United States Member #59354 March 13, 2008 3962 Posts Online

Posted: July 8, 2010, 6:13 am - IP Logged

Quote: Originally posted by lottobrain on July 7, 2010

I have experimented with using last digits before in my lotto games, and I recently tried the positional approach that you used without any luck that way either. What I had done in the past and what I have gone back to is just setting up a chart from 0-9 down a page and then tracking each draw across the page. You end up with a "hit" chart this way and then I just guess for the next draw by selecting a couple of last digits that just hit as these seem to repeat, and then picking a couple of overdues, and then a couple of others. Sometimes I select one of each last digits resulting in no more than 10 numbers. If I feel like it may be time for a certain digit to have 2 hits in the next draw, then I'll pick 2. By tracking the individual digits across the page in this way, you can develop a feel for what might be the next. The system I use for arranging my numbers into plays is an old Robert Serotic system for "pairs" with one key number that can guarantee the jackpot if you get the numbers to hit in pairs and your key number is right. For example in Hot Lotto tonight I selected 15 white ball numbers, covering all end digits. This gave me 1 key number with 7 pairs. I then wheel all of the pairs with each other plus the key number (7 x 6 = 42/2 = 21 combinations. I picked 5 "hot balls" that I thought were due and played them over and over thru the combinations. #2 was my favorite and I played it 6 times. I also played the extra $ for the "sizzler". My white ball number selection was terrible as I got nothing right out of 15 numbers from 39!! But #2 "hot ball" hit, so I won $36, losing only $6 for the night.

Everyone.

I must be horrible at explaining things because many are not following important rules that this system

needs to work, so I will try again. sorry.

ID = total number of "DIFFERENT" digits in a set not counting "0" when to the left of another digit

TD = "ALL" digits in a set except the "0" when it is to the left of another digit. ie numbers less then 10

The thing to remember is to first select the ID value and then select the digits. If you select

6 for your ID value then select 6 digits. If you feel the need to add digits then start over.

Never add digits above your ID setting. If one selects a ID value of say 5 and then playes all or most

of the digits then nothing will be gained. When playing this system you must be able to select the correct

digits within +/- 1 for it to work. If your lottery is like my SM-5 game then most drawings will have the

digits 1-2-3. Never add up digits and play the best hitters as this is a very common mistake that many

make. Sure they hit the most often but they don't hit togeather every time. If this was the case than the

lottery would be very easy to win. Before playing best hitters togeather first check them in pairs or trays.

Once you have selected your ID value and digits then build a list of all the numbers that can be

formed using the digits.

example.

If digits selected = 1-2-3-5-8-9

01-02-03-05-08-09

11-12-13-15-18-19

21-22-23-25-28-29

31-32-33-35-38-39

24 numbers

Next select your TD value. Lets say that you think TD will equal 10 for the next drawing. All of the

numbers "01-02-03-05-08-09" only have 1 digit because the "0" is not counted when it is to the

left of another digit TD = total digits.

10 TD example "12-14-22-28-39"

9 TD example "01--5-22-34-36"

8 TD example "02-06-17-23-30"

7 TD example "01-04-07-20-36"

6 TD example "01-03-04-08-29"

5 TD example "01-03-04-07-09"

In this example leat say that we have decided to use ID = 10 so we remove the numbers "01 .... 09".

We now have 18 numbers left. Next Lets say that in viewing the last 30 draws we think the fifth

number will be above 30.

Next make a note of how often digits 1-2-3 hit in the second position for your lottery. In my lottery,

at least until I posted this most drawings had at least 1 of the base numbers 1-2-3 as a second digit

example "11-12-13-21-22-23-31-32-33"

again lets say that we have made the following decissions or best guesses.

#1 ID = 6

#2 digits = 1-2-3-5-8-9

#3 TD = 10

#4 numbers "01-02-03-05-08-09 cannot be used because ID = 10

#5 first number must be above 10

#6 Last number will be 31 or more

#7 we have 18 numbers left to form our set

#8 first digit, first number will most likely be a "1"

#9 fifth number, first digit will be a 3

#10 we must use all 6 digits at least once to build every set

#11 digits we have not used yet = 2-5-8-9

Next study your data and make your best guess if the first number will be hi or low, meaning

low= 11-12-13 and hi = 15-18-19, do the same for the fifth number low = 31-32-33, Hi = 35-38-39

next try to decide if they will they be odd or even.

Next after making your selections count how many digits you have used. lets say that you decided

the first number will be odd and low you are now left with 11-13 for the first number. Next lets say

you select hi and even for the fifth number "38"

used digits = 1-3-8

unused digits= 2-5-9

The digits 2, 5 and 9 must be used to make ID= 6 and 5 and 9 can only be used as a second digit in

this example because there ther are 39 numbers total.

