United States Member #128373 May 22, 2012 201 Posts Offline

Posted: September 16, 2012, 12:52 pm - IP Logged

From what I'm reading, RL, it seems that you're focusing heavily on the decades, groups, and digits and not so much on the other filters (i.e., double odd, double even, etc)? Please explain.

The lottery is NOT a tax on the poor. By calling it a tax, you are calling it mandatory, which is what taxes are. But the lottery is NOT mandatory, therefore calling it a tax highly inaccurate.

Park City, UT United States Member #69864 January 18, 2009 993 Posts Offline

Posted: September 16, 2012, 2:04 pm - IP Logged

Just did a group representation based on gaps and for the most part the entire group gap string did not repeat.

So an example for the last draw the groups were:

0021001010 which I represent as 34 79 the gaps would be 1 3 2. It appears as a whole the gap strings are fairly unique and do not repeat.

If you look at partial gap strings the post popular beginning gap pattern is 1 1 which means a group pattern that starts with 3 consecutive groups with 17 hits in 74 draws so far in 2012 or about 1 in every 4.35 draws.

As a side note I know RL is doing the digit/group setup as he should to work out the kinks in his new programs. I'm just trying to contribute to the research.

United States Member #59354 March 13, 2008 3968 Posts Offline

Posted: September 16, 2012, 5:51 pm - IP Logged

Quote: Originally posted by Ronnie316 on September 16, 2012

You may be asking how this can help because

you not only have to select the 1 out of the 15 group sets of 6 but you also have to select the correct 4 of

the 6 from the second subset

That is in fact the very question I was asking..........

That, and can you show me an example of a group that hit 5 of 5??

Ronnie

I can't put it in a nutshell so let's say that I use a RNG to generate a string with 6 letters from A to j.

I then run the RNG 15 times so that I have 15 strings all with different arrangments of 6 letters which I

then sort so that they are in order like A-C-E-F-I-J

All 15 strings contain 6 letters of the possible 10 ->ABCDEFGHIJ. If you have downloaded

my software you know that each of these letters repersent groups of 6 numbers each which

is not important for what I am talking about here, the main goal is selecting the correct 3,4 or

5 to put into play for the next draw. Several of the strings will have several letters in common

with other strings. We don't know which groups will hit but using the TG filter, which stands for

"total groups" which is the number of these groups that will provide all the numbers for the

next draw.

The five winning numbers for the last MM drawing came from groups C-G-H-I with group G providing

two of the numbers. For this example lets say we decide to play 4 groups based on the analysis of

the TG filter. Below is an actual run of the rng. Each run produces different results. I am using a draw

that has already taken place so people can understand the idea.

15 randomly selected groups

A D E F G J =1 G A C F G H I =4 C-G-H-I B D E F H J =1 H A C E F H I =3 C-H-I B D E F H J =1 H C F G H I J =4 C-G-H-I A B C D F H =2 C-H B C D F H I =3 C-H-I D E G H I J =2 H-I A B D F H J =1 H B C D E G H =3 C-G-H A B C F H J =2 C-H B E F G H I =2 G-H-I E F G H I J =3 G-H-I B C D F I J =2 C-I

We can see from the above that 2 of the random sets contained all 4 groups that showed in the

last draw and 5 that had 3 of the groups and 4 that had 2 and 4 that had 1 correct. These

results are very close to the expected using the calculations on the previous page match

random

Match Expected sample +/-

4 1 2 +1

3 4 5 +1

<3 10 8 -2

In the above example we knew which groups to look for but when the draw has not happened yet we have

to find a set of 4 groups that fits as close as possible all the expected values. Before I start to

explain how the program finds the best groups to play I want to remind everyone of something I have

said many times. Every 4of5 needs one wrong number so don't try to set 4 groups to play and block the

other 6, What we need is to put 6 into play and block the remaining 4. This increases the lower prizes

and also gives you room to make a few mistakes and still hit a 5of5. Of the 6 groups we end with here

I suggest setting no more than 3 to play on a TG=5 setup or 2 for a TG=4 setup and let the others 3 or 4

run wild. So for a TG=5 setup you would set 3 to (P) 3 to (W) and 4 to (B).

Now, how the program picks the best four to play.

A D E F G J A C F G H I B D E F H J A C E F H I B D E F H J C F G H I J A B C D F H B C D F H I D E G H I J A B D F H J B C D E G H A B C F H J B E F G H I E F G H I J B C D F I J

Totals

A= 6

B= 9

C= 8

D= 9

E= 8

F=13

G= 7

H=13

I= 8

J= 9

First we total all the times each groups exist in the random strings. The first step is to take the top 3 or 4 groups

in this case we find they are H-F + B, D, J so we will make 3 sub groups H-F-B, H-F-D, H-F-J. Next find in how many

of the strings these sets of groups appear.

