Taking the Mystery out of Picking Numbers (jackpot games)Prev Topic Next Topic

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RJOh

100

mid-Ohio
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March 24, 2001
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Aug 20, 2015, 1:35 pm

Quote: Originally posted by ElinaSammy2081 on Aug 20, 2015

Luck and timing and for me I have to learn to have patience and stop self doubting myself and learn to follow my gut instinct. MM I play every week I just laugh after the drawings because sometimes it draws number That I don't even look or notice during my studies it always throws a curve ball.

Tia gave me an idea about a new chart.

"MM I play every week I just laugh after the drawings because sometimes it draws number That I don't even look or notice during my studies"

That may be a clue for how to use the numbers from your studies. When I come up with a list using the same program for MM I used for CL, the list is about 25 numbers which usually includes one of two of the winning numbers so I use it to eliminate numbers instead. I find each game is unique in how it responds to the data.

* you don't need to buy every combination, just the winning ones *
RJOh

100

mid-Ohio
United States
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March 24, 2001
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Aug 21, 2015, 6:39 pm

Quote: Originally posted by RJOh on Aug 19, 2015
I wrote a program some years back that does something similar. It looks at the last drawing and checked which numbers followed its numbers in previous drawings going in the same direction.

For example Ohio's Classic Lotto(6/49) Monday's results were 08/17/15 - 13 33 37 41 44 49 and all the numbers were higher than the six numbers in the previous drawings in the same position so the program would give me these 43 numbers to put into my positional RNG to pick some combinations.

[CP = 43]
13-COL 1 = 1 2 3 4 5 6 7 8 10 11 12 13
33-COL 2 = 3 6 16 26 27 33
37-COL 3 = 11 12 16 20 23 26 28 29 37
41-COL 4 = 19 20 21 24 26 27 28 29 30 31 35 41
44-COL 5 = 13 19 21 24 25 26 28 29 30 31 32 35 36 37 38 39 40 41 42 43 44
49-COL 6 = 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49

I've since wrote a program that look at past results and concludes if all the numbers are in this group only three are likely to be in their assigned positions so now I accept combinations with three or more numbers in their assigned position that have never matched more than four in previous drawings.

I posted 10 lines I picked on the prediction board to see what happens.

For Saturday's Ohio's Classic Lotto I ran that program again and it included 47 numbers which means I have to choose from 77% of the possible combinations unlike Wednesday' result which included only 43 numbers which covered 44% of the possible combinations.

On the other hand the other program suggest that five of the winning numbers will hit in their assigned positions.

I may give it another try this week end in spite of the worsen odds. At least spend the $2 I won on a couple of tickets.

I need to design a program that can calculate the numbers of combinations a positional wheel would generate using those parameters.

Below is a chart showing percent of coverage a regular full wheel would cover generated by a program I wrote using some information Jadelottery posted in the math forum.

WHEEL COVERAGE AND PERCENT
LOTTERY POOL SIZE 49
COMBINATION SIZE 6
13983816 POSSIBLE COMBOS - Wheel Size - Percent Cover - Possible Combinations
No. %COVER Combos No. %COVER Combos
________________________________________________________________________________
49 = 100.000000% 13983816 48 = 87.755102% 12271512
47 = 76.785714% 10737573 46 = 66.983283% 9366819
45 = 58.246333% 8145060 44 = 50.480155% 7059052
43 = 43.596498% 6096454 42 = 37.513265% 5245786
41 = 32.154227% 4496388 40 = 27.448731% 3838380
39 = 23.331421% 3262623 38 = 19.741965% 2760680
37 = 16.624818% 2324784 36 = 13.928902% 1947792
35 = 11.607418% 1623160 34 = 9.617575% 1344904
33 = 7.920356% 1107568 32 = 6.480284% 906191
31 = 5.265237% 736281 30 = 4.246159% 593775
29 = 3.396920% 475019 28 = 2.694107% 376739
27 = 2.116804% 296010 26 = 1.646403% 230230
25 = 1.266464% 177100 24 = 0.962513% 134596
23 = 0.721884% 100947 22 = 0.533567% 74613
21 = 0.388049% 54264 20 = 0.277178% 38760
19 = 0.194024% 27132 18 = 0.132753% 18564
17 = 0.088502% 12376 16 = 0.057266% 8008
15 = 0.035791% 5005 14 = 0.021475% 3003
13 = 0.012271% 1716 12 = 0.006608% 924
11 = 0.003304% 462 10 = 0.001502% 210
9 = 0.000601% 84 8 = 0.000200% 28
7 = 0.000050% 7 6 = 0.000007% 1

* you don't need to buy every combination, just the winning ones *
garyo1954

Texas
United States
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May 2, 2004
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Aug 28, 2015, 9:49 pm

It's only fair........