I am left with the 3 middle numbers that at least 2 of them must end with 5 or 9

P1 = 11 or 13

p2 =

p3 =

p4 =

p5 = 38

Next I must select two of the numbers 15-19-25-29-35 to fill in two of the remaining 3 positions

I now have 2 first choices of 11 or 13

I have to select two of the numbers 15-19-25-29-35

I have to select one of the numbers 12-21-22-23-31-32-33 and 13 if not used as the first

I have 38 as my last number

I select 11-19-21-32-38

I count the digit 1 it's ok

I count the digit 2 it's ok

I count the digit 3 it's ok

I count the digit 5 problem no 5's, this set is rejected.

I also notice that digit 1 is in the set 3 times and 2, 2 times and 3, 2 times

I take a look at the last 30 draws and find that all three digits 1-2-3 htting more than once in a

single set has happened only 3 times. I conclude this is another bad sign and would reject it based

on that information alone.

Next set 11-15-28-29-38

I count the digit 1 it's ok

I count the digit 2 it's ok

I count the digit 3 it's ok

I count the digit 5 it's ok

I count the digit 8 it's ok

I count the digit 9 it's ok

I have all six digits, OK

The digits 1,2 and 8 all hit more than once so I look at my data again and see that 8 hitting twice

is common enough to play but I also notice that when 8 hits more than once It is in draws where

TD = 9 or less. Since I am playing TD = 10, I might not want to play this number set either.

Next I take the previous nights drawing and write it down and place my selection over the top of it.

11-15-28-29-38

01-04-12-19-34

The first thing that I notice is that the digit 9 is the second digit in both 4th numbers. I again look at

the last 30 draws and find that this does not happen very often. I do notice that 9 repeats but not in

the same position, I find that most second digit repeats move at least one number to the right or left.

Based on these two observations I choose not play this number.

Next I may swap two digits around and see if I can make the set fit the patterns of my datafile. If not

the set is rejected. Don't limit yourself to only what I have used here, much more can be applied. Build

a couple of sets and then change digits and start again. Remember ID first and then select the digits

and then TD. Make a decision and follow it to the end. If you start adding and removing digits once you

start you will not do well. If you find you don't like a certian set or selection then start over from

the beginning. A college Professor once told me. "Never change boats in the middle of the stream."

Try to work the set from the ends inward to the middle, this will reduce the choices and always remember

the lottery is random, you cannot predict with any certainty what will happen but you can play smarter

Hope this helps

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

Clearwater, FL United States Member #31472 January 29, 2006 167 Posts Offline

Posted: July 8, 2010, 8:47 am - IP Logged

Thanks RL, for the Ohio Rolling Cash 5 I have chosen TD =9 and ID = 6, the digits are 1, 2, 3, 5, 6, 7, first digits are 01233. I removed the last digits drawn by position, last drawn 11, 13, 16, 17, 22 so, Pos 1 no 1, Pos 2 no 3, Pos 3 no 6, Pos 4 no 7, Pos 5 no 2. I made every posible combination of 01233 TD 9 and ID 6 which leaves 126 combinations. Due to the choice of 01233 and having no 3's in pos 2 and no 6's in position 3, the total amount of main numbers used went from 23 to 21 dropping the 13 and 26.

Now I have 126 combination meeting the TD and ID I need to know it down some more, what would be the next best move?

Clearwater, FL United States Member #31472 January 29, 2006 167 Posts Offline

Posted: July 8, 2010, 11:20 am - IP Logged

Nice, that's what I was thinking, using the MDN, DEV, DOD to filter down, I have those number sets already setup for filtering, I think my fear on that is when MDN is drawn 5 but, I think playing the mid average of 3 MDN is the best way to go.

Clearwater, FL United States Member #31472 January 29, 2006 167 Posts Offline

Posted: July 8, 2010, 9:12 pm - IP Logged

I used MDN 3, DOD 1, DEV 1 and got the 126 down to 22 tickets whcih had 2 match 3 and 1 match 2 for $21 and $1 loss. I checked the original 126 and found that I had filtered out a match 4 which would have been $300. The MDN drawn was 2, DOD 2, DEV 1. Hey, I'm on my way.

raleigh, north carolina United States Member #92685 June 12, 2010 68 Posts Offline

Posted: July 8, 2010, 9:22 pm - IP Logged

Quote: Originally posted by RL-RANDOMLOGIC on May 30, 2010

The Digit System

I have been programming for 25 years and took up a challenge to write a program that was capable of producing repeatable results for pick-5 pick-6 lotteries.

