there boxed or either straight.

How many numbers are there in a pick3 game, kola? 1000 numbers, that's how many. How many boxed numbers are there in a pick3 game, kola? 220 numbers, that's how many.

So, you're method can not, i repeat, it can not create more than 220 numbers, it can not create 240 numbers, after the duplicates have been filtered out, since you filter out box, otherwise you would always end up with 460 numbers. (these are straight filtered) Why? Easy, because that is theoretically and practically impossible!!!

To me, what you have here is a very complex way of creating all possible combo's, with a maximum of 220. Furthermore, the amount of unique combo's created depends on the width of the numbers used as draw-number. (on the previous page i posted examples of that)

I don't know if you are very familiar with pick3, b/c i read earlier on you were impressed with the table of shortsums (or LDR or LSD, 3 different names for the same item) that CD posted.

I could go through some length and adjust those numbers, so that instead of 012 it would show 201, or 210. But it would still be the same idea. The winning number is there each and every time.

United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 9:33 am - IP Logged

Quote: Originally posted by LANTERN on May 20, 2006

Now this is how things really are:

On the 460 straight combos the winning number will be there only from 40 to 50 percent (%) of the time and no more than that average in the long run.

But the winning number will be among those straight combos boxed 95% of the time, make no mistake about it, so when the 460 numbers are boxed to 210 boxed combos the winning number will be there an average in the long run of about from 94 to 96 percent of the time (95%), But much more likely will be there boxed and not straight.

The trick if it can be done at all is to be able to have the straight winning number there among the 210 boxed combos 40 to 50 percent of the time as it always is on the 460 straight combos.

Kola or somebody else needs to find a way of trapping the winning number straight among the 210 boxed combos 40 to 50 percent of the time as it is always on the 460 straight combos.

When the 450 straight combos are boxed, you might be keeping a boxed version of the winning number among them and filtering out the straight version of the winning number as singles are 6 way numbers and doubles are 3 way numbers, when you box straight numbers, more often than not you will also filter out the straight version of the winning number and get instead a boxed version and more so ifthe straight version is only among the 460 from 40 to 50 percent of the time anyway, among the 460 strraight combos you might have the winning number from 2 to 4 times, 3 times average of those 3 winning numbers, 40 to 50 percent of the time 1 of them will be straight and 2 boxed the other 60 to 50 percent of the time all 3 versions of the winning number among the 460 straight combos will be there boxed only.

That is all.

Your job is to trap the winning number straight and not boxed among the 210 boxed combos 40 to 50 percent of the time or as often as possible.

And this is the way that it is.

Have a nice day!

Lantern thanks for cutting trough the muck, and pulling out some pearls of of good reason. I've been working on it. Somethin' s brewin'...Well, we'll see. Still testing...

United States Member #28945 December 25, 2005 1532 Posts Offline

Posted: May 20, 2006, 9:55 am - IP Logged

Quote: Originally posted by bipolar on May 20, 2006

well i trapped a straight Kola using youre method and Desteny200f's method.night before was 549 so i did (UDU)- up down up (5 becomes a 6) (4 becomes a 3) and (9 becomes a 0). i took the pairs 49 form night before and went up and theirs the 03 thats how i got my straight. bought 10 tickets of 036 won 5,000.00 dollarsi played it straight on all tickets. after i did your method and looked at desteny's chart i said that had to be it so i took a chance. Thanks Kola and Desteny i will use your system because ive back tested and they work together for Louisiana!!!!!

YEEEAAAAHHHH!!!! BiPolar. So happy for you. That's what I'm talking about.

All these systems help to inform each other. They work along the same harmonics.

Anyway. yes,yes, yes!!! Although DSUM s expansive enough to net the possible

numbers its strength is what Paurths spoke of earlier as it being a sort of static

array to LOCK DOWN the winning number. With another

strong pointer or system as in Bipolar awesome usage of Destiny's case you can

see strong convergences toward the numbers, and hopefully straight. The pi

method I posted in the beginning of this thread, and more elucidated later in the

thread, shows a very strong convergence toward just a few particular numbers. It

can readily be used with DSUM. There number has never failed to be in the pi

workout as well. Again Congrats BiPolar. Great wagering. May you have tons of

Poway CA (San Diego County) United States Member #3489 January 25, 2004 14120 Posts Offline

Posted: May 20, 2006, 10:47 am - IP Logged

Quote: Originally posted by paurths on May 20, 2006

Quote: Originally posted by Kola on May 20, 2006

Quote: Originally posted by paurths on May 20, 2006

Width 1: 210 numbers (always a double) Width 3: 190 numbers, and 200 numbers if a double Width 4: 180 or 210 numbers (190 if a double) ... so it seems...

Yes Thank you paurths. My manual workouts have always yielded these numbers.

Ofcourse they did, those numbers go by certain laws, and the result is always the same, which, in short, means that your workout will always be the same too! It will pretty much always produce all the possible combo's!!! Ofcourse the winning number is there all the time. The problem is, with 220 numbers, one can only win if a double hits, and by playing online-odds.

I can write code in about 25 seconds to produce the 1000 straight picks, and the winner will be there every time. And not boxed, but straight up. I would just need to tweak my code a little bit so i can find out where the winning numbers is about in the output.... LOL To me it seems you have developed an extremely difficult workout to only produce pretty much all the possible boxed combo's.

240????? I have the feeling that something is not very clear..............

you keep hammering on this 200 to 240 numbers.

You also state that the winning number is always there.

You also state that the winning number is either there boxed or either straight.

How many numbers are there in a pick3 game, kola? 1000 numbers, that's how many. How many boxed numbers are there in a pick3 game, kola? 220 numbers, that's how many.

So, you're method can not, i repeat, it can not create more than 220 numbers, it can not create 240 numbers, after the duplicates have been filtered out, since you filter out box, otherwise you would always end up with 460 numbers. (these are straight filtered) Why? Easy, because that is theoretically and practically impossible!!!

To me, what you have here is a very complex way of creating all possible combo's, with a maximum of 220. Furthermore, the amount of unique combo's created depends on the width of the numbers used as draw-number. (on the previous page i posted examples of that)

I don't know if you are very familiar with pick3, b/c i read earlier on you were impressed with the table of shortsums (or LDR or LSD, 3 different names for the same item) that CD posted.

I could go through some length and adjust those numbers, so that instead of 012 it would show 201, or 210. But it would still be the same idea. The winning number is there each and every time.

Use any list, the winning number will be there 100% of the time.

Right on, Ricky!! This is what I have been trying to say, but you did a great job saying it yourself. Even with this explanation there will be people that are impressed by this method. I am not.