F-H-B =7

F-H-D =5

H-F-J =6

The expected number of strings to have 3 groups is 4. All of these are above the expected number of average hits

so they are not expected to all show in the set to be played. In the last draw C-G-H-I were the correct groups and

none of the above groups of 3 hit and only one of the top hitting values hit in the draw. Almost every time the pool

members sent in there top six choices only 1 of the overall top 3 hit. The lottery officals use probability to calculate

how many tickets will match each of the prizes for any draw, what we are doing here is the same thing only in

reverse. It it works for them then it has to work for us, it has to be one or the other. This is very good stuff and I

hope everyone understands what I am saying. If the draw is not tampered with then this logic should work in a very

predictable way.

It will take too much time to do every tray of groups and sort them by the ones that fit the expected values but the

program does this for trays, pairs and then ones. If at the end of the process the program cannot find a set of four

groups that fits the expected value then it checks for strings that have 4 matching groups and if it finds two or more

that all contain 4 matching groups within another string then it replaces those strings with another randomly generated

set.

Once the program is finished it may find more than one set of four groups to play which it would then try to cover all

of them within one string of six groups. Remember I said I was looking for 6 groups to use in my setup. If the process

finds too many or too few then it starts over by generating 15 new strings and runs the process again. Probability says

that one of the 15 strings should contain a 4of4 so the end set must contain four groups from one of the orgional strings.

If a match of 4 cannot be found then it starts the whole process again.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

United States Member #116268 September 7, 2011 20244 Posts Offline

Posted: September 16, 2012, 6:03 pm - IP Logged

Quote: Originally posted by RL-RANDOMLOGIC on September 16, 2012

Ronnie

I can't put it in a nutshell so let's say that I use a RNG to generate a string with 6 letters from A to j.

I then run the RNG 15 times so that I have 15 strings all with different arrangments of 6 letters which I

then sort so that they are in order like A-C-E-F-I-J

All 15 strings contain 6 letters of the possible 10 ->ABCDEFGHIJ. If you have downloaded

my software you know that each of these letters repersent groups of 6 numbers each which

is not important for what I am talking about here, the main goal is selecting the correct 3,4 or

5 to put into play for the next draw. Several of the strings will have several letters in common

with other strings. We don't know which groups will hit but using the TG filter, which stands for

"total groups" which is the number of these groups that will provide all the numbers for the

next draw.

The five winning numbers for the last MM drawing came from groups C-G-H-I with group G providing

two of the numbers. For this example lets say we decide to play 4 groups based on the analysis of

the TG filter. Below is an actual run of the rng. Each run produces different results. I am using a draw

that has already taken place so people can understand the idea.

15 randomly selected groups

A D E F G J =1 G A C F G H I =4 C-G-H-I B D E F H J =1 H A C E F H I =3 C-H-I B D E F H J =1 H C F G H I J =4 C-G-H-I A B C D F H =2 C-H B C D F H I =3 C-H-I D E G H I J =2 H-I A B D F H J =1 H B C D E G H =3 C-G-H A B C F H J =2 C-H B E F G H I =2 G-H-I E F G H I J =3 G-H-I B C D F I J =2 C-I

We can see from the above that 2 of the random sets contained all 4 groups that showed in the

last draw and 5 that had 3 of the groups and 4 that had 2 and 4 that had 1 correct. These

results are very close to the expected using the calculations on the previous page match

random

Match Expected sample +/-

4 1 2 +1

3 4 5 +1

<3 10 8 -2

In the above example we knew which groups to look for but when the draw has not happened yet we have

to find a set of 4 groups that fits as close as possible all the expected values. Before I start to

explain how the program finds the best groups to play I want to remind everyone of something I have

said many times. Every 4of5 needs one wrong number so don't try to set 4 groups to play and block the

other 6, What we need is to put 6 into play and block the remaining 4. This increases the lower prizes

and also gives you room to make a few mistakes and still hit a 5of5. Of the 6 groups we end with here

I suggest setting no more than 3 to play on a TG=5 setup or 2 for a TG=4 setup and let the others 3 or 4

run wild. So for a TG=5 setup you would set 3 to (P) 3 to (W) and 4 to (B).

Now, how the program picks the best four to play.

A D E F G J A C F G H I B D E F H J A C E F H I B D E F H J C F G H I J A B C D F H B C D F H I D E G H I J A B D F H J B C D E G H A B C F H J B E F G H I E F G H I J B C D F I J

Totals

A= 6

B= 9

C= 8

D= 9

E= 8

F=13

G= 7

H=13

I= 8

J= 9

First we total all the times each groups exist in the random strings. The first step is to take the top 3 or 4 groups

in this case we find they are H-F + B, D, J so we will make 3 sub groups H-F-B, H-F-D, H-F-J. Next find in how many

of the strings these sets of groups appear.