This is a small part of a system that I have been working on for many years I have had much success using this system up to the past few months. I am sharing this system in hopes that in doing so will improve my carma. "Give and it shall be given".

I will not post the whole system as it would take 30 to 40 pages but will give a good working description that should allow those who are interested a starting place. I play 5-39 and 6-44 games. so most of the information I give will pertain to information I have gathered from these games.

Some Definitions first

ID = Independent digits. Digits 0-9 counted only once regardless of times within a set.

TD = Total digits. Number of all digits within a set but does not include leading zero's

DOD = Double odd digits. Numbers made from two odd digits

DEV = Double even digit. Numbers made from two even digits

MDN = Mixed digit numbers. Numbers made from 1-odd and 1-even digit

Are you interested yet? and these are the only 4 sites I checked when I began to write this. Funny it was there all along but went unnoticed.

Don't get to excited yet because it's not that simple. Like I said I have been searching and writing lottery software for 20 years and I don't have millions, yet.

Most drawing sets consist of 6 digits, Remember I said Most. A bell curve will peek on 5 or 6 for most any lottery. Take another look at your lottery and you will find that most draw sets will have the digits "1-2-3" in a large percent of draws with many of those having more then one of at least 2 of the "1-2-3" base digits within it.

Next consider that the largest percent of draws contain at least one number that consist of only one digit, "number below 10" and many sets contain two single digit numbers. In a 5 number draw the maximum TD possible is ten.

Now for the mathmen, 6 digits in a 5/39 lottery can yield over 6000 combos depending on the 6 digits selected. Done that! been there. I don’t need your brain power to tell me what I already know. I don't want any odds quoted concerning this. Believe me I have ran every combo of digits in every way conceivable. At one time I was running 4, really fast, striped down computers 24/7/365 crunching numbers my own version of a home super. I will give those that wish to baffle a question to ponder. I say odds are for the losers. I know of no real lottery in the world that has sold all winning combo's within one drawing but yet lotteries are won every day by everyday people many of which purchased a one dollar play. What’s the odds on that. A person will win or lose not based on the odds but on the ticket he or she holds in their hand. A lottery player considers the odds but plays anyway, Kind of like a certain paint store worker that may of considered the odds but choose to sing anyway. And as Forest would say "that's all I got to say about that"

Now for those who like to dream big, and hope to one day pull down a really big one, I will continue. Dreams are good and I hope all your dreams come true. As I stated above it would seem easy to build a set of winning numbers based on the info just provided. To put it simply, It is not. Many draws will follow this path but not all. Don't expect, but hope that the information provided in this post will help your dreams come true.

notice that I pad all single digit numbers with a "0". This digit will be ignored except in some cases.

Step #1 compile a list of at least 30 drawings. They can be a random sample. A current day to day drawing list is no better then a random sample I for years believed that the patterns I found would repeat until I discovered that the patterns were also random. All roads will intersect with another if they run far enough. That being said, go through each drawing on your list and mark how many TD, ID, DOD, DEV, MDN digits are in each draw, When writing down the sets, arrange them in 10 columns, the numbers 12 18 22 35 39 would look like this include leading zero's in this list

Step #3 On another sheet of paper convert the number sets to digits, do not include the padded "0" in this list. "08-12-15-18-34" to "1-2-3-4-5-8" each digit is counted only once and then to the right of this place the digits that were not in the draw

Draw set Digits hit Digits out 08-12-15-18-34 1-2-3-4-5-8 6-7-9-0

Step #4 Study the list you have made and trends will begin to appear. I say trends not patterns. A trend is like a pattern but it is not a pattern. All lotteries develop trends. look at each column of numbers and decide which digit hits most often for that column and write them down. On a new sheet of paper draw 10 lines, one for each digit. ___ ___ ___ ___ ___ ___ ___ ___ ___ ___ make a list of the best ID, TD, DOD, DEV, MDN, values that hit most often. now using the information gleamed from the data sheets fill in the best digit for each place on the line. Next look at the digits and see if all the data from ID,TD,DOD,DEV,MDN fits your selection. if not then repeat the process. do not be concerned with how your numbers appear on the lines as they may not be in any order. Keep your data sheets for reuse or make several different ones and play a set or two from each.

As stated above this is but a small part of a much larger system. My system allows a range of settings for each value + wildcards then generates all possible combo's then filters them and then finally wheels them down to 10 or so of the best sets. I have hit as many as four 4/5 in one day. I have won three 5/6 using this system.

I gave my sister in law a small list of numbers to play and within a week she had hit two or three 4/5 plays and many 3/5. This system does work but requires some skill and some gut instinct to make the final selections.