I went all out talking about how (my) SPs have beaten the QPs hands down in this thread.

Last night for the first time in Texas 2Step, QPs actually beat me.

The winning numbers were 5 15 19 22 BB 8.

I had the 5 and the 8 (albeit 8 was the BB). For some reason I seem to get the bonus ball in my lines. Can't figure that one out.

And the QP had the 15, 19 and the BB 8. Congratulations QP! You won $19! I'll take it. I'm far from even over the last month, but maybe we can start a streak?

Yeah, for real $2 was all I played. Almost didn't play at all. Kept going back between 24 and 29. In the end the 4 won out since it hasn't been seen in a few (can't remember exact number) draws.

I'm probably here unless I'm not.
Dreaming would be a perfectly useless function if it's only purpose was to entertain.
dr san

bgonÃ§alves
Brasil
Member #92,560
June 9, 2010
3,779 Posts
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Aug 28, 2015, 10:41 pm

Hello rjohl, you have to create the possible total number with position limit
example =
49/6
1st place = 01-20 2ª'posiçao 02-25 28th position 03-34 4th 04 38
5th position 15 to 42 and 6 [20 position to the 49
Doing so in a diagonal 6 positions in ascending order the draws
1st 01-20
2nd 03-25
The 3rd = 05 35
4th from 15 to 40
5th position from 20 to 45
E 6th 25-49
Do you see the possibility for toatal limit numbers by position and its use in 49/6, thanks
ChetserDennis

Ontario
Canada
Member #70,049
January 23, 2009
80 Posts
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Sep 10, 2015, 8:18 am

Quote: Originally posted by RL-RANDOMLOGIC on Aug 7, 2015
Here are a couple charts that show the Base-digit Independent digit digit counts for my 5-39. You can

see games where 8 of the positional digits are base digits. In the ID chart you can see that 5 or 6

make up most of the drawings.

BD's

ID's

RL

RL-RANDOMLOGIC,

Which of your programs show the BD's and ID's?

Thanks,

CD
RJOh

100

mid-Ohio
United States
Member #9
March 24, 2001
20,272 Posts
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Sep 10, 2015, 9:25 am

Quote: Originally posted by dr san on Aug 28, 2015
Hello rjohl, you have to create the possible total number with position limit
example =
49/6
1st place = 01-20 2ª'posiçao 02-25 28th position 03-34 4th 04 38
5th position 15 to 42 and 6 [20 position to the 49
Doing so in a diagonal 6 positions in ascending order the draws
1st 01-20
2nd 03-25
The 3rd = 05 35
4th from 15 to 40
5th position from 20 to 45
E 6th 25-49
Do you see the possibility for toatal limit numbers by position and its use in 49/6, thanks

I don't know how to calculate the number of possible combinations with limits on the range of numbers per position. I suppose one would have to write a program that printed all such possible combinations and counted them. Sorry.

* you don't need to buy every combination, just the winning ones *
garyo1954

Texas
United States
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May 2, 2004
4,228 Posts
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Sep 10, 2015, 2:17 pm

Quote: Originally posted by RJOh on Sep 10, 2015
I don't know how to calculate the number of possible combinations with limits on the range of numbers per position. I suppose one would have to write a program that printed all such possible combinations and counted them. Sorry.

Write a counter to count the hits by number per positions. Run it against the entire matrix or the draw results. You can format your output to look something like this.....

This is the entire matrix of Texas 2Step. Each number hits a total of 5984 times. What I've done is calculate the times each number hits in a position by that that total. You could also calculate the percentage of hits versus all draws but it would not be much help (the percentages would be minuscule).

Once you have your percentages (from the program or Excel) you can set your range by position, BUT....

you need to go back and check those ranges against the drawings to see how they perform.

For 6/49 it will take longer to run the program than to write it.

Good luck!

I'm probably here unless I'm not.
Dreaming would be a perfectly useless function if it's only purpose was to entertain.
RJOh

100

mid-Ohio
United States
Member #9
March 24, 2001
20,272 Posts
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Sep 10, 2015, 10:00 pm

Quote: Originally posted by garyo1954 on Sep 10, 2015
Write a counter to count the hits by number per positions. Run it against the entire matrix or the draw results. You can format your output to look something like this.....

This is the entire matrix of Texas 2Step. Each number hits a total of 5984 times. What I've done is calculate the times each number hits in a position by that that total. You could also calculate the percentage of hits versus all draws but it would not be much help (the percentages would be minuscule).

Once you have your percentages (from the program or Excel) you can set your range by position, BUT....

you need to go back and check those ranges against the drawings to see how they perform.

For 6/49 it will take longer to run the program than to write it.

Good luck!