F-H-B =7

F-H-D =5

H-F-J =6

The expected number of strings to have 3 groups is 4. All of these are above the expected number of average hits

so they are not expected to all show in the set to be played. In the last draw C-G-H-I were the correct groups and

none of the above groups of 3 hit and only one of the top hitting values hit in the draw. Almost every time the pool

members sent in there top six choices only 1 of the overall top 3 hit. The lottery officals use probability to calculate

how many tickets will match each of the prizes for any draw, what we are doing here is the same thing only in

reverse. It it works for them then it has to work for us, it has to be one or the other. This is very good stuff and I

hope everyone understands what I am saying. If the draw is not tampered with then this logic should work in a very

predictable way.

It will take too much time to do every tray of groups and sort them by the ones that fit the expected values but the

program does this for trays, pairs and then ones. If at the end of the process the program cannot find a set of four

groups that fits the expected value then it checks for strings that have 4 matching groups and if it finds two or more

that all contain 4 matching groups within another string then it replaces those strings with another randomly generated

set.

Once the program is finished it may find more than one set of four groups to play which it would then try to cover all

of them within one string of six groups. Remember I said I was looking for 6 groups to use in my setup. If the process

finds too many or too few then it starts over by generating 15 new strings and runs the process again. Probability says

that one of the 15 strings should contain a 4of4 so the end set must contain four groups from one of the orgional strings.

If a match of 4 cannot be found then it starts the whole process again.

RL

This is extremely interest RL, but again Im wondering how often you achieve 5 of 5 and how many lines are covered to achieve a 5 of 5 result??

United States Member #59354 March 13, 2008 3968 Posts Offline

Posted: September 16, 2012, 6:51 pm - IP Logged

Quote: Originally posted by LottoPerro on September 16, 2012

From what I'm reading, RL, it seems that you're focusing heavily on the decades, groups, and digits and not so much on the other filters (i.e., double odd, double even, etc)? Please explain.

LottoPerro

I feel common filters are the killers of jackpots and they are used to filter my sets down to a playable

amount after digits and groups. Take away the digits and groups and DM is just another run of the

mill software. With my 5-39 the groups can reduce the matrix to 1024 lines or less and then the digits

take me down to less than 100 lines most days. I use as few filters as I can get by with, Digits and

groups are the power filters and I think that to win you have to master them as much as possible.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

United States Member #59354 March 13, 2008 3968 Posts Offline

Posted: September 16, 2012, 6:58 pm - IP Logged

Quote: Originally posted by jimjwright on September 16, 2012

Just did a group representation based on gaps and for the most part the entire group gap string did not repeat.

So an example for the last draw the groups were:

0021001010 which I represent as 34 79 the gaps would be 1 3 2. It appears as a whole the gap strings are fairly unique and do not repeat.

If you look at partial gap strings the post popular beginning gap pattern is 1 1 which means a group pattern that starts with 3 consecutive groups with 17 hits in 74 draws so far in 2012 or about 1 in every 4.35 draws.

As a side note I know RL is doing the digit/group setup as he should to work out the kinks in his new programs. I'm just trying to contribute to the research.

Jimmy

JW

keep posting as I read them all, you can always send me anything you feel will help out. I am holding

off playing tell the cash value is at least equal to one million per member. Might be next friday before

we take another shot at it. If PB jumps up really high we might take a poke at it also. I hope to finish

the new program and test it before the next draw. I have a new DM update ready but having a few

test it out before sending it out to everyone in case of errors. We did find an error in the RAC option

which really cut down on it's performance.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else

United States Member #128373 May 22, 2012 201 Posts Offline

Posted: September 16, 2012, 6:58 pm - IP Logged

Quote: Originally posted by RL-RANDOMLOGIC on September 16, 2012

LottoPerro

I feel common filters are the killers of jackpots and they are used to filter my sets down to a playable

amount after digits and groups. Take away the digits and groups and DM is just another run of the

mill software. With my 5-39 the groups can reduce the matrix to 1024 lines or less and then the digits

take me down to less than 100 lines most days. I use as few filters as I can get by with, Digits and

groups are the power filters and I think that to win you have to master them as much as possible.

RL

Thanks for explaining, RL. And that makes sense, actually. About the common filters, that is. I'm guessing you just play with the Digits and Groups filters and leave the other ones alone for the most part? Or use the other ones sparingly?

The lottery is NOT a tax on the poor. By calling it a tax, you are calling it mandatory, which is what taxes are. But the lottery is NOT mandatory, therefore calling it a tax highly inaccurate.

United States Member #59354 March 13, 2008 3968 Posts Offline

Posted: September 16, 2012, 7:04 pm - IP Logged

Quote: Originally posted by LottoPerro on September 16, 2012

Thanks for explaining, RL. And that makes sense, actually. About the common filters, that is. I'm guessing you just play with the Digits and Groups filters and leave the other ones alone for the most part? Or use the other ones sparingly?

LP

Thats the way I play but it takes time to learn how they move draw to draw. I am finding that the big

games are quite different than my 5-39 but I feel I am zeroing in on them a little each draw. Hope you

win soon.

RL

Working on my Ph.D. "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not. Many great discoveries come while searching for something else