Good luck and if interest is high enough I will maybe add some more at a later date.

Try to flush your mind of what you think will happen, several years ago I wanted to know what I was doing wrong. I wrote into my software the ability to track my inputs and then report back were I made mistakes. Guess what? I made the same mistakes over and over again, I let my personal preferences overrun what the data was saying, "that can't happen again", that sort of thing. I also included the ability to see what changes would have increased my winnings, There were many times when one click of a mouse would have won me millions.

Enjoy

I appreicate your taking the time to do a well done system

Hope to POP a good lump sum soon!!!! I am really looking at your system and just gotta say it makes sense

fits like a puzzle, just need to put the proper pieces together at the proper time. THANKS!

Visualize and then Materialize... Mega Millions Millions & MILLIONS 4 ME $$$$

God is space...........Demonstrated!

The light from just one candle can dispel a sea of darkness so...let there be LIGHT!!!

Ohio United States Member #93878 July 9, 2010 7 Posts Offline

Posted: July 9, 2010, 4:11 pm - IP Logged

RL-Randomlogic:

This thread is truly amazing. I never thought I would join a lottery forum, this thread and this thread alone made me join here. I am going home tonight and going through this in detail. I love what you have created and would love to help. I definitely have less mathematical/statistical/computer knowledge than many of you guys, but I have always been intrigued with math!

United States Member #59354 March 13, 2008 3962 Posts Online

Posted: July 9, 2010, 5:15 pm - IP Logged

PICKING DIGITS

Using this system requires selecting the correct digits and I will now addressed this issue. I use a number of different methods and will explain in detail one of the best. Before getting started I will show and explain some of the basics.

As I have explained in the previous post this system is built around what I call the ID or independent digits, but to be successful one must be able to select the correct digits.

Our numerical system has only 10 digits "0-1-2-3-4-5-6-7-8-9" from which any value can be repesented. This post is for double digit lotteries which are defined by selecting the correct set from a larger pool.

Using Power-Ball for an example we must select 5 white balls from a pool of 59. Your first selection has 59 choices your second has 58 third 57 ect...

I think that everyone understands this. Now if using digits you will have five possible decades with 10 singel digits plus 9 single digit numbers.

Number system 1 of 59 total choices for first selection

Digit system 1 of (5 * 10) + 9 = 59 total choices for first selection

If numbers vs digits have the same odds then why play digits and not numbers? Good question, read on.

Some math "rounded" ID=6 + ID=7 for the current matrix for powerball has a 67% hit rate. ID=6 + ID=7 accounts for 65% of the total sets. So we conclude that this group has hit only 2% above it's expected average for the game. Not very impressive and is most likely considered within the standard deviation for any group of sets within the game.

Bear with me, I am heading somewhere with this. A little story first. I had a friend that was a fishing guide here on the lake of the Qzarks. People paid good money for him to show them where to fish, Why, because he knew the best spots to catch fish. If you have ever been to the Lake of the Oarks you know it's a big lake. Power Ball is a big game, Why not fish where most of the fish are.

For ID to work one must select the correct digits to play. Above I showed that ID without regard to specific digits adds little to nothing that helps one win.

We know that most of the winning sets drawn come from the ID=6 and ID=7 range. This is a good place to start fishing. It's still a very wide area so we need to shrink it down to a size that allows us a better chance.

First remember this, the odds never change for the game unless the matrix is changed. Even if you purchase every combination the odds remain the same.

PB-5/59 total sets % of sets hits For ID=2 60 .000012 0 For ID=3 13,240 .0026 0 For ID=4 255,660 .051 8 For ID=5 1,241,646 .25 32 For ID=6 2,026,760 .40 58 For ID=7 1,205,500 .24 47 For ID=8 249,000 .05 10 For ID=9 14,400 .0028 2 For ID=10 120 .000024 0

It makes since that most of the hits will come from the ID value that has the most sets. Id=6 has the most hits and is the largest group, a no brainer. You must be asking how does this help me I still have to select the winning set from a group of over 2 million. using the ID value of 6.

In a 5-36 all numbers are made from the digits "0-1-2-3-4-5-6-7-8-9" and so are the 59 numbers for the Power Ball matrix. A 5-36 has 376,992 total sets and PB has 5,006,386, or 195,249,054 if you count the 39-PB's.

ID + Digits Lets say that you choose the ID value of 6 to start with. The total sets to choose from have droped by 60% leaving 40% to make your selections from. This is still far too many to play. This is where digit selection comes in. You now need to select 6 of the 10 digits to build your number sets. For this example I will select digits 1-2-5-7-8-0.