I know the number of times all numbers hit in each position for any group of drawings but if I understand his question he want to know the number of possible combinations if the numbers were limited in first position to 01-20, second position to 03-25, third position to 05-35, forth position to 15-40, fifth position to 20-45 and sixth position to 25-49.

The only way I know how to do that is created a set of loops to print out all the possible combinations with those parameters and count them or go through a full 6/49 wheel and count the combinations that fit those parameters.

* you don't need to buy every combination, just the winning ones *
garyo1954

Texas
United States
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May 2, 2004
4,228 Posts
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Sep 11, 2015, 12:09 am

Quote: Originally posted by RJOh on Sep 10, 2015
I know the number of times all numbers hit in each position for any group of drawings but if I understand his question he want to know the number of possible combinations if the numbers were limited in first position to 01-20, second position to 03-25, third position to 05-35, forth position to 15-40, fifth position to 20-45 and sixth position to 25-49.

The only way I know how to do that is created a set of loops to print out all the possible combinations with those parameters and count them or go through a full 6/49 wheel and count the combinations that fit those parameters.

Guess I'm lucky. I don't understand.

After rereading the post, the parameters for each position changed from the first time to the second time.

198,000,000 sounds about right going by your post (20*22*30*25*25*24).

That would mean 275,000 to 1,650,000 real sets could be made.

I'm probably here unless I'm not.
Dreaming would be a perfectly useless function if it's only purpose was to entertain.
SkyLine69

Krypton
United States
Member #140,096
March 11, 2013
904 Posts
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Sep 11, 2015, 12:28 am

Quote: Originally posted by garyo1954 on Aug 28, 2015
It's only fair........

I went all out talking about how (my) SPs have beaten the QPs hands down in this thread.

Last night for the first time in Texas 2Step, QPs actually beat me.

The winning numbers were 5 15 19 22 BB 8.

I had the 5 and the 8 (albeit 8 was the BB). For some reason I seem to get the bonus ball in my lines. Can't figure that one out.

And the QP had the 15, 19 and the BB 8. Congratulations QP! You won $19! I'll take it. I'm far from even over the last month, but maybe we can start a streak?

Yeah, for real $2 was all I played. Almost didn't play at all. Kept going back between 24 and 29. In the end the 4 won out since it hasn't been seen in a few (can't remember exact number) draws.

I got such in a hurry tonight I filled out the sane line twice lol. I made it to the store AGAIN with 2 minutes to spare. I need time off G. Will you talk to my wife and beg her yo give me some alone time lol. I'll pick my own numbers any day of the week. I can normally lock down a min of two. Sometimes 3 to 4. I normally don't post tickets but thought I'd share this as part of my frustration Oh, I did get several 3/4,tonight on Two Step and a 4/4 no BB again. This makes 3 times having 4/4 within the last 7 draws. Something better give soon lol The winner was 2-4-30-35 BB 11

Stay In The Vortex, you'll be happy you did ..... Random? Seriously? You want me to believe that?
garyo1954

Texas
United States
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May 2, 2004
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Sep 11, 2015, 12:39 am

Congratulations Skyline! I'm coming to your place to eat!

Hope you got all you can eat for $7 I only had the 35 and the 11.

You have about $2149 in four lines!

Congrats!

Tell the wife I'll help out (if you slip me $50).

I'm probably here unless I'm not.
Dreaming would be a perfectly useless function if it's only purpose was to entertain.
ElinaSammy2081

Bronx, NY
United States
Member #164,546
March 6, 2015
1,374 Posts
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Sep 11, 2015, 1:09 am

Congratulations Skyline on your wins.
Tialuvslotto

Texas
United States
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December 31, 2013
824 Posts
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Sep 11, 2015, 6:39 am

Congratulations, Skyline! With pickin' like that we should start calling you "Banjo Man".

"There is no such thing as luck; only adequate or inadequate preparation to cope with a statistical universe."

~Robert A. Heinlein
SkyLine69

Krypton
United States
Member #140,096
March 11, 2013
904 Posts
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Sep 11, 2015, 9:26 am

Quote: Originally posted by Tialuvslotto on Sep 11, 2015
Congratulations, Skyline! With pickin' like that we should start calling you "Banjo Man".

Thanks lol

Stay In The Vortex, you'll be happy you did ..... Random? Seriously? You want me to believe that?
SkyLine69

Krypton
United States
Member #140,096
March 11, 2013
904 Posts
Offline

Sep 11, 2015, 9:26 am

Quote: Originally posted by ElinaSammy2081 on Sep 11, 2015
Congratulations Skyline on your wins.

Thanks

Stay In The Vortex, you'll be happy you did ..... Random? Seriously? You want me to believe that?

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Taking the Mystery out of Picking Numbers (jackpot games)Prev TopicNext Topic

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