PB-5/59 ID=6 using Digits 1-2-5-7-8-0 = 4111 unfiltered sets 4111 / 5,006,386 = .00082 in ony 2 steps.

Next lets say that the number set 12-25-28-50-57 is drawn, of the 4111 sets 344 sets have 3 matching numbers 34 sets have 4 matching numbers 1 set has 5 matching numbers

Of the 4111 sets 379 have 3 or more matching numbers. 4111 / 379 = 10.8 This means that on average 1 out of every 10.8 sets has at least 3 of the winning numbers. For PB the odds of a 3 of 5 hit are 1 in 291.

Selecting The digits. Here is a method that I use that allows me to correctly select the digits on a regular basic. First using the last 30 or more draws, make a list for the 10 digits like the one below. I always add the current draw to the top of my database but this can be reversed.

The set 12-25-28-50-57 = digits 1-2-5-7-8-0, remember that the digit "0" is not counted when it is to the left of a digit, ie. numbers less than 10

1 2 5 7 8 0 =1 1 0 0 1 0 1 1 0 1

You don't have to use 1's or 0's, use whatever looks good to you. another examle

This is all done within my software but can be done using pen and paper. To begin with you should have already decided on a ID value. We will use 6 for this example

You will now try to select the 6 digits that you hope will make up the drawing.

First look at the decade digits, Power Ball has 5 decade digits "1-2-3-4-5" The digit "0" can be used in the position of a decade but is not counted in this methode. Example "04" the 0 is in the decade position but is not counted the 4 is in the ones position.

The number 37 means 3X10 + 7X1 = 37, the 3 is the decade and 7 is in the ones.

The list above shows

0 sets have 1 decades 2 sets have 2 decades 4 sets have 3 decades 18 sets have 4 decades 6 sets have 5 decades

27 sets have decade 1 21 sets have decade 2 24 sets have decade 3 21 sets have decade 4 24 sets have decade 5

19 sets have decades 1&2 22 sets have decades 1&3 19 sets have decades 1&4 22 sets have decades 1&5 16 sets have decades 2&3 12 sets have decades 2&4 17 sets have decades 2&5 16 sets have decades 3&4 18 sets have decades 3&5 17 sets have decades 4&5

I notice that 4 decades is the best hitter and it is out the last 3 draws. and in all but 1 draw with 4 decades a 1 decade has hit.

Lets say that 4 decades looks best to hit and decade 1 should be one of them. Next I see that when decade 1 hits that decade 3 hit 22 times with it and decade 5 also hit 22 times.

I now have decades 1-3-5 but still need one more. I see now that decade 4 hits good with decade 5 so I select it. I now have my 4 decades for the selection and only need 2 more digits to compleat the ID=6

Next looking only at the digits 6-7-8-9-0, I start another method of selection. Now I start looking at digit 1's over 1's and 0's over 0's. I find that only 8 draws did not have at least one 1 over a 1 and only one draw with no 0's over 0's.

In the last draw I find that 7 & 9 are both 0's and 6,8,and 0 are 1's. If I stay with what has happened in the past then I will not play both 7 and 9 because it would mean that no 0's over 0,s would be in the next drawing. Something that has only ocured once in 30 drawings. So now I must select 2 digits and only 1 or less will be digits 7 or 9.

This means that I must select both digits from the 1's group of 6-8-0 or one from each group. Next I look at 7 and 9 to see which looks best to hit.

7 has hit 12 9 has hit 13 Not much help! 7 is out 2 draws 9 is out 5 draws a little better 7 max skip = 6 and has hit after a skip of 2 only once. 9 max skip = 5 and needs to hit. but may be going cold

I then set these aside for now and look at the group 6-8-0. 6 has hit 9 with no repeats. 8 has hit 15 and likes to hit repeats 0 has hit 11 and has hit 2 draws in a row and one 3 in a row.

The digit 8 would be my frist selection for the next digit.

Both 7 & 9 have a better hit rate than 6 and the fact that 6 shows no repeats I then remove it from the list. I also remove the digit "0" because it has hit 2 in a row and only can apear in the numbers "10-20-30-40-50" which is one less than any of the other remaining digits

I now must choose 7 or 9 for my last digit. From the data here I cannot make a choice each has a 50/50 choice. I choose to play them both in 2 runs

ID=6 + 1-3-4-5-7-8 ID=6 + 1-3-4-5-8-9

both of these have less than 1/2 of one percent of the total sets for PB. You can apply many filters to the above steps such as odd /even hi /low sums. A filter can be anything that can be measured against something else.

Now I apply the filters digits 1-3-4-5-7-8 TD=10 DOD=range 1 to 2 DED= range 1 to 2 ODD= range 3 to 4 BN= 1-2 RN= 1-2 PN= 1-2 HN= 1-3 digit "1" must hit more than 1 time per set and digit "7" can only hit once sets reduced to 188.

I selected a random set from the list and checked for matches using the 181 sets. simulating a drawing.

13 38 44 47 51

21 draws matched 3 numbers 6 draws matched 4 numbers 1 draws matched 5 numbers

1 in 6.7 sets matched at least 3 numbers.

I have many more filters to cut this down and only listed a few. This example is what can happen when all the selections are correct. The digit selection is critical to hitting a prize. I used Power Ball in this example because it has such a large matrix.

When applied to a standard 5/36 game the results are much better and far fewer sets will be generated. I have all the software and filters and databases and don't play PowerBall. Consider this. If you set pennies side by side in a line, One for each set in Power Ball then the line of pennies would be 2,311.186719 miles long. If you purchased one mile of pennies it would cost you $84,480.00 and you would have only .000432678 percent of the total sets. If powerball is your game than say a little prayer and buy a QP, same for MM.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

United States Member #59354 March 13, 2008 3962 Posts Online

Posted: July 9, 2010, 8:37 pm - IP Logged

Quote: Originally posted by Porkin on July 9, 2010

RL-Randomlogic:

This thread is truly amazing. I never thought I would join a lottery forum, this thread and this thread alone made me join here. I am going home tonight and going through this in detail. I love what you have created and would love to help. I definitely have less mathematical/statistical/computer knowledge than many of you guys, but I have always been intrigued with math!

Love it and keep up the great work

-P-

Porkin

Jump in, and as for math skills. I once had a math professor tell me that I needed to learn real math.

Took one look at my paper and handed it back, called it Mountian Math. I don't know what that means

but I figured It was something "real good" as tiggs would say.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

ORLANDO, FLORIDA United States Member #4924 June 3, 2004 5893 Posts Offline

Posted: July 10, 2010, 4:15 pm - IP Logged

Quote: Originally posted by RL-RANDOMLOGIC on July 9, 2010

PICKING DIGITS

Using this system requires selecting the correct digits and I will now addressed this issue. I use a number of different methods and will explain in detail one of the best. Before getting started I will show and explain some of the basics.

As I have explained in the previous post this system is built around what I call the ID or independent digits, but to be successful one must be able to select the correct digits.

Our numerical system has only 10 digits "0-1-2-3-4-5-6-7-8-9" from which any value can be repesented. This post is for double digit lotteries which are defined by selecting the correct set from a larger pool.

Using Power-Ball for an example we must select 5 white balls from a pool of 59. Your first selection has 59 choices your second has 58 third 57 ect...

I think that everyone understands this. Now if using digits you will have five possible decades with 10 singel digits plus 9 single digit numbers.

Number system 1 of 59 total choices for first selection

Digit system 1 of (5 * 10) + 9 = 59 total choices for first selection

If numbers vs digits have the same odds then why play digits and not numbers? Good question, read on.

Some math "rounded" ID=6 + ID=7 for the current matrix for powerball has a 67% hit rate. ID=6 + ID=7 accounts for 65% of the total sets. So we conclude that this group has hit only 2% above it's expected average for the game. Not very impressive and is most likely considered within the standard deviation for any group of sets within the game.

Bear with me, I am heading somewhere with this. A little story first. I had a friend that was a fishing guide here on the lake of the Qzarks. People paid good money for him to show them where to fish, Why, because he knew the best spots to catch fish. If you have ever been to the Lake of the Oarks you know it's a big lake. Power Ball is a big game, Why not fish where most of the fish are.

For ID to work one must select the correct digits to play. Above I showed that ID without regard to specific digits adds little to nothing that helps one win.

We know that most of the winning sets drawn come from the ID=6 and ID=7 range. This is a good place to start fishing. It's still a very wide area so we need to shrink it down to a size that allows us a better chance.

First remember this, the odds never change for the game unless the matrix is changed. Even if you purchase every combination the odds remain the same.

PB-5/59 total sets % of sets hits For ID=2 60 .000012 0 For ID=3 13,240 .0026 0 For ID=4 255,660 .051 8 For ID=5 1,241,646 .25 32 For ID=6 2,026,760 .40 58 For ID=7 1,205,500 .24 47 For ID=8 249,000 .05 10 For ID=9 14,400 .0028 2 For ID=10 120 .000024 0

It makes since that most of the hits will come from the ID value that has the most sets. Id=6 has the most hits and is the largest group, a no brainer. You must be asking how does this help me I still have to select the winning set from a group of over 2 million. using the ID value of 6.

In a 5-36 all numbers are made from the digits "0-1-2-3-4-5-6-7-8-9" and so are the 59 numbers for the Power Ball matrix. A 5-36 has 376,992 total sets and PB has 5,006,386, or 195,249,054 if you count the 39-PB's.

ID + Digits Lets say that you choose the ID value of 6 to start with. The total sets to choose from have droped by 60% leaving 40% to make your selections from. This is still far too many to play. This is where digit selection comes in. You now need to select 6 of the 10 digits to build your number sets. For this example I will select digits 1-2-5-7-8-0.

PB-5/59 ID=6 using Digits 1-2-5-7-8-0 = 4111 unfiltered sets 4111 / 5,006,386 = .00082 in ony 2 steps.

Next lets say that the number set 12-25-28-50-57 is drawn, of the 4111 sets 344 sets have 3 matching numbers 34 sets have 4 matching numbers 1 set has 5 matching numbers

Of the 4111 sets 379 have 3 or more matching numbers. 4111 / 379 = 10.8 This means that on average 1 out of every 10.8 sets has at least 3 of the winning numbers. For PB the odds of a 3 of 5 hit are 1 in 291.

Selecting The digits. Here is a method that I use that allows me to correctly select the digits on a regular basic. First using the last 30 or more draws, make a list for the 10 digits like the one below. I always add the current draw to the top of my database but this can be reversed.

The set 12-25-28-50-57 = digits 1-2-5-7-8-0, remember that the digit "0" is not counted when it is to the left of a digit, ie. numbers less than 10

1 2 5 7 8 0 =1 1 0 0 1 0 1 1 0 1

You don't have to use 1's or 0's, use whatever looks good to you. another examle

This is all done within my software but can be done using pen and paper. To begin with you should have already decided on a ID value. We will use 6 for this example

You will now try to select the 6 digits that you hope will make up the drawing.

First look at the decade digits, Power Ball has 5 decade digits "1-2-3-4-5" The digit "0" can be used in the position of a decade but is not counted in this methode. Example "04" the 0 is in the decade position but is not counted the 4 is in the ones position.

The number 37 means 3X10 + 7X1 = 37, the 3 is the decade and 7 is in the ones.

The list above shows

0 sets have 1 decades 2 sets have 2 decades 4 sets have 3 decades 18 sets have 4 decades 6 sets have 5 decades

27 sets have decade 1 21 sets have decade 2 24 sets have decade 3 21 sets have decade 4 24 sets have decade 5

19 sets have decades 1&2 22 sets have decades 1&3 19 sets have decades 1&4 22 sets have decades 1&5 16 sets have decades 2&3 12 sets have decades 2&4 17 sets have decades 2&5 16 sets have decades 3&4 18 sets have decades 3&5 17 sets have decades 4&5

I notice that 4 decades is the best hitter and it is out the last 3 draws. and in all but 1 draw with 4 decades a 1 decade has hit.

Lets say that 4 decades looks best to hit and decade 1 should be one of them. Next I see that when decade 1 hits that decade 3 hit 22 times with it and decade 5 also hit 22 times.

I now have decades 1-3-5 but still need one more. I see now that decade 4 hits good with decade 5 so I select it. I now have my 4 decades for the selection and only need 2 more digits to compleat the ID=6

Next looking only at the digits 6-7-8-9-0, I start another method of selection. Now I start looking at digit 1's over 1's and 0's over 0's. I find that only 8 draws did not have at least one 1 over a 1 and only one draw with no 0's over 0's.

In the last draw I find that 7 & 9 are both 0's and 6,8,and 0 are 1's. If I stay with what has happened in the past then I will not play both 7 and 9 because it would mean that no 0's over 0,s would be in the next drawing. Something that has only ocured once in 30 drawings. So now I must select 2 digits and only 1 or less will be digits 7 or 9.

This means that I must select both digits from the 1's group of 6-8-0 or one from each group. Next I look at 7 and 9 to see which looks best to hit.

7 has hit 12 9 has hit 13 Not much help! 7 is out 2 draws 9 is out 5 draws a little better 7 max skip = 6 and has hit after a skip of 2 only once. 9 max skip = 5 and needs to hit. but may be going cold

I then set these aside for now and look at the group 6-8-0. 6 has hit 9 with no repeats. 8 has hit 15 and likes to hit repeats 0 has hit 11 and has hit 2 draws in a row and one 3 in a row.

The digit 8 would be my frist selection for the next digit.

Both 7 & 9 have a better hit rate than 6 and the fact that 6 shows no repeats I then remove it from the list. I also remove the digit "0" because it has hit 2 in a row and only can apear in the numbers "10-20-30-40-50" which is one less than any of the other remaining digits

I now must choose 7 or 9 for my last digit. From the data here I cannot make a choice each has a 50/50 choice. I choose to play them both in 2 runs

ID=6 + 1-3-4-5-7-8 ID=6 + 1-3-4-5-8-9

both of these have less than 1/2 of one percent of the total sets for PB. You can apply many filters to the above steps such as odd /even hi /low sums. A filter can be anything that can be measured against something else.

Now I apply the filters digits 1-3-4-5-7-8 TD=10 DOD=range 1 to 2 DED= range 1 to 2 ODD= range 3 to 4 BN= 1-2 RN= 1-2 PN= 1-2 HN= 1-3 digit "1" must hit more than 1 time per set and digit "7" can only hit once sets reduced to 188.

I selected a random set from the list and checked for matches using the 181 sets. simulating a drawing.

13 38 44 47 51

21 draws matched 3 numbers 6 draws matched 4 numbers 1 draws matched 5 numbers

1 in 6.7 sets matched at least 3 numbers.

I have many more filters to cut this down and only listed a few. This example is what can happen when all the selections are correct. The digit selection is critical to hitting a prize. I used Power Ball in this example because it has such a large matrix.

When applied to a standard 5/36 game the results are much better and far fewer sets will be generated. I have all the software and filters and databases and don't play PowerBall. Consider this. If you set pennies side by side in a line, One for each set in Power Ball then the line of pennies would be 2,311.186719 miles long. If you purchased one mile of pennies it would cost you $84,480.00 and you would have only .000432678 percent of the total sets. If powerball is your game than say a little prayer and buy a QP, same for MM.

RL

RL,thanks for sharing your system and this method for picking digits. I want to add this, for the first digits, in Fla F5, using these dbls, 001, 002, 003, 011, 022, 033, 112, 113, 122, 133, 223, 233, in P1P2P3, a 67% chance of being right. The max skip for one of those is 3 draws.

Clearwater, FL United States Member #31472 January 29, 2006 167 Posts Offline

Posted: July 11, 2010, 4:35 am - IP Logged

I look at the spreadsheet for first digits and it shows that the top hitting first digit combinations are 3 single digits and 1 pair of digits, the most common are 01123, 01223, 01233, 00123. Now I look at the actual drawn first digits for the last 30 draws and I find that 16 draws there are two pair of digits plus 1 digit and 10 draws there are triple digits drawn and a few of those had quads which I didn't count. I got the same results from both the Ohio Rolling Cash 5 and the Fl Fantasy 5, both had the same results for the last 30 draws.

Now getting the last digits is hard enough but I wonder if playing the top first digit hitters against the dbl dbls and the triples is a smart move? If you using the spreadsheet or doing things on paper take a look at the first digit list and see how the dbl dbls and triples fair for your game.

ORLANDO, FLORIDA United States Member #4924 June 3, 2004 5893 Posts Offline

Posted: July 11, 2010, 6:32 am - IP Logged

Quote: Originally posted by PadawanLotto on July 11, 2010

I look at the spreadsheet for first digits and it shows that the top hitting first digit combinations are 3 single digits and 1 pair of digits, the most common are 01123, 01223, 01233, 00123. Now I look at the actual drawn first digits for the last 30 draws and I find that 16 draws there are two pair of digits plus 1 digit and 10 draws there are triple digits drawn and a few of those had quads which I didn't count. I got the same results from both the Ohio Rolling Cash 5 and the Fl Fantasy 5, both had the same results for the last 30 draws.

Now getting the last digits is hard enough but I wonder if playing the top first digit hitters against the dbl dbls and the triples is a smart move? If you using the spreadsheet or doing things on paper take a look at the first digit list and see how the dbl dbls and triples fair for your game.

Padawan

Took a look at Fla and you have a valid point. The hits for dbl-dbl's and trips are 69% .

Ohio United States Member #93878 July 9, 2010 7 Posts Offline

Posted: July 11, 2010, 8:41 pm - IP Logged

RL and the rest.

I have been following this system for 2 days. I play 6 plays per day. I pick ten numbers and then do an abbreviated wheeling system

I am on page 13 and will contribute my thoughts after I have gotten to page 18. I am creating my own excel for OHIO not for distribution, but so I can understand what is going on and contribute. I have thoughts, but I want to get caught up to the rest of you before I do it.

Day 1: Played $6, matched 2 of the 5 numbers on 2 lines; +2 = -$4.00

Day 2: Played $6, matched 3 of the 5 numbers, but only 2 on 3 lines; +3 = -$3.00

I feel like either I have been really lucky or this system as I expected kicks you know what.

I'll contribute once I get my brain and my excell up to page